Table 2.
Special Circumstances Allowing (αfb)water (1:10) ≈ (αfb)e-liquida
| case 1 | no protonating acid is present in the e-liquid, so (αfb)e-liquid = 1, and the nicotine concentration after dilution is high enough to yield a relatively high aqueous pH, giving (αfb)water (1:10) ≈ 1 |
| case 2 | a protonating acid is present in the e-liquid and is sufficiently strong to react stoichiometrically with free-base nicotine in both the e-liquid and in water |
| 2a | (eq/L acid/eq/L nicotine) = y < 1: (αfb)e-liquid ≈ (αfb)water (1:10) ≈ 1 − y |
| 2b | (eq/L acid/eq/L nicotine) ≥ 1: (αfb)e-liquid ≈ (αfb)water (1:10) ≈ 0 |
a
Assumes the use of CO2-free water.