Abstract
Fourier transform infrared studies of active-site-methylated rhodopsin (ASMR) show that, as compared to unmodified rhodopsin, the photoreaction is almost unchanged up to the formation of lumirhodopsin. Especially, the deviations are much smaller than those observed for the corresponding intermediates of 13-desmethyl-rhodopsin. In metarhodopsin-I, larger alterations are present with respect to the three internal carboxyl groups. Similar deviations have been observed in meta-I of 13-desmethyl-rhodopsin. This indicates that, in agreement with our previous investigations, these carboxyl groups are located in close proximity to the chromophore. Because this latter pigment is capable, when bleached, of activating transducin, our data provide support for the earlier conclusion that deprotonation of the Schiff base is a prerequisite for transducin activation. The positions of the C = C and C - C stretching modes of the retinal suggest that the redshift observed in ASMR and its photoproducts can be explained by an increased distance of the Schiff base from the counterion(s). It is further shown that the photoreaction does not stop at metarhodopsin-I, but that this intermediate directly decays to a metarhodopsin-III-like species.
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