Table 4.

Calculation of the ILL d₂₂₀ value (scenario 1).

NW04 d220 t = 22.5 °C, p = 0 Pa	192.015 569 6(10) × 10−12 m
(dILL − dWS1)/dWS1	40(10) × 10−9
(dWS1 − dNW04)/dNW04	−20(9) × 10−9
(dILL − dNW04)/dNW04	20(14) × 10−9
(dILL − dNW04)/dNW04 (combined uncertainty)	20(29) × 10−9
ILL d220 t = 22.5 °C, p = 0 Pa	192.015 573 5(56) × 10−12 m