Table 2.
Definition of the terms and formulas for calculation of the JIP-test parameters from the chlorophyll a fluorescence transient OJIP emitted by dark-adapted leaves.
| Quantum Yields and Probabilities | |
| ϕP0 = 1 − F0/FM | Maximum quantum yield of primary photochemistry in PSII (at t = 0) |
| ϕE0 = (1 − F0/FM)(1 − VJ) | Quantum yield of electron transport (at t = 0) beyond QA− |
| ϕR0 = (1 − F0/FM)(1 − VI) | Quantum yield for reduction of the end of electron acceptors at PSI acceptor side (RE) |
| ϕD0 = F0/FM | Quantum yield (at t = 0) of energy dissipation |
| δR0 = (1 − VI)/(1 − VJ) | The efficiency with which an electron can move from the reduced intersystem electron acceptors to the PSI end electron acceptors |
| ψE0 = 1 − VJ | Probability (at t = 0) that a trapped exciton will move an electron into electron transport chain beyond QA− |
| Specific Energy fluxes expressed per active PSII reaction center (RC) | |
| ABS/RC = (1 − γRC)/ γRC = M0 × (1/VJ)/[1 − (F0/FM)] | Apparent antenna size of active PSII RC |
| TR0/RC = Mo(1/Vj) | Trapping flux (leading to QA reduction) per RC |
| DI0/RC = (ABS/RC − TR0/RC) | Dissipated energy flux per RC |
| ET0/RC = M0(1/Vj) ψ0 | Electron transport flux per RC (further than QA−) |
| RC/CS0 = FO φP0 Vj/M0 | Density of RCs (QA− reducing PSII reaction centers) |
| Performance index per absorption | |
| PIABS = 1 − (F0/FM)/Mo/VJ × FM − F0/F0 × 1 − VJ/VJ | Performance index (potential) for energy conservation from exciton to the reduction of intersystem electron acceptors |
| Phenomenological energy fluxes per excited cross-section (CS) | |
| ABS/CS | Absorption energy flux per CS |
| TR0/CS | Trapped energy flux per CS |
| ET0/CS | Electron transport flux per CS |
| DI0/CS | Dissipation energy flux per CS |
F0—fluorescence intensity at 50 µs, FM—maximal fluorescence intensity, FJ—fluorescence intentisity at J step (at 2 ms), VJ—relative variable fluorescence at 2 ms calculated as VJ = (FJ − F0)/(FM − Fo), Mo initial slope of fluorescence kinetics which can be derived from equatation Mo = 4 × (F300µs − F0)/(FM − F0).