A 54-year old man is on CAPD for 2 years. He is on 3 exchanges per day with night time dwell. His weight is 65 Kg and height 168 cm. 24-hour peritoneal dialysate drain volume is 10 L, pooled dialysate urea is 42 mg/dL, and plasma urea is 48 mg/dl. Calculate his Kt/V peritoneal dialysis. If his 24-hour urine output is 450 ml, and urine urea concentration is 550 mg/dL, then calculate his residual kidney function, and total weekly Kt/V. Is he receiving adequate CAPD based on your result? |
Answer: |
Step 1: Calculating daily peritoneal urea clearance or Kt |
Kt in Liters = (Durea/Purea) x VD (measured in Liters) |
=(42/48) x 10=0.875 x 10=8.75 L |
Step 2: Calculating V (volume of distribution of urea, that is total body water, by Watson Equation) |
Watson: Male TBW or Volume of distribution of urea in Liters=2.447 - (0.09156 x age) + (0.1074 x height) + (0.3362 x weight) |
= 2.447 - (0.09156 x 54) + (0.1074 x 168) + (0.3362 x 65) |
=2.447-4.9442+18.0432+21.853=37.399 L |
Step 3: Calculating daily peritoneal dialysis achieved (Kt/Vurea) |
=8.75/37.399=0.234 |
Weekly peritoneal dialysis=daily peritoneal dialysis x 7=0.234 x 7=1.638 |
Step 4: Calculating residual kidney function Krt/V: |
Calculate Kr, t, and V (Kr is urea clearance per week, t is time=1 week, and V is volume measured as total body water). |
Kr is calculated in liters per week so we need to convert urea clearance obtained above from ml/min to liters/week. |
Kr (L/week)= Urea clearance (ml/min) X [60 X 24 X 7/1000] = Urea clearance (ml/min) X 10.08 |
V (total body water or volume of distribution of urea) is already calculated above (37.399L) |
Urine volume in 24 hours is 450 ml. |
Urine volume per minute=450/(24 x 60) = 450/1440=0.3125 ml/min |
Urea clearance=Ureaurine X Vurine (in ml/min)/Ureaplasma=550 x 0.3125/48=3.5807 ml/min |
Kr in Liters/week=urea clearance (ml/min) x 10.08=3.5807 x 10.08=36.0935 |
Krt/V = (36.0935 x 1)/37.399=0.9651 |
Step 5: Total Kt/V (Peritoneal dialysis+Residual kidney function) = Kt/V peritoneal + Krt/V=1.638+0.9651=2.6031 |
Based on this result (total Kt/V=2.6031), this patient is receiving adequate peritoneal dialysis [minimum Kt/V urea should be more than 1.7 as per guidelines]. |