Table 2.

Topological indices derive from M(BTnt_lq; x, y).

Topological index		Derivation from M(BTntlq; x, y) = g(x, y)
RRR[BTntlq]	=	$D_x^{\frac{1}{2}}{D}_y^{\frac{1}{2}}{Q}_{y(-1)}{Q}_{x(-1)}{\left[g(x,y)\right]}_{x=y=1}$
AG1[BTntlq]	=	$\frac{1}{2}{D}_{x}J{S}_x^{\frac{1}{2}}{S}_y^{\frac{1}{2}}{\left[g(x,y)\right]}_{x=1}$
SK[BTntlq]	=	$\frac{1}{2}(D_x+D_y){\left[g(x,y)\right]}_{x=y=1}$
SK1[BTntlq]	=	$\frac{1}{2}{D}_x{D}_y{\left[g(x,y)\right]}_{x=y=1}$
Sk2[BTntlq]	=	$\frac{1}{4}{D}_x^{2}J{\left[g(x,y)\right]}_{x=y=1}$
EM1[BTntlq]	=	$D_x^2{Q}_{x(-2)}J{\left[g(x,y)\right]}_{x=1}$
SCI[BTntlq]	=	$S_x^{\frac{1}{2}}J{\left[g(x,y)\right]}_{x=1}$
SCIλ[BTntlq]	=	$D_x^{\lambda }J{\left[g(x,y)\right]}_{x=1}$
F[BTntlq]	=	$(D_x^2+D_y^2){\left[g(x,y)\right]}_{x=1}$

Where the operator used are defined as

$D_{x}g(x,y)=x\frac{\partial (g(x,y))}{\partial x},$ $D_{y}g(x,y)=y\frac{\partial (g(x,y))}{\partial y},$ Jg(x, y) = g(x, x), $Q_{x(\alpha )}g(x,y)=x^{\alpha }g(x,y),$

$D_x^{\frac{1}{2}}g(x,y)=\sqrt{x\frac{\partial (g(x,y))}{\partial x}}·\sqrt{g(x,y)},$      $D_y^{\frac{1}{2}}g(x,y)=\sqrt{y\frac{\partial (g(x,y))}{\partial y}}·\sqrt{g(x,y)},$

$S_x^{\frac{1}{2}}g(x,y)=\sqrt{\underset{0}{\overset{x}{\int }}\frac{g(t,y)}{t}dt}·\sqrt{g(x,y)},$     $S_y^{\frac{1}{2}}g(x,y)=\sqrt{\underset{0}{\overset{y}{\int }}\frac{g(x,t)}{t}dt}·\sqrt{g(x,y)}$.