Table 4.

Percentage increase in the rate of heat transfer due to solid nanoparticle volume fraction, when $Nr=Nb=Nt=0.1,Pr=6.2,\epsilon =1.1,c=0.02$.

${\phi }_1={\phi }_2$	$-2{\kappa }_{\mathit{nf}}/{\kappa }_f{c}^{1/2}{\theta }^{\prime }\left(c\right)$ $\left(\mathit{Cu}\right)$	% Increase	$-2{\kappa }_{\mathit{hnf}}/{\kappa }_f{c}^{1/2}{\theta }^{\prime }\left(c\right)$ $\left(A{l}_2{O}_3+Cu\right)$	% Increase
0.0	1.83318		1.83318
0.01	1.89320	3.27409%	1.89413	3.324%
0.02	1.95485	6.6371%	1.95679	6.742%