Algorithm 1: NS ADR Algorithm for a given ED.

Input: $SF$, $P_{\mathrm{T}}$, $S{F}_{\min }=7$, $Margin$ = 10 $dB$

$SN{R}_{\max }=max\left\{last20uplinkpacketsreceived\right\}$,

$SN{R}_{\min }$ given in Table 3 by setting $SF$,

$SN{R}_{\mathrm{margin}}=SN{R}_{\max }-SN{R}_{\min }-Margin$,

$N_{\mathrm{step}}=⌊\frac{SN{R}_{\mathrm{margin}}}{3}⌋$

Output: $SF$, $P_{\mathrm{T}}$

1 if $N_{\mathrm{step}}>0$ then$\phantom{(}$

2  while $N_{\mathrm{step}}>0 \& SF>S{F}_{\min }$ do

3   $\phantom{(}$$SF=SF-1$

4   $N_{\mathrm{step}}=N_{\mathrm{step}}-1$

5  while $N_{\mathrm{step}}>0 \& P_{\mathrm{T}}>P_{{\mathrm{T}}_{\min }}$ do

6   $\phantom{(}$$P_{\mathrm{T}}=P_{\mathrm{T}}-3dB$

7   $N_{\mathrm{step}}=N_{\mathrm{step}}-1$

8 else$\phantom{(}$

9  while $N_{\mathrm{step}}<0 \& P_{{\mathrm{T}}_{\mathrm{temp}}}<P_{{\mathrm{T}}_{\max }}$ do

10   $\phantom{(}$$P_{\mathrm{T}}=P_{\mathrm{T}}+3dB$

11   $N_{\mathrm{step}}=N_{\mathrm{step}}+1$

12 return $SF$, $P_{\mathrm{T}}$