Table 1.
Analysis of Variance (ANOVA) for different response variables.
| (a) ANOVA for Fiber Orientation | |||||
|---|---|---|---|---|---|
| Parameter | DF | SS | MS | F | P |
| POLYMER | 3 | 117.7 | 39.2 | 13.58 | 0.000 * |
| ALIGNMENT | 1 | 39,627.0 | 39,627.0 | 13,721.95 | 0.000 * |
| Error | 35 | 101.1 | 2.9 | ||
| Total | 39 | 39,845.8 | |||
| (b) ANOVA for Fiber Diameter | |||||
| Parameter | DF | SS | MS | F | P |
| POLYMER | 3 | 459,946 | 153,315 | 77.49 | 0.000 * |
| ALIGNMENT | 1 | 21 | 21 | 0.01 | 0.918 |
| Error | 35 | 69,252 | 1979 | ||
| Total | 39 | 529,219 | |||
| (c) ANOVA for Tensile Strength | |||||
| Parameter | DF | SS | MS | F | P |
| POLYMER | 3 | 125.94 | 41.981 | 34.20 | 0.000 * |
| ALIGNMENT | 1 | 395.64 | 395.641 | 322.34 | 0.000 * |
| Error | 35 | 42.96 | 1.227 | ||
| Total | 39 | 564.54 | |||
| (d) ANOVA for Suture Retention Strength | |||||
| Parameter | DF | SS | MS | F | P |
| POLYMER | 3 | 902.50 | 300.83 | 1815.37 | 0.000 * |
| ALIGNMENT | 1 | 1000.00 | 1000.00 | 6034.48 | 0.000 * |
| Error | 35 | 5.80 | 0.17 | ||
| Total | 39 | 1908.30 | |||
| (e) ANOVA for Burst Pressure | |||||
| Parameter | DF | SS | MS | F | P |
| POLYMER | 3 | 21,700 | 7233 | 14.08 | 0.000 * |
| ALIGNMENT | 1 | 883,278 | 883,278 | 1719.68 | 0.000 * |
| Error | 35 | 17,977 | 514 | ||
| Total | 39 | 922,955 | |||
* Statistically significant; DF = degree of freedom; SS = sum of squared deviation; MS = Mean squared deviation; F = F-static; P = probability of null hypothesis.