Unmanned Aerial Vehicle in the Logistics of Pandemic Vaccination: An Exact Analytical Approach for Any Number of Vaccination Centres

. 2022 Oct 20;10(10):2102. doi: 10.3390/healthcare10102102

Domains: D	Equivalent graphs
D₀( $\frac{1}{\frac{n + 1}{2}} < \frac{d}{C} \leq \frac{1}{\frac{n - 1}{2}})$	G{n, N = 3, ( $\frac{n - 1}{2}$ , $\frac{n - 1}{2}, 1)$ }
$k_{1} (d) = \frac{n - 1}{2}$	G{n, N = 3, ( $\frac{n - 1}{2}$ , $\frac{n - 3}{2}, 2)$ }
	\|, with m = { $\begin{matrix} \frac{n}{4} - \frac{3}{4}, n \in {3 + 4 k / k \in I N} \\ \frac{n}{4} - \frac{5}{4}, n \in {5 + 4 k / k \in I N} \end{matrix}$
	G{n, N = 3, ( $\frac{n - 1}{2}$ , $\frac{n - 1}{2} - m, 1 + m)$ }
D₁( $\frac{1}{\frac{n - 1}{2}} < \frac{d}{C} \leq \frac{1}{\frac{n - 3}{2}})$	G{n, N = 3, ( $\frac{n - 3}{2}$ , $\frac{n - 3}{2}, 3)$ }
$k_{1} (d) = \frac{n - 3}{2}$	G{n, N = 3, ( $\frac{n - 3}{2}$ , $\frac{n - 5}{2}, 4)$ }
	\|, with m = { $\begin{matrix} \frac{n}{4} - \frac{9}{4}, n \in {9 + 4 k / k \in I N} \\ \frac{n}{4} - \frac{11}{4}, n \in {11 + 4 k / k \in I N} \end{matrix}$
	G{n, N = 3, ( $\frac{n - 3}{2}$ , $\frac{n - 3}{2} - m, 3 + m)$ }
D₂( $\frac{1}{\frac{n - 3}{2}} < \frac{d}{C} \leq \frac{1}{\frac{n - 5}{2}})$	G{n, N = 3, ( $\frac{n - 5}{2}$ , $\frac{n - 5}{2}, 5)$ }
$k_{1} (d) = \frac{n - 5}{2}$	G{n, N = 3, ( $\frac{n - 5}{2}$ , $\frac{n - 7}{2}, 6)$ }
	\|, with m = { $\begin{matrix} \frac{n}{4} - \frac{15}{4}, n \in {15 + 4 k / k \in I N} \\ \frac{n}{4} - \frac{17}{4}, n \in {17 + 4 k / k \in I N} \end{matrix}$
	G{n, N =3, ( $\frac{n - 5}{2}$ , $\frac{n - 5}{2} - m, 5 + m)$ }
D₃( $\frac{1}{\frac{n - 5}{2}} < \frac{d}{C} \leq \frac{1}{\frac{n - 7}{2}})$	G{n, N = 3, ( $\frac{n - 7}{2}$ , $\frac{n - 7}{2}, 7)$ }
$k_{1} (d) = \frac{n - 7}{2}$	G{n, N = 3, ( $\frac{n - 7}{2}$ , $\frac{n - 9}{2}, 8)$ }
	\|, with m = { $\begin{matrix} \frac{n}{4} - \frac{21}{4}, n \in {21 + 4 k / k \in I N} \\ \frac{n}{4} - \frac{23}{4}, n \in {23 + 4 k / k \in I N} \end{matrix}$
	G{n, N = 3, ( $\frac{n - 7}{2}$ , $\frac{n - 7}{2} - m, 7 + m)$ }
D_p( $\frac{1}{\frac{n - 1}{2} - p + 1} < \frac{d}{C} \leq \frac{1}{\frac{n - 1}{2} - p})$	G{n, N = 3, ( $\frac{n - 1}{2} - p$ , $\frac{n - 1}{2} - p, 2 p + 1)$ }
$k_{1} (d) = \frac{n - 1}{2} - p$	G{n, N = 3, ( $\frac{n - 1}{2} - p$ , $\frac{n - 3}{2} - p - 1, 2 p + 2)$ }
	\|, with m = { $\begin{matrix} \frac{n}{4} - \frac{3 (2 p + 1)}{4}, n \in {3 + 6 p + 4 k / k \in I N} \\ \frac{n}{4} - \frac{3 (2 p + 1)}{4} - \frac{1}{2}, n \in {5 + 6 p + 4 k / k \in I N} \end{matrix}$
	G{n, N = 3, ( $\frac{n - 1}{2} - p$ , $\frac{n - 1}{2} - p - m, 2 p + 1 + m)$ }