Table 2B.
Order | Choice | Decisions | Predicted h values | %Consistency | Actual h value(s) |
44% | |||||
1 | (1)10 Yuan 100% vs. (2) 17 Yuan 90% | 2 | 6.30 | ||
56% | |||||
2 | (1) 10 Yuan 100% vs. (2) 17 Yuan 80% | 2 | 2.80 | ||
67% | |||||
3 | (1) 10 Yuan 100% vs. (2) 17 Yuan 70% | 2 | 1.63 | ||
78% | |||||
4 | (1) 10 Yuan 100% vs. (2) 17 Yuan 60% | 2 | 1.05 | ||
89% | 0.86 | ||||
5 | (1) 10 Yuan 100% vs. (2) 17 Yuan 50% | 1 | 0.70 | ||
78% | |||||
6 | (1) 10 Yuan 100% vs. (2) 17 Yuan 40% | 2 | 0.47 | ||
89% | 0.37 | ||||
7 | (1) 10 Yuan 100% vs. (2) 17 Yuan 30% | 1 | 0.30 | ||
78% | |||||
8 | (1) 10 Yuan 100% vs. (2) 17 Yuan 20% | 1 | 0.18 | ||
67% | |||||
9 | (1) 10 Yuan 100% vs. (2) 17 Yuan 10% | 1 | 0.08 | ||
56% | |||||
Geometric mean: 0.57 |
Table Legend: Shown are the nine trials with 17 Yuan and varied probabilities of receiving. Assuming that the h value was between 1.05 and 0.70, the participant should have chosen the probabilistic option in the top four and the certain option from the fifth trial. However, in the sixth trial, the participant chose the probabilistic option. Thus, the consistency for this range was (4+4)/9*100 = 89%. The consistencies of the 10 bounded ranges of h values (including unbounded) were calculated and are shown in Table 2B.