Supporting information for Chen et al. (2003) Proc. Natl. Acad. Sci. USA, 10.1073/pnas.0435755100
Supporting Text
Transmittance Measurements
. Beers law states that the transmittance T through a thickness HL of fluid medium containing a dye of absorptivity ε and concentration Cd can be expressed as log T = εCdHL. We used a spectrophotometer (Hewlett Packard 8453) to measure the transmittance of HL = 1 cm of varying concentrations of dye solutions at the wavelengths corresponding to the emission lines of the mercury lamp (365, 405, and 435 nm) used for exposing photoresist. A plot of logT vs. CdHL (Fig. 5, orange, blue, and green squares) for each wavelength reveals the linearity expected from Beers Law. The linear fits (solid lines) had r2 values of 0.9994, 0.9985, and 0.9991 for T365nm, T405nm, and T435nm, respectively.Average Transmittance
. The relative intensities of the emission lines (365, 405, and 436 nm) of our lamp were 2, 4, and 3, respectively, as measured by a UV-intensity meter (Vari-Wave, Quintel). Thus we can find an average transmittance Tavg asT
avg = (2 × T365nm + 4 × T405nm + 3 × T435nm)/9for each CdHL value (Fig. 5, black squares). The log(Tavg) values also follow a clear linear relationship with CdHL and can be linear-fitted to log(Tavg) = εavgCdHL (Fig. 5, black line, r2 = 0.9933) to find εavg = 9.19373 liters/g·cm. For simplicity, we use this value to generate the Tavg simulation in Fig. 3. We note that Tavg is an average over wavelength. To consider the effect of a double exposure, one must use an effective transmittance (i.e., averaged over time). Because both exposures lasted the same amount of time, t = 78 s, the effective transmittance, Teff, is the average of the two transmittances over the total exposure time, 2t. The energy deposited in the photoresist is E = Io × T × t, where Io is the intensity of the UV lamp, and t is the exposure time. In two subsequent exposures of same duration t through masks of different T, the total energy is ET = Io × (T1 + T2) × t. This is equivalent to the energy deposited in a single exposure of duration 2t through a mask of effective transmittance, Teff = (T1 + T2)/2, ET = Io × Teff × 2t.
Transmittance in the Microfluidic Photomasks (µFPMs).
In a typical µFPM with HL = 50 µm, the light-absorbing path is 200 times shorter than the 1-cm-long path used for Fig. 5, hence we used 200 times higher Cd values in the microchannels to study the same range of CdHL values. Fig. 6 shows measured photoresist heights after exposure through µFPMs in eight different experiments (five different Cd values per µFPM, with CdHL in the range of 0270 mg·cm/liter); the µFPMs had a channel height HL = 62.4 µm (circles) or HL = 38.9 µm (triangles). The lowest Tavg (darkest gray) that can be achieved depends on the solubility of the dye, which is 140 g/liter in 3:5 water/glycerol. For a 50-µm-high µFPM, the maximal CdHL value would be 700 mg·cm/liter, yielding Tavg = 4 × 107. From Fig. 6 it is clear that for the exposure and developing times used in this work (156 s and 9 min, respectively), the dynamic range of photoresist falls within CdHL = 0100 mg·cm/liter, i.e., Tavg = 10100% (see Fig. 6, top axis). In this range, we were able to reliably achieve photoresist heights ranging from 0% to 100% of the original unexposed height, demonstrating that an arbitrarily large number of gray-scale levels can be obtained. Note that the curves would vary with photoresist type and would shift down with longer developing times or higher exposure doses, and therefore the actual dependence of photoresist height on Tavg (as in any gray-scale photolithography approach) needs to be calibrated for different experimental protocols.Phase Effect at the Microchannel Walls
. At every PDMSliquidphotoresist interface, a phase shift of δ = 2πΔnHL/λ occurs (1), where Δn is the difference between the refractive index of PDMS and that of the liquid, λ is the wavelength of incident light, and HL (HL >> λ) is the height of the microchannel. Thus small variations in HL result in unpredictable interference conditions ranging from fully constructive to fully destructive. To make the refractive index of the dye solution match that of PDMS (i.e., Δn 0), we add glycerol (in an amount empirically determined for each dye concentration) to the solution. The rationale for choosing glycerol is that nPDMS = 1.4, somewhat in between nwater = 1.33 and nglycerol = 1.47 (20ºC and 589 nm; ref. 2). For the channel in Fig. 2D (67 µm high), a water/glycerol ratio of 3:5 and a dye concentration Cd =39.3 g/liter resulted in no ripples.1. Rogers, J. A., Paul, K. E., Jackman, R. J. & Whitesides, G. M. (1997) Appl. Phys. Lett. 70, 26582660.
2. Lide, D. R. (2002) CRC Handbook of Chemistry and Physics (CRC, Cleveland), 83rd Ed.