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. 2019 Nov 2;8(11):1842. doi: 10.3390/jcm8111842

Table 4.

Statistical analysis of CTLA4 (SNPs).

SNP Genotype Genotype Frequency Odds Ratio (95 % CI) p Value
Patient (n) Control (n)
rs11571315 CC 0 0 NA NA
CT 8 11 0.468 (0.136–1.611) p = 0.226
TT 14 9 2.139 (0.621–7.370) p = 0.226
rs733618 CC 4 4 0.889 (0.190–4.150) p = 1
CT 18 12 3.000 (0.736–12.227) p = 0.118
TT 0 4 0.421 (0.290–0.611) p = 0.043 **
rs4553808 AA 19 13 3.410 (0.742–15.677) p = 0.152
AG 3 7 0.293 (0.064–1.348) p = 0.152
GG 0 0 NA NA
rs11571316 AA 0 0 NA NA
AG 5 4 1.176 (0.267–5.176) p = 1
GG 17 16 0.850 (0.193–3.739) p =1
rs62182595 AA 0 0 NA NA
AG 3 7 0.293 (0.064–1.348) p = 0.152
GG 19 13 3.410 (0.742–15.677) p = 0.152
rs16840252 CC 19 12 1.22 (0.932–19.131) p = 0.052 *
CT 3 8 0.237 (0.052–1.073) p = 0.052 *
TT 0 0 NA NA
rs5742909 CC 19 13 3.410 (0.742–15.677) p = 0.152
CT 3 7 0.293 (0.064–1.348) p = 0.152
TT 0 0 NA NA
rs231775 AA 0 0 NA NA
AG 8 11 0.468 (0.136–1.611) p = 0.226
GG 14 9 2.139 (0.621–7.370) p = 0.226
rs3087243 AA 0 0 NA NA
AG 5 4 1.250 (0.283–5.525) p = 1
GG 17 16 0.800 (0.181–3.536) p = 1

95%CI: 95% confidence interval; NA: Not applicable. * indicates p < 0.1, ** indicates p < 0.05.