Box 1.
Problem: A 46-year-old female patient with plasma BUN 74 (average of post dialysis and pre-dialysis BUN described above) and 24-h urine output of 400 ml, urine BUN 350 mg/dl. Height is 165 cm, and weight 54 Kg. Calculate her residual kidney function (Krt/V). |
Solution: |
Step 1: Calculate urea clearance or BUN clearance (urea clearance and BUN clearance is equal) |
BUN clearance=BUNurine x Vurine (in ml/minute)/BUNplasma |
BUNurine=350 mg/dl |
BUNplasma=74 mg/dl |
Vurine in ml/minute=400 ml/(24 x 60) = 400/1440 ml/min |
BUN clearance = (350/74) x (400/1440) = 1.314 ml/min |
Step 2: Calculate Krt/V |
Kr (L/week) = Urea clearance (ml/min) X 10.08 |
Kr=1.314 x 10.08 |
Kr=13.245 L/week |
V = -2.097 + (0.2466 X Weight in Kg) + (0.1069 X Height in cm) |
= - 2.097 + (0.2466 x 54) + (0.1069 x 165) |
=-2.097+13.3164+17.6385=28.8579 L=approximately 28.86 L |
Krt/V=13.245 x 1/28.86=0.4589 |