Table 2.

The decision data in HBNS information

	$c_1$	$c_2$	$c_3$
$A_1$	$\left.〈\left\{0.4,0.5\right\},\left\{0.2,0.3\right\},\left\{0.3,0.4\right\},\right)$ $\left(-0.4,-0.2,\left\{-0.4,-0.5\right\}\right.〉$	$\begin{array}{c}\left.〈0.5,\left\{0.1,0.3\right\},0.2,\left\{-0.2,-0.3\right\},\right)\\ \left(-0.7,\left\{-0.4,-0.6\right\}\right.〉\\ \end{array}$	$\begin{array}{c}\left.〈0.2,\left\{0.2,0.3\right\},\left\{0.5,0.6\right\},-0.5,-0.8,\right)\\ \left(\left\{-0.1,-0.3\right\}\right.〉\\ \end{array}$
$A_2$	$\begin{array}{c}\left.〈\left\{0.6,0.7\right\},\left\{0.1,0.2\right\},\left\{0.2,0.3\right\},\right)\\ \left(\left\{-0.2,-0.3\right\},-0.2,-0.7\right.〉\\ \end{array}$	$\begin{array}{c}\left.〈\left\{0.6,0.7\right\},\left\{0.1,0.2\right\},\left\{0.2,0.3\right\}\right),\\ \left\{-0.2,-0.3\right\},\left(-0.8,-0.7\right.〉\\ \end{array}$	$\begin{array}{c}\left.〈\left\{0.3,0.6\right\},\left\{0.3,0.5\right\},0.1,\right)\\ \left(-0.2,-0.4,-0.7\right.〉\\ \end{array}$
$A_3$	$\begin{array}{c}\left.〈\left\{0.3,0.6\right\},0.2,0.4,\left\{-0.3,-0.4\right\},\right)\\ \left(\left\{-0.2,-0.3\right\},-0.5\right.〉\\ \end{array}$	$\begin{array}{c}\left.〈\left\{0.5,0.6\right\},\left\{0.2,0.3\right\},0.4,\right)\\ \left(-0.3,-0.7,-0.7\right.〉\\ \end{array}$	$\begin{array}{c}\left.〈\left\{0.5,0.6\right\},0.3,0.2,\left\{-0.1,-0.3\right\},\right)\\ \left(-0.6,-0.4\right.〉\\ \end{array}$
$A_4$	$\begin{array}{c}\left.〈0.7,\left\{0.0,0.1\right\},\left\{0.1,0.2\right\},-0.2,-0.1,\right)\\ \left(\left\{-0.7,-0.8\right\}\right.〉\\ \end{array}$	$\begin{array}{c}\left.〈0.6,0.1,\left\{0.1,0.3\right\},\right)\\ \left(-0.2,-0.8,\left\{-0.6,-0.7\right\}\right.〉\\ \end{array}$	$\begin{array}{c}\left.〈0.4,0.3,\left\{0.1,0.2\right\},\left\{-0.1,-0.2\right\},\right)\\ \left(-0.7,-0.3\right.〉\\ \end{array}$