Abstract
Let {Sn : n ≥ 0} (S0 = 0) denote the successive sums of independent non-negative random variates, of possibly differing distributions. Define: (1) the number N(b) = inf{n ≥ 0 : Sn > b} of sums in the interval [0,b]; and (2) the overshoot Rb = SN(b) −b. This paper bounds the tail ℙ{Rb > c} and the moments .
Keywords: Renewal theory, excess over the boundary, Lorden's inequality
1 Introduction and Statement of Results
As usual, define ℕ0 := ℕ∪{0} := {0,1,2,…} (“:=” represents a definition). Let (Xn ≥ 0 : n ∈ ℕ) be a sequence of independent non-negative random variates, not necessarily identically distributed. Denote sums of the {Xn} by , where S0 := X0 := 0, and assume that limn→∞ Sn = ∞ with probability 1. For any set A ⊆ ℕ, define the number NmA := #{n ≥ m : Sn ∈ A} of sums following epoch m and falling in the set A. In particular, define
| (1) |
where inf Ø := ∞. For brevity, we sometimes drop the subscript m = 0 on N(b) := N0(b). This paper presents inequalities on the distribution of the overshoot Rb := SN(b) −b beyond the boundary b.
The overshoot plays a central role in renewal theory (Asmussen 2003), where the {Xn} are usually taken to be independent and identically distributed. In that case, let X =d X1 be the generic distributional representative of {Xn}. Elegant coupling methods (Lindvall 1992) yield inequalities on the tail supb≥0 ℙ{Rb > c} and the moments . The best bounds known are (Chang 1994), with the improvement known as Lorden's inequality 𝔼Rb ≤ 𝔼X2/𝔼X for k = 1 (Lorden 1970). The coupling proofs rely heavily on the existence of a stationary distribution limb→∞ ℙ{Rb > c} for the overshoot, however, so ready generalizations to non-identically distributed {Xn} seem unavailable.
Lorden (1970) mentions the bound supb≥0 ℙ{Rb > c} ≤ supx≥0 ℙ{X > x + c|X > x}, where the right side is 0 if ℙ{X > x} = 0. Without giving a specific page number, he ascribes the bound to Wald (1947). Wald's bound becomes particularly simple, if the failure rate (d/dx)[−log ℙ{X > x}] of X is monotone increasing for x ≥ 0 : because then log ℙ{X > x} is concave, i.e., ℙ{X > x + c|X > x} ≤ ℙ{X > c|X > 0}, so supb≥0 ℙ{Rb > c} ≤ ℙ{X > c|X > 0}, with equality if X is exponential. Brown (1980) also gives some related results.
Inequalities on the tail supb≥0 ℙ{Rb > c} are useful outside classical renewal theory. Nonlinear renewal theory (Lai and Siegmund 1977; Lai and Siegmund 1979), where the {Xn} might be neither independent nor identically distributed, sometimes requires the hypothesis limc→∞ supb≥0 ℙ{Rb > c} = 0 (Woodroofe 1990). Other applications, such as the statistical theory justifying the bootstrapping a database ((Green and Brenner 2002); see also the Appendix of (Schaffer et al. 2001)), require inequalities on supb≥0 ℙ{Rb > c} for {Xn} independent but not identically distributed. Accordingly, this paper presents overshoot inequalities for the case of independent but non-identically distributed {Xn}. With extra work, our methods can be applied in even more general circumstances.
To state our main result, let X ≤d X′ denote stochastic inequality: ℙ{X ≥ x} ≤ ℙ{X′ ≥ x} for all x ∈ ℕ and let X =d X′ denote equality of distribution for X and X′. Assume Y̮m ≤d Xn ≤d Y̑m for all n > m ≥ 0, where (Y̮n ≥ 0: n ∈ ℕ0) is stochastically increasing (i.e., Y̮n ≤d Y̮n+1); and (Y̑n ≥ 0: n ∈ ℕ0), stochastically decreasing. For brevity, let Y̮ := Y̮0 and Y̑ := Y̑0, and assume that 0 < 𝔼Y̮ ≥ 𝔼Y̑ < ∞.
We note in passing that the bound Lorden attributes to Wald generalizes directly: for any b,c ≥ 0 and m ∈ ℕ0,
| (2) |
where the right side is 0 if ℙ {Y̮m > y}=0. We prove Eq (2) later, but our main result is Theorem 1.1 below.
Let , where , and the () are independent variates with the same distribution as Y̮m. Abbreviate the average density of renewals as , and , and use the unambiguous abbreviation , where .
Theorem 1.1
Under the above set-up, for any b,c ≥ 0, δ > 0, and m ∈ ℕ0,
| (3) |
. From and , the integration of Eq (3) over c ∈ [0, ∞) yields
| (4) |
Note that the bounds in Eq (3) and (4) can be minimized over δ > 0 and m ∈ ℕ0.
Because 0 ≤ [Y̑ + δ − c]+ ≤ Y̑ + δ, we have limc→∞ 𝔼[Y̑ + δ − c]+ = 0 by dominated convergence. From Eq (3) with m = 0 and any δ > 0 , the conditions of Theorem 1.1 suffice (Woodroofe 1990) to demonstrate that limc→∞ supb≥0 ℙ{Rb > c} = 0.
With m = 0, Eqs (3) and (4) show that ℙ{Rb > c} ≤ 𝔼 [Y̑ + δ−c]+ ρ̮(δ) and independently of b ≥ 0. The bounds are particularly useful in theoretical contexts, because the best bounds known for identically distributed random variates {Xn} (Chang 1994) contain moments of the same order.
If required, the usual methods yield explicit bounds for the renewal density ρ̮m(δ). Coupling, e.g., shows that if pm (δ) := ℙ{Y̮m ≥ δ}, then Bernoulli (pm(δ)) ≤d δ−1Y̮m, so N̮m [0,δ)≤d Geometric (pm(δ)) (the right side being the waiting time for the sum of independent Bernoulli (pm(δ)) variates to leave [0,1)). Thus, 𝔼N̮m [0,δ)≤1/ pm (δ) so ρ̮m (δ)≥ δ−1 / pm (δ). Thus, from Eq (4) for m = 0 and k = 1,
| (5) |
Although Eq (5) does not reduce to equality in any special case, it compares reasonably well with Lorden's inequality supb≥0 𝔼Rb ≤ 𝔼X2/𝔼X, which hypothesizes variates with equal distributions.
In passing, note that the moment generating function ϕm (θ) := 𝔼 exp (θY̮m) and a Chernoff-type inequality with θ < 0 also yield a bound for the renewal density ρ̮m (δ) :
| (6) |
.
The next section proves Theorem 1.1 and concludes with a brief proof of the inequality Eq (2).
2 Proof of Theorem 1.1
Let us bound the tail of the overshoot distribution:
| (7) |
.
To continue from Eq (7), let j = ⌊b/δ⌋, so . Substitute the inclusion into the domain of integration, noting that ℙ{Y̑m > y + c} ≤ ℙ{Y̑m > iδ + c} for y ∈ [iδ,(i + 1)δ) :
| (8) |
because ℙ{Y̑m > iδ + c} ≤ ℙ{Y̑m > y − δ + c} for y ∈ [iδ,(i + 1)δ), and
| (9) |
.
Eq (8) motivates a bound on 𝔼N̮m (t,t+δ]. A minor variation on a standard coupling argument (e.g., (Lindvall 1992)) provides the bound 𝔼N̮m (t,t+δ] ≤ 𝔼N̮m [0,δ). To sketch the argument, construct a probability space containing sequences and , where for and for . In an obvious notation, on this space, so Eq (3) follows. This concludes the proof of Theorem 1.1.
A brief demonstration of the inequality Eq (2) follows. Start as in Eq (7):
| (10) |
Because
| (11) |
Eq (2) is proved.
Acknowledgments
This research was supported by the Intramural Research Program of the National Library of Medicine, NIH.
Footnotes
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