Table 4.

The iteration result of linguistic term in PLTS

Iterations k	k = 1	k = 2	k = 3	$\cdots$	Steady values
[− 3,0,3] → [0.2,0.5,0.8]	[0.6631,0.7582,0.7616]	[0.7610,0.7615,0.7615]	[0.7614,0.7615,0.7615]	$\cdots$	[0.7614,0.7615,0.7615]
[− 3,0,3] → [0.2,0.5,0.8]	[0.6657,0.7582,0.7616]	[0.7610,0.7615,0.7616]	[0.7615,0.7615,0.7616]	$\cdots$	[0.7615,0.7615,0.7616]
[− 3,0,3] → [0.2,0.5,0.8]	[0.6681,0.7593,0.7616]	[0.7611,0.7616,0.7616]	[0.7615,0.7616,0.7616]	$\cdots$	[0.7615,0.7616,0.7616]
[− 3,0,3] → [0.2,0.5,0.8]	[0.6135,0.7506,0.7612]	[0.7584,0.7608,0.7609]	[0.7606,0.7609,0.7609]	$\cdots$	[0.7606,0.7609,0.7609]
[− 3,0,3] → [0.2,0.5,0.8]	[0.6984,0.7609,0.7616]	[0.7615,0.7616,0.7616]	[0.7616,0.7616,0.7616]	$\cdots$	[0.7616,0.7616,0.7616]
[− 3,0,3] → [0.2,0.5,0.8]	[0.6606,0.7573,0.7615]	[0.7609,0.7615,0.7615]	[0.7614,0.7615,0.7615]	$\cdots$	[0.7614,0.7615,0.7615]
[− 3,0,3] → [0.2,0.5,0.8]	[0.6630,0.7581,0.7616]	[0.7609,0.7615,0.7616]	[0.7614,0.7615,0.7616]	$\cdots$	[0.7614,0.7615,0.7616]
[− 3,0,3] → [0.2,0.5,0.8]	[0.6495,0.7562,0.7615]	[0.7605,0.7614,0.7615]	[0.7613,0.7614,0.7615]	$\cdots$	[0.7613,0.7614,0.7615]
[− 3,0,3] → [0.2,0.5,0.8]	[0.6775,0.7598,0.7616]	[0.7613,0.7616,0.7616]	[0.7615,0.7616,0.7616]	$\cdots$	[0.7615,0.7616,0.7616]
[− 3,0,3] → [0.2,0.5,0.8]	[0.6877,0.7608,0.7616]	[0.7614,0.7616,0.7616]	[0.7616,0.7616,0.7616]	$\cdots$	[0.7616,0.7616,0.7616]
[− 3,0,3] → [0.2,0.5,0.8]	[0.6404,0.7518,0.7611]	[0.7600,0.7610,0.7608]	[0.7614,0.7615,0.7615]	$\cdots$	[0.7611,0.7610,0.7608]
[− 3,0,3] → [0.2,0.5,0.8]	[0.6731,0.7597,0.7616]	[0.7612,0.7616,0.7616]	[0.7615,0.7616,0.7616]	$\cdots$	[0.7615,0.7616,0.7616]
[− 3,0,3] → [0.2,0.5,0.8]	[0.6607,0.7584,0.7616]	[0.7609,0.7615,0.7616]	[0.7614,0.7615,0.7616]	$\cdots$	[0.7614,0.7615,0.7616]