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. 2020 Apr 3;10:5871. doi: 10.1038/s41598-020-62457-2

Table 2.

Results of the statistical tests used.

Figure Comparison Test Factors Levels F value Sig. Pairwise comparisons Sig.
3 A Membrane resistance 1 w ANOVA age 5 F97,4 = 11.306 p < 0.001 2 vs 4,5–6,8–11 weeks p < 0.001
3 A 3 vs 5–6,8–11 weeks p < 0.001
3 A 2,3,4,5–6 vs 8–11 weeks p < 0.05
3B Membrane capacitance 1 w ANOVA age 5 F97,4 = 27.604 p < 0.001 2–4 vs 5–6 weeks p < 0.01
3B 2–4 vs 8–11 weeks p < 0.01
3 C IV curve - ACSF 1 w ANOVA voltage 26 F25,389 = 26.72 p < 0.001
1 w ANOVA age 2 F1,389 = 25.45 p < 0.001
1 w ANOVA voltage*age 26 F25,389 = 2.188 p = 0.001
t-test current*age 26 p < 0.05 20–50 mV (2w vs 4 w)
3 F AP threshold 1 w ANOVA age 5 F97,4 = 16.472 p < 0.001 5–6 vs 2,3,4 weeks p < 0.001
3 F 8–11 vs 2,3,4 weeks p < 0.001
3 G Firing frequency 1 w ANOVA age 5 F91,4 = 6.666 p < 0.001 2,3 vs 8–11 weeks p < 0.05
4 A EPSCs amplitude 1 w ANOVA age 3 F2,46 = 8.043 p = 0.001 2 vs 4 weeks p = 0.006
4 A 3 vs 4 weeks p = 0.003
4B EPSCs frequency 1 w ANOVA age 3 F2,46 = 6.91 p = 0.002 2 vs 4 weeks p = 0.004
4B 3 vs 4 weeks p = 0.026
4 G IPSCs amplitude 1 w ANOVA age 3 F2,19 = 2.474 p = 0.114
4 H IPSCs frequency 1 w ANOVA age 3 F2,19 = 1.876 p = 0.184
5 C EPSCs frequency 1 w ANOVA age 3 F2,23 = 6.091 p = 0.008 2 vs 4 weeks p = 0.0012
5 C 4 vs 4 weeks-AOBX p = 0.027
6 A Paired pulse amplitude 2 w ANOVA peak 2 F1,779 = 10.368 p = 0.001
6 A age 2 F1,779 = 77.109 p = 0.000
6 A peak*age F1,779 = 0.462 p = 0.497
7B Dendritic length 1 w ANOVA age 3 F2,13 = 6.29 p = 0.015 2–3 vs 4+ weeks p = 0.014
7D Spine density 1 w ANOVA age 3 F2,13 = 5.48 p = 0.022 2–3 vs 4+ weeks p = 0.018
8B PmCo c-Fos 2 w ANOVA age 2 F2,35 = 9.127 p = 0.005
8B odor 3 F2,35 = 7.981 p = 0.002
8B age*odor F2,35 = 7.247 p = 0.003
8B PmCo c-Fos juvenile 1 w ANOVA odor 3 F2,15 = 4.087 p = 0.042 FU vs ctrl p = 0.036
8B PmCo c-Fos mature 1 w ANOVA odor 3 F2,19 = 12.328 p < 0.001 MU vs ctrl p = 0.003
8B FU vs MU p = 0.001
8 C ACP c-Fos 2 w ANOVA age 2 F2,26 = 37.078 p < 0.001
8 C odor 3 F2,26 = 30.764 p < 0.001
8 C age*odor F2,26 = 16.348 p < 0.001
8 C ACP c-Fos juvenile 1 w ANOVA odor 3 F2,13 = 5.926 p = 0.018 FU vs ctrl p = 0.017
8 C ACP c-Fos mature 1 w ANOVA odor 3 F2,12 = 32.481 p < 0.001 FU vs ctrl p < 0.001
8 C MU vs ctrl p < 0.001
8 C FU vs MU p = 0.006
8D ACP c-fos odor experience 1 w ANOVA odor 4 F3,13 = 40.448 p < 0.001 nMU vs ctrl,fMU,uMU p < 0.001
8D uMU vs ctrl p = 0.005
S2A Dendritic length 1 w ANOVA age 3 F2,104 = 4.35 p = 0.016 2–3 vs 4+ weeks p = 0.018
S2A Dendritic length 2 w ANOVA distance 9
S2A age*distance F16,104 = 1.362 p = 0.18
S2B Spine density 1 w ANOVA distance 9 F8,104 = 2.730 p = 0.01 50 vs 150–450 μm p < 0.01
S2B 100 vs 150–450 μm p < 0.01
S2B 2 w ANOVA distance*age F16,104 = 1.478 p = 0.13
S2C Branching points 1 w ANOVA age 3 F2,104 = 0.75 p = 0.47
S2C 2 w ANOVA distance*age F16,104 = 0.6 p = 0.86
S3A Normal distribution Levene's test p = 0.002 e
S3A Amplitude Wilcoxon electrode*LED p < 0.001
S4A Response ratio (electrode) 1 w ANOVA age (weeks) 4 F3,15 = 4.304 p = 0.028 2nd vs 5th p = 0.039
S4A Response ratio (LED) 1 w ANOVA age (weeks) 3 F2,10 = 11.925 p = 0.004 2nd vs 3rd p = 0.032
S4A 3rd vs 4th p = 0.005
S5A Amplitude 1 w ANOVA age (weeks) 3 F2,58 = 2.030 p = 0.141
S5B Frequency 1 w ANOVA age (weeks) 3 F2,57 = 4.676 p = 0.013 2nd vs 4+ p = 0.023
S5C Amplitude 1 w ANOVA age (weeks) 3 F2,28 = 2.518 p = 0.1
S5D Frequency 1 w ANOVA age (weeks) 3 F2,28 = 2.171 p = 0.134