Table 5:

Classifier performance in discriminating TB patients from non-TB patients: The performance achieved by each considered classifier architecture in terms of the area under the ROC curve (AUC). Optimal classifier hyperparameters, determined during cross-validation, are also shown. Mean and standard deviations of AUC are calculated over the five outer folds of the nested k-fold cross-validation, shown in Figure 7.

Classifier	Feature Hyperparameters	Mean AUC	Mean SD	Mean Accuracy	Mean PPV	Mean NPV	Optimal Classifier Hyperparameters
LR	$\mathcal{M}=13$; $\mathcal{F}=2^{11}$; $\mathcal{S}=1$	0.8000	0.0519	78.82%	75.41%	83.29%	ν1=100, ν2=0.15, ν3=0.85
LR	$\mathcal{M}=13$; $\mathcal{F}=2^{10}$; $\mathcal{S}=1$	0.7842	0.0645	75.93%	72.59%	80.43%	ν1=0.001, ν2=0.25, ν3=0.75
LR	$\mathcal{M}=13$; $\mathcal{F}=2^{11}$; $\mathcal{S}=1$	0.7477	0.0402	72.67%	70.36%	75.56%	ν1=10, ν2=0.15, ν3=0.85
LR	$\mathcal{M}=26$; $\mathcal{F}=2^{11}$; $\mathcal{S}=1$	0.8632	0.0601	84.54%	80.56%	89.71%	ν1 =0.01, ν2 =0.3, ν3 =0.7
LR	$\mathcal{M}=26$; $\mathcal{F}=2^{11}$; $\mathcal{S}=1$	0.7845	0.0491	76.22%	72.9%	80.67%	ν1=0.00001, ν2=0.45, ν3=0.55
LR	$\mathcal{M}=39$; $\mathcal{F}=2^{11}$; $\mathcal{S}=1$	0.7458	0.0531	72.11%	70.14%	74.51%	ν1=0.0001, ν2=0.7, ν3=0.3
LR	$\mathcal{M}=39$; $\mathcal{F}=2^{11}$; $\mathcal{S}=1$	0.7402	0.0455	73.02%	70.57%	76.14%	ν1=0.0001, ν2=0.4, ν3=0.6
LR	$\mathcal{B}=60$; $\mathcal{F}=2^{11}$; $\mathcal{S}=1$	0.7526	0.0507	72.89%	70.26%	76.31%	ν1=0.1, ν2=0.45, ν3=0.55
KNN	$\mathcal{M}=26$; $\mathcal{F}=2^{11}$; $\mathcal{S}=1$	0.7701	0.0505	75.09%	71.89%	79.38%	χ1=80 χ2=20
KNN	$\mathcal{M}=26$; $\mathcal{F}=2^{11}$; $\mathcal{S}=1$	0.7394	0.0385	70.76%	68.95%	72.96%	χ1=60 χ2=15
SVM	$\mathcal{M}=26$; $\mathcal{F}=2^{11}$; $\mathcal{S}=1$	0.7435	0.0543	71.91%	69.69%	74.7%	ζ1=0.01 ζ2=100
SVM	$\mathcal{M}=39$; $\mathcal{F}=2^{10}$; $\mathcal{S}=1$	0.7291	0.0495	70.05%	67.95%	72.71%	ζ1=0.001 ζ2=0.0001
MLP	$\mathcal{M}=13$; $\mathcal{F}=2^{11}$; $\mathcal{S}=1$	0.7389	0.0457	71.16%	68.91%	74.02%	ξ1=80, ξ2=0.0001, ξ3=0.65
MLP	$\mathcal{M}=26$; $\mathcal{F}=2^{11}$; $\mathcal{S}=1$	0.8000	0.0391	77.87%	75.13%	81.28%	ξ1=50, ξ2=0.001, ξ3=0.55
MLP	$\mathcal{M}=39$; $\mathcal{F}=2^{11}$; $\mathcal{S}=1$	0.7742	0.0409	76.47%	73.63%	80.09%	ξ1=30, ξ2=0.01, ξ3=0.35
CNN	$\mathcal{M}=26$; $\mathcal{F}=2^{11}$; $\mathcal{S}=1$	0.7109	0.0409	68.89%	67.7%	70.25%	α1=32 α2=0.3, α3=128
CNN	$\mathcal{M}=39$; $\mathcal{F}=2^{10}$ $\mathcal{S}=1$	0.7001	0.0301	68.71%	67.52%	70.07%	α1=64 α2=0.1, α3=128