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. 2022 Oct 20;10(10):2102. doi: 10.3390/healthcare10102102
Domains: D ¯ Equivalent graphs
D¯1(1n2<dC≤1n2−1) G{n, N = 3, (n2−1,n2−1, 2)}
k1(d)=n2−1 G{n, N = 3, (n2−1,n2−2, 3)}
|, with m = {n4−32, n∈{6+4k /k∈IN}n4−2, n∈{8+4k /k∈IN}
G{n, N = 3, (n2−1,n2−1−m, 2+m)}
D¯2(1n2−1<dC≤1n2−2) G{n, N = 3, (n2−2,n2−2, 4)}
k1(d)=n2−2 G{n, N = 3, (n2−2,n2−3, 5)}
|, with m = {n4−3, n∈{12+4k /k∈IN}n4−72, n∈{14+4k /k∈IN}
G{n, N = 3, (n2−2,n2−2−m, 4+m)}
D¯3(1n2−2<dC≤1n2−3) G{n, N = 3, (n2−3,n2−3, 6)}
k1(d)=n2−3 G{n, N = 3, (n2−3,n2−4, 7)}
|, with m = {n4−92, n∈{18+4k /k∈IN}n4−5, n∈{20+4k /k∈IN}
G{n, N = 3, (n2−3,n2−3−m, 6+m)}
D¯q(1n2−q+1<dC≤1n2−q) G{n, N = 3, (n2−q,n2−q, 2q)}
k1(d)=n2−q G{n, N = 3, (n2−q,n2−q−1, 2q+1)}
|, with m = {n4−3q2, n∈{6q+4k /k∈IN}n4−(3q+1)2, n∈{6q+2+4k /k∈IN}
G{n, N = 3, (n2−q,n2−q−m, 2q+m)}