Table 3.
T0–T1 | T0–T2 | T1–T2 | |
---|---|---|---|
EQ‐5D‐5L (2017 tariff) | (n = 128) | (n = 61) | (n = 49) |
Mean score | T0 = 0.51; T1 = 0.67 | T0 = 0.54; T2 = 0.69 | T1 = 0.67; T2 = 0.69 |
Difference in mean score | 0.15 | 0.15 | −0.02 |
95% CI | 0.12, 0.18 | 0.097, 0.20 | −0.086, 0.03 |
p value | <.001 | <.001 | .451 |
Effect sizeb | 0.831 | 0.728 | −0.108 |
EQ‐5D (VAS) | (n = 127) | (n = 61) | (n = 51) |
Mean score | T0 = 51.58; T1 = 63.39 | T0 = 51.00; T2 = 68.77 | T1 = 65.02; T2 = 68.24 |
Difference in mean score | 11.81 | 17.77 | 3.22 |
95% CI | 8.10, 15.52 | 11.94, 23.60 | −3.49, 9.92 |
p value | <.001 | <.001 | .340 |
Effect sizeb | 0.559 | 0.780 | 0.135 |
ASCOT SCT‐4 | (n = 128) | (n = 59) | (n = 47) |
Mean score | T0 = 0.73; T1 = 0.82 | T0 = 0.70; T2 = 0.80 | T1 = 0.791; T2 = 0.792 |
Difference in mean score | 0.09 | 0.10 | 0.002 |
95% CI | 0.06, 0.11 | 0.05, 0.15 | −0.04, 0.04 |
p value | <.001 | <.001 | .928 |
Effect sizeb | 0.641 | 0.540 | 0.013 |
Barthel Index | (n = 96) | Barthel Index not collected at T2. | |
Mean score | T0 = 72.4; T1 = 80.1 | ||
Difference in mean score | 7.71 | ||
95% CI | 4.03, 11.39 | ||
p value | .001 | ||
Effect sizeb | 0.424 | ||
NEADL Scale | (n = 128) | (n = 64) | (n = 52) |
Mean score | T0 = 9.67; T1 = 10.40 | T0 = 11.58; T2 = 13.22 | T1 = 11.50; T2 = 13.29 |
Difference in mean score | 0.73 | 1.64 | 1.79 |
95% CI | −0.06, 1.51 | 0.17, 3.11 | 0.55, 3.03 |
p value | .071 | .029 | .006 |
Effect sizeb | 0.161 | 0.279 | 0.401 |
GHQ‐12 | (n = 128) | (n = 62) | (n = 50) |
Mean score | T0 = 3.95; T1 = 2.42 | T0 = 3.89; T2 = 2.10 | T1 = 2.62; T2 = 2.06 |
Difference in mean score | −1.53 | −1.79 | −0.56 |
95% CI | −1.96, −1.11 | −2.46, −1.11 | −1.28, 0.16 |
p value | <.001 | <.001 | .123 |
Effect sizeb | −0.629 | −0.67 | 0.222 |
Difference in mean scores between time points are presented with corresponding: p‐values, 95% CI and effect size. Mean scores at each time point are also presented.
For all measures except GHQ‐12, higher scores = better outcomes. For GHQ‐12, it is the reverse.
Cohen's d = (mean2 − mean1)/standard deviation, (d = 0.2 small, d = 0.5 medium, d = 0.8 large).