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. 2021 Feb 14;260:117797. doi: 10.1016/j.carbpol.2021.117797

Table 1.

Composition of HS and CS from bat lung and human lung.

HS TriS HS NS6S HS NS2S HS NS HS 2S6S HS 6S HS 2S HS 0S Total NS a Total NAc b Total sulfation c
Male bat lung HS 0.16 ± 0.10 % 3.63 ± 1.41 % 25.8 ± 3.19 % 48.1 ± 2.94 % 0.16 ± 0.16 % 2.45 ± 1.06 % 1.56 ± 1.24 % 18.1 ± 6.82 % 77.7 ± 6.47 % 22.3th±5.11 % 112 ± 15.1 %
Female bat lung HS 0.34 ± 0.06 % 3.02 ± 0.45 % 23.8 ± 3.62 % 47.3 ± 2.80 % 0.03 ± 0.06 % 3.53 ± 0.51 % 1.15 ± 0.67 % 20.8 ± 4.77 % 74.5 ± 4.78 % 25.5 ± 4.78 % 107 ± 12.4 %
All bat lung HS 0.25 ± 0.12 % 3.32 ± 1.02 % 24.8 ± 3.34 % 47.7 ± 2.69 % 0.09 ± 0.13 % 2.99 ± 0.97 % 1.35 ± 0.95 % 19.4 ± 5.63 % 76.1 ± 5.54 % 23.9 ± 4.89 % 109 ± 14.0 %
Human lung HS 0.12 ± 0.21 % 0.43 ± 0.55 % 2.44 ± 2.37 % 6.75 ± 3.82 % 0.00 ± 0.00 % 5.12 ± 0.97 % 6.27 ± 1.11 % 78.9 ± 7.74 % 9.74 ± 6.81 % 90.3 ± 6.81 % 24.2 ± 12.4 %
CS TriS CS 2S4S CS 2S6S CS 4S6S CS 4S CS 6S CS 2S CS 0S / / Total sulfation d
Male bat lung CS 0.00 ± 0.00 % 1.54 ± 2.37 % 0.54 ± 1.08 % 0.30 ± 0.59 % 72.2 ± 0.68 % 8.74 ± 1.22 % 5.34 ± 3.81 % 11.3 ± 4.41 % / / 163 ± 13.9 %
Female bat lung CS 0.00 ± 0.00 % 3.53 ± 1.26 % 3.44 ± 1.20 % 0.21 ± 0.42 % 66.7 ± 2.83 % 12.7 ± 4.77 % 4.28 ± 2.92 % 9.15 ± 2.53 % / / 164 ± 18.7 %
All bat lung CS 0.00 ± 0.00 % 2.54 ± 2.06 % 1.99 ± 1.87 % 0.25 ± 0.48 % 69.4 ± 3.53 % 10.7 ± 3.86 % 4.81 ± 3.19 % 10.2 ± 3.52 % / / 164 ± 22.5 %
Human lung CS 0.06 ± 0.04 % 2.11 ± 0.58 % 0.44 ± 0.08 % 1.12 ± 0.52 % 84.2 ± 1.76 % 5.80 ± 1.82 % 4.67 ± 0.12 % 1.55 ± 0.49 % / / 185 ± 7.41 %

%S = 0×%0S + 1×%4S + 1×%6S + 1×%2S + 2×%2S4S + 2×%2S6S + 2×%4S6S + 3×%Tris. Values represent means ± standard deviations of 4 male bat lungs, 4 female bat lungs, and 6 male human lungs.

a

The total NS indicates all the HS disaccharides containing N-sulfo (NS) group.

b

The total NAc indicates all the HS disaccharides containing N-acetyl (NAc) group.

c

The total sulfation of HS (%S) is calculated by the following formula. %S = 0×%0S + 1×%NS + 1×%2S + 1×%6S + 2×%NS6S + 2×%NS2S + 2×%2S6S + 3×%Tris.

d

The total sulfation of CS (%S) is calculated by the following formula.