Abstract
The set‐coloring Ramsey number is defined to be the minimum such that if each edge of the complete graph is assigned a set of colors from , then one of the colors contains a monochromatic clique of size . The case is the usual ‐color Ramsey number, and the case was studied by Erdős, Hajnal and Rado in 1965, and by Erdős and Szemerédi in 1972. The first significant results for general were obtained only recently, by Conlon, Fox, He, Mubayi, Suk and Verstraëte, who showed that if is bounded away from 0 and 1. In the range , however, their upper and lower bounds diverge significantly. In this note we introduce a new (random) coloring, and use it to determine up to polylogarithmic factors in the exponent for essentially all , , and .
Keywords: probabilistic method, Ramsey theory, random graphs
1. INTRODUCTION
The ‐color Ramsey number is defined to be the minimum such that every ‐coloring of the edges of the complete graph on vertices contains a monochromatic clique of size . These numbers (and their extensions to general graphs, hypergraphs, etc.) are among the most important and extensively‐studied objects in combinatorics, see for example the beautiful survey article [6].
In this paper, we will study the following generalization of the ‐color Ramsey numbers.
Definition 1.1
The set‐coloring Ramsey number is the least such that every coloring contains a monochromatic clique of size , that is, a set with and a color such that for every .
In other words, we assign a set of colors to each edge of the complete graph, and say that a clique is monochromatic if there exists a color that is assigned to every edge of the clique. Note that when this is simply the usual ‐color Ramsey number , for which the best known bounds are
Both bounds have simple proofs: the upper bound follows from the classical method of Erdős and Szekeres [8], while the lower bound can be proved using a simple product coloring due to Lefmann [11]. Determining whether or not is a major and longstanding open problem, see for example the recent improvements of the lower bound in [3, 13, 14].
The study of set‐coloring Ramsey numbers was initiated in the 1960s by Erdős, Hajnal and Rado [7], who conjectured that for some function as . This conjecture was proved by Erdős and Szemerédi [9] in 1972, who showed that in fact
The lower bound follows from a simple random coloring, while to prove the upper bound Erdős and Szemerédi showed that any 2‐coloring in which one of the colors has density at most contains a monochromatic clique of size , where , and then applied this result to the color that is assigned to most edges.
For more general values of , the first significant progress was made only recently, by Conlon, Fox, He, Mubayi, Suk and Verstraëte [4], who showed that
for every function such that is bounded away from 0 and 1. More precisely, they used a clever generalization of the approach of Erdős and Szemerédi [9] to prove that
| (1) |
for some absolute constant , and defined a product colouring, which exploited an interesting and surprising connection with error‐correcting codes, to show that
| (2) |
for some constant . They also noted that a simple random coloring gives a lower bound of the form , which is stronger when .
While the exponents in (1) and (2) differ by only a factor of when , they diverge much more significantly when .1The main result of this paper is the following improved lower bound, which will allow us to determine up to a poly‐logarithmic factor in the exponent for essentially all , , and .
Theorem 1.2
There exist constants and such that the following holds. If with , then
(3) for every , where .
Note that the bound (3) matches the upper bound (1) on , proved in [4], up to a factor of in the exponent for all . When our method does not provide a construction, but in this case the bounds from [4] only differ by a factor of order in the exponent, the lower bound coming from a simple random coloring.
The lower bound on in Theorem 1.2 is also not far from best possible, since if then the most common color has density at least , and therefore , by Turán's theorem. We remark that the range in which Turán's theorem provides an optimal bound was investigated in detail by Alon, Erdős, Gunderson and Molloy [1] in the case . In Section 4, we will describe a simpler version of our construction which proves the lower bound
| (4) |
for all , , and . Note that this bound matches the upper bound (1) up to a factor of order when . Moreover, as long as for some constant , we can use the same construction to prove (with a slightly more careful calculation) a lower bound of the form
| (5) |
Thus, writing to hide poly‐logarithmic factors of , we obtain the following corollary.
Corollary 1.3
Let and , and set . We have
for every .
It would be interesting to determine the behavior of in the range , especially in light of the initial progress made in [1].
2. THE CONSTRUCTION
In this section, we will define the (random) coloring that we use to prove Theorem 1.2, and give an outline of the proof that it has the desired properties with high probability. The idea behind our construction, to let each color be a random copy of some pseudorandom graph, was introduced in the groundbreaking work of Alon and Rödl [2] on multicolor Ramsey numbers, and has been used in several recent papers in the area [10, 12, 13, 14]. However, our approach differs from that used in these previous works in several important ways; in particular, we will not count independent sets, and it will be important that our color classes are chosen (almost) independently at random. We will discuss the novel aspects of our construction in more detail at the end of this section.
Our first attempt at defining a coloring with no monochromatic is as follows: let the edges with be a random blow‐up of the random graph , where , and is chosen so that is unlikely to contain a copy of . The problem with this coloring is that there will be some ‘bad’ edges which receive fewer than colors,2and we will therefore need to modify the construction by giving these edges extra colors. The key idea is to only give them the colors for which they are ‘crossing’ edges, that is, not in the same part of the random blow‐up for that color.
We will next define the coloring precisely. Fix a sufficiently small3 constant , and set . Recall that , and define
Note that , since and , and by our choice of .
Set , and for each color , let
be an independently chosen copy of the random graph , and
be an independently and uniformly chosen random function.
Now define to be the (random) graph with vertex set and edge set
that is, a random blow‐up of , with parts given by . Define a coloring of by
and define the set of bad edges to be
| (6) |
We will also say that an edge is ‐crossing if , and define
We can now define the colouring that we will use to prove Theorem 1.2.
Definition 2.1
For each , we define the set of colors by
Our task is to show that with high probability for every , and moreover that contains no monochromatic copy of . Before giving the details, let us briefly outline how we will go about proving these two properties.
The first property, that for every , is a relatively straightforward consequence of the definition of and our choice of . Indeed, by Definition 2.1 and (6), it will suffice to show that for every , and this follows from a simple first moment calculation, using the fact that .
Proving that with high probability contains no monochromatic copy of is more difficult, and will be the main task of Section 3. Cliques with few bad edges are easily dealt with using Chernoff's inequality, so let us focus here on cliques with many bad edges, where ‘many’ means at least . The difficulty in this case is that the events and are correlated, since the endpoints may be in the same part in some of the random partitions. In particular, if for many colors and many pairs of high‐degree vertices of , the graph of bad edges in our monochromatic ‐clique, then Chernoff's inequality will not provide strong enough bounds on our large deviation events.
To deal with this issue, we will use the randomness of the partitions to show (see Lemma 3.5) that there is not too much ‘clustering’ of the vertices of any graph with vertices and edges. To do so, we will not be able to use a simple union bound over all graphs, since there will be too many choices for the low‐degree vertices of ; instead, we will need to find a suitable ‘bottleneck event’ for each , and apply the union bound to these events. Roughly speaking, we will find an initial segment of the vertices of , ordered according to their degrees, with the following property: there are pairs and such that there exists an ‘earlier’ vertex with . We will then sum over the choices of , using the fact that for each such pair and , this event (conditioned on the choices of for earlier ) has probability at most .
On the other hand, when there is not too much clustering of the high‐degree vertices of in the random partitions , we will use the randomness in the choice of to bound the probability that there are more bad edges than expected. More precisely, we will choose one vertex from each cluster in each color, and apply Chernoff's inequality, noting that the edges between these vertices are independent.
The proof outlined above diverges from the method of Alon and Rödl [2] (and the more recent constructions of [10, 12, 13, 14]) in several important ways. Of these new ideas, we note in particular that our choice of for the bad edges is somewhat subtle (and perhaps surprising), since for almost all edges , which seems very wasteful. The point is that there are very few bad edges, and by only including crossing colors in we ensure that there is not too much dependence between the colors of different edges. It is also important that the random graphs are chosen independently; if we used the same random graph for each color, then we would not be able to prove a sufficiently strong bound on the probability that a clique has too many bad edges.
3. THE PROOF
We begin by observing that with high probability for every .
Lemma 3.1
With high probability, for every .
Note first that, by the definition of , if is not a bad edge then and . It will therefore suffice to show that
(7) for each edge . To do so, note that for each we have
all independently, by the definition of the functions . Recalling that and that , since and , it follows that
Since , we obtain (7), and so the lemma follows by Markov's inequality.
We are left with the (significantly more challenging) task of showing that, with high probability, contains no monochromatic copy of . We will first deal with the (easier) case in which the clique has few bad edges. Recall that .
Lemma 3.2
With high probability, the colouring contains no monochromatic ‐clique with at most bad edges.
Suppose contains a monochromatic clique of color such that at most of the edges are bad. For each , let , and observe that the set has size , since by Definition 2.1, and the fact that , every edge such that is ‐crossing.
Now, if is not a bad edge, then , and hence . Since there are at most bad edges in , it follows that
since and . Since , it follows from Chernoff's inequality4 that this event has probability at most . Therefore, taking a union bound over colors and sets of size , the probability that contains a monochromatic clique with at most bad edges is at most
(8) Since , the right‐hand side of (8) tends to zero as , as required.
It remains to prove the following lemma, which is not quite so straightforward.
Lemma 3.3
With high probability, every ‐clique contains at most bad edges.
In other words, our task is to show that, with high probability, there does not exist a graph in the family
such that .5We will not be able to prove this using a simple first moment argument, summing over all graphs , since the probability of the event is not always sufficiently small. Instead, we will need to identify a ‘bottleneck event’ for each .
To do so, let us first choose an ordering on the vertices of satisfying
In other words, we order the vertices according to their degrees in , breaking ties arbitrarily. Now, define
to be the set of vertices which share a part of with another vertex of that comes earlier in the order . We remark that if , then .
We will bound the probability in two different ways, depending on the size of
When is large, we will find an initial segment of the order such that there are at least pairs and . First, however, we will deal with the case in which is small, where we can use a simple union bound.
Lemma 3.4
With high probability, there does not exist
with
We first reveal the random functions , and therefore the sets (and hence also the random variable ) for each . To prove the lemma we will only need to use the randomness in the choice of . More precisely, we will consider the set
of pairs such that neither endpoint of is contained in , and
the number of such pairs for which . Note that , and that
since the events for are independent, and correspond to the appearance of certain edges in the graphs . Indeed, for each , the graph is contained in a clique with at most one vertex in each part of .
Thus, given (which is determined by ) the random variable is a binomial random variable with expectation
Now, note that if , then for each edge , there are at least colors such that . Thus
and moreover, if , then
since for each vertex we remove at most edges from . By Chernoff's inequality, it follows that for a fixed we have6
Therefore, taking a union bound over , and recalling that , it follows that the probability that there exists with and is at most
as claimed, where in the final step we used our choice of , the bound
which holds by our assumption that , and our choice of .
Finally, we will use the randomness in to show that is always small.
Lemma 3.5
With high probability,
for every .
For each graph , and each , define a set
and a random variable
Note that the random functions determine , and hence . The key step is the following claim, which provides us with our bottleneck event.
Claim 3.6
If , then there exists such that
(9) Observe that
and therefore if , then
(10) Note also that
Thus, if (9) fails to hold for every then, by (10), we have
Since , this is a contradiction, and so the claim follows.
Fix such that (9) holds, and set
Now, if we reveal for the vertices of one vertex at a time using the order , then for each vertex we must choose to be one of the (at most ) previously selected elements of . The expected number of sets such that (9) holds is thus at most7
as , as required, since and .
We remark that a simple union bound over graphs would fail by a factor of (in the exponent), since only implies that there are at least pairs with and , whereas .
Combining Lemmas 3.4 and 3.5, we obtain Lemma 3.3.
Proof of Lemma 3.3
By Lemma 3.5, with high probability we have for every . By Lemma 3.4, it follows that with high probability for every . Therefore, with high probability every ‐clique contains at most bad edges, as claimed.
We can now easily put together the pieces and prove our main theorem.
Proof of Theorem 1.2
With high probability, the random coloring satisfies:
for every , by Lemma 3.1;
contains no monochromatic with at most bad edges, by Lemma 3.2;
every ‐clique contains at most bad edges, by Lemma 3.3.
Thus , as required.
4. A SIMPLER CONSTRUCTION FOR SMALL
To conclude, we will prove the alternative lower bounds (4) and (5), promised in the introduction, which hold for smaller values of . Together with Theorem 1.2 and the results of [4], these bounds will allow us to prove Corollary 1.3.
Theorem 4.1
Let , and set . We have
for every .
Note that Theorem 4.1 only gives a non‐trivial bound when . However, the same construction (together with a slightly more careful calculation) in fact gives an exponential lower bound almost all the way down to the Turán range .
Theorem 4.2
Let and , and set . We have
for some and every .
The construction is a simpler version of the one we used to prove Theorem 1.2: instead of taking blow‐ups of a random graph for our colors, we take blow‐ups of the complete graph with vertices (i.e., we take complete ‐partite graphs). In particular, this means that we do not need to worry about crossing edges.
To define the coloring precisely, let be independent uniformly chosen functions from to , and for each define to be the (random) graph with vertex set and edge set
that is, a random complete ‐partite graph, with parts given by . Define a coloring of the edges of by
Since each color class is ‐partite, contains no monochromatic copy of . Our task is to show that, with positive probability, every edge receives at least colors.
Proof of Theorem 4.1
Let . Since only if , which occurs with probability , independently for each color, it follows that
(11) Thus, if , then the expected number of edges such that is less than 1, and hence there exists a choice of the functions such that every edge receives at least colors, as required.
To prove an exponential bound when , we simply replace the union bound in (11) by an application of Chernoff's inequality.
Proof of Theorem 4.2
We may assume that , since otherwise the claimed bound (with an absolute constant) follows from Theorem 4.1. Let , and recall that the event occurs with probability , independently for each color . Since , it follows by Chernoff's inequality that
for some constant . Thus, if , then the expected number of edges such that is less than 1, and hence there exists a choice of the functions such that every edge receives at least colors, as required.
We can now easily deduce Corollary 1.3.
Proof of Corollary 1.3
The upper bound holds by (1), which was proved in Theorem 1.1 of [4], and holds for all and all . When and , the lower bound follows from Theorem 1.2 (though note that in the case it was first proved in [4]), and when it follows from a simple random coloring (see Section 2 of [4]) that
Finally, when , the lower bound follows from Theorem 4.2.
5. CONCLUDING REMARKS
We expect that determining up to a constant factor for all will be extremely difficult (though it does not seem unreasonable to hope that doing so in this range might prove to be easier than in the case ). On the other hand, the upper and lower bounds in Corollary 1.3 differ by a factor of roughly in the exponent when , and also when . We expect that the lower bound can be improved by a factor of in these cases.
Conjecture 5.1
There exists a constant such that
(12) for every and , where .
It seems plausible that (12) could be proved in the case using a modified version of the construction in Section 4 (taking Turán graphs with fewer parts, and assigning the set to edges with ), since the density of bad edges will be small, and the correlation between them not too large. The obstruction when is potentially more serious, since in this case the density of bad edges will be larger than , so one would not expect the conclusion of Lemma 3.3 to hold. It therefore seems unlikely that the construction from Section 2 can be used to prove (12) in this range.
ACKNOWLEDGMENTS
The research that led to this paper started at WoPOCA 2022. We thank the workshop organizers for a productive working environment. This research was funded in whole, or in part, by the Austrian Science Fund (FWF) P36161. For the purpose of open access, the author has applied a CC BY public copyright licence to any Author Accepted Manuscript version arising from this submission. This study was also financed in part by the Coordenação de Aperfeiçoamento de Pessoal de Nível Superior, Brasil (CAPES), Finance Code 001. This research was supported by: (Maurício Collares) the Austrian Science Fund (FWF P36131); (Taísa Martins) CNPq (Proc. 406248/2021‐4); (Robert Morris) FAPERJ (Proc. E‐26/200.977/2021) and CNPq (Proc. 303681/2020‐9).
Aragão L., Collares M., Marciano J. P., Martins T., Morris R., A lower bound for set‐coloring Ramsey numbers, Random Struct. Alg. 64 (2024), 157–169. 10.1002/rsa.21173
Footnotes
We remark that the range was of particular interest to the authors of [4], who were motivated by an application to hypergraph Ramsey numbers, see [5].
Note that for edges that receive more than colors, we can take an arbitrary subset of size .
In fact taking would suffice, but we will not make any attempt to optimize the constants in Theorem 1.2.
Indeed, the probability that , where , is at most , and .
Here, and below, we abuse notation slightly by treating the set of bad edges as a graph.
Indeed, since is a binomial random variable with expected value at most , the event has probability at most .
Indeed, there are at most choices for the set , and at most choices for the ‘first’ (in some arbitrary order) pairs with and . For each such pair, we must have for some with , and each of these choices is made independently.
DATA AVAILABILITY STATEMENT
Data sharing is not applicable to this article as no new data were created or analyzed in this study.
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