Table 1.

p-values of testing the association between CNV sequential order and RMS subtype trying different CNV group sizes. n is the group size and (#) denotes the total number of CNVs on the chromosome.

Chr.	#CNV	n = 1	n = 2	n = 3	n = 4	n = 5	n = 6
2	5584	$2.45\times {10}^{-2}$	$5.10\times {10}^{-2}$	$8.31\times {10}^{-2}$	$3.49\times {10}^{-3}$	$4.25\times {10}^{-3}$	$3.21\times {10}^{-2}$
8	5365	$2.61\times {10}^{-5}$	$7.37\times {10}^{-6}$	$1.13\times {10}^{-6}$	$7.63\times {10}^{-7}$	$4.99\times {10}^{-8}$	0
11	3449	$2.03\times {10}^{-2}$	$8.26\times {10}^{-3}$	$2.93\times {10}^{-3}$	$1.54\times {10}^{-3}$	$5.82\times {10}^{-4}$	$1.20\times {10}^{-4}$
13	2462	$1.80\times {10}^{-3}$	$3.56\times {10}^{-3}$	$4.86\times {10}^{-3}$	$6.06\times {10}^{-3}$	$7.89\times {10}^{-3}$	$6.23\times {10}^{-2}$