Antiviral treatment for the control of pandemic influenza: some logistical constraints

Abstract

Disease control programmes for an influenza pandemic will rely initially on the deployment of antiviral drugs such as Tamiflu, until a vaccine becomes available. However, such control programmes may be severely hampered by logistical constraints such as a finite stockpile of drugs and a limit on the distribution rate. We study the effects of such constraints using a compartmental modelling approach.

We find that the most aggressive possible antiviral programme minimizes the final epidemic size, even if this should lead to premature stockpile run-out. Moreover, if the basic reproductive number R₀ is not too high, such a policy can avoid run-out altogether. However, where run-out would occur, such benefits must be weighed against the possibility of a higher epidemic peak than if a more conservative policy were followed.

Where there is a maximum number of treatment courses that can be dispensed per day, reflecting a manpower limit on antiviral distribution, our results suggest that such a constraint is unlikely to have a significant impact (i.e. increasing the final epidemic size by more than 10%), as long as drug courses sufficient to treat at least 6% of the population can be dispensed per day.

1. Introduction

The H5N1 virus, with its demonstrated virulence in humans, has drawn widespread attention to the threat of an influenza pandemic (Li et al. 2004; Beigel et al. 2005). Should the virus acquire the ability to easily infect humans, the resulting pandemic would have far-reaching consequences.

Although vaccines are an important means of control for seasonal influenza, with the emergence of a novel pandemic strain, no effective vaccine would be available for at least the first six months (Fedson 2003; Webby & Webster 2003). During this period, control strategies would depend largely on social distancing (e.g. closure of schools and workplaces; UK Health Departments 2005; US Department of Health and Human Services 2005) and stockpiles of antiviral drugs, such as Tamiflu (oseltamivir phosphate).

The role envisaged for Tamiflu in current pandemic plans is chiefly to relieve symptoms in infected individuals. However, there has also been discussion on the use of antiviral drugs for targeted prophylaxis (Longini et al. 2005; McCaw & McVernon in press). In this paper we shall concentrate on the former, assuming that an antiviral stockpile would be intended mainly for treatment rather than prophylaxis. Clinical trials with seasonal influenza have shown Tamiflu to reduce infectiousness and the infectious period (Treanor et al. 2000; Ward et al. 2005), as long as treatment commences within the first 48 hours of symptoms developing. The efficacy of Tamiflu against H5N1 is not yet known; nonetheless, by lowering infection rates, the use of Tamiflu in the community also offers an opportunity to limit the pandemic impact, for example by reducing the overall number of cases.

Previous modelling work on antiviral drugs has addressed such issues as the treatment of health care workers and children (Barnes et al. in press). Ferguson et al. (2005) and Longini et al. (2005) used intensive numerical simulations to consider the effect of targeted antiviral treatment, in combination with other intervention strategies. However, simpler compartmental models have the advantage of being more transparent (Arino et al. 2006). Gani et al. (2005) used this approach to consider optimal targeting strategies for various stockpile sizes. Such models can also be more amenable to understanding the effect of uncertainties such as the efficacy of antiviral drugs. In this paper we use this approach to consider the implications of antiviral run-out, as well as the effect of limited manpower in antiviral distribution.

2. Public health issues

In the ideal antiviral (AV) scenario, there is an unlimited stockpile, a capability to treat an unlimited number of cases per day and a perfectly efficacious drug. None of these will apply in practice, and this prompts the following questions: for given infection and drug efficacy parameters, what stockpile would be sufficient? With a stockpile that is potentially insufficient, is it preferable to adopt an ‘aggressive’ AV programme, dispensing treatment to as many infected cases as possible, or a more ‘conservative’ one, limiting the distribution rate to try and avoid run-out? If there were a limit on the number of cases that can be treated per day, would this have a significant impact?

Once a pandemic-capable strain evolves and starts to spread widely, containment would be unfeasible. We therefore concentrate on the use of antiviral drugs to reduce the impact of a pandemic. In particular, in the absence of reliable data on the effect of AV treatment on hospitalizations, we consider primarily its effect in reducing the overall attack rate (final epidemic size). Additionally, we consider the effect of an AV programme in mitigating the ‘peak pandemic impact’, which includes the following factors: (i) reducing the peak prevalence eases the pressure on public health services; (ii) delaying the epidemic peak affords more time to acquire vaccines or to replenish the AV stock.

3. The basic model

We use a compartmental modelling approach, as developed by Kermack & McKendrick (1927). We write S for the proportion of the population that is susceptible, I_T for the proportion who are infected and receiving treatment, I_N for the proportion who are infected and not receiving treatment, R_T for the proportion who have recovered via treatment and R_N for those who have recovered without treatment.

Regarding AV distribution, an ideal scenario might be that all infected cases receive treatment within 48 hours of developing symptoms. This is infeasible in practice; a certain proportion of cases would be asymptomatic (Couch et al. 1971), and thus tend to escape detection before they can infect others. Moreover, for a very limited stockpile, a policy decision may be taken to preferentially treat those most at risk from secondary complications, such as the elderly, and those with pre-existing conditions (UK Health Departments 2005). We write α for the proportion of infected cases receiving treatment within 48 hours of symptoms. This quantity, the ‘AV coverage’, provides a convenient way of representing the AV programme.

We assume that the effect of treatment is to reduce the infectious period, so that those receiving treatment recover in 1/γ_T days, and the remainder of infected cases recover in 1/γ_N days, where γ_T>γ_N. The model is summarized schematically in figure 1; we assume a constant population size and neglect births and deaths. For simplicity, we do not explicitly include disease-related deaths—to do so is equivalent to modifying the definition of γ_N and γ_T to include removal of infected cases due to mortality (i.e. writing them as recovery rate + death rate), and this does not alter the qualitative behaviour of the model. Where disease-related deaths may be significant, all variables are interpreted as proportions of the initial population size.

Figure 1.

Summary of the basic model, where f=β(I_T+I_N). A proportion α of infected cases receive treatment (class I_T) and recover in 1/γ_T days. The remainder of infected cases (class I_N) recover in 1/γ_N days, where γ_T>γ_N.

The governing equations are as follows:

$$\dot{S}=-\beta S(I_{\text{T}}+I_{\text{N}}),$$ (3.1)

$${\dot{I}}_{\text{T}}=\alpha \beta S(I_{\text{T}}+I_{\text{N}})-{\gamma }_{\text{T}}{I}_{\text{T}},$$ (3.2)

$${\dot{I}}_{\text{N}}=(1-\alpha )\beta S(I_{\text{T}}+I_{\text{N}})-{\gamma }_{\text{N}}{I}_{\text{N}}\text{and}$$ (3.3)

$${\dot{R}}_{\text{T}}={\gamma }_{\text{T}}{I}_{\text{T}},0\le \alpha \le 1,$$ (3.4)

where β is the infection rate and $\dot{S}$ denotes dS/dt. Seeding the epidemic by a small perturbation I_N0 to the disease-free state in class I_N, the initial conditions are

$$I_{\text{N}}=I_{\text{N0}}\ll 1,S=S_0=1-I_{\text{N0}}\text{and}{I}_{\text{T}}=R_{\text{T}}=0\text{at}t=0.$$ (3.5)

For simplicity, we take S₀≈1, I_N0≈0 in the calculations to follow. The number of AV courses that have been dispensed at any given time is R_T+I_T (i.e. a sum of those recovered and those recovering through treatment), and so a stockpile sufficient to treat a proportion M of the population is exhausted when R_T+I_T=M. Where this occurs in the numerical calculation, we set α=0 for all subsequent time.

4. Reproductive numbers

The basic reproductive number R₀ is the average number of secondary cases arising from one index case, in a wholly susceptible population. We define the ‘treated’ reproductive number R_α as the corresponding quantity, but, in the presence of an AV programme, with AV coverage α. Following van den Driessche & Watmough (2002), the next-generation matrix is

$$\left(\begin{array}{cc}\alpha \beta /{\gamma }_{\text{T}}& \alpha \beta /{\gamma }_{\text{N}}\\ (1-\alpha )\beta /{\gamma }_{\text{T}}& (1-\alpha )\beta /{\gamma }_{\text{N}}\end{array}\right).$$ (4.1)

Since this has rank 1, its spectral radius is equal to its trace, giving

$$R_{\alpha }=\alpha \frac{\beta }{{\gamma }_{\text{T}}}+(1-\alpha )\frac{\beta }{{\gamma }_{\text{N}}}\text{and}{R}_0=\frac{\beta }{{\gamma }_{\text{N}}}.$$ (4.2)

There are two possibilities for a pandemic-capable strain: R_α<1<R₀ and 1<R_α<R₀. The first corresponds to successful containment and is a particularly simple case, where I_T, I_N remain small and S≈1 throughout. In this paper we concentrate instead on the second scenario, that is where an epidemic still occurs in the presence of an AV programme, but with a smaller reproductive number than in the case of no treatment.

5. Parameters

We note that the lower γ_T is, the less efficacious the drug is in reducing the infectious period (i.e. residence time in the infected class). We follow Gani et al. (2005) in assuming that the effect of antiviral treatment is to reduce the infectious period from 4 to 2.5 days. In other words, γ_N=0.25, γ_T=0.4.

It is not possible to determine R₀ in advance for a pandemic strain. From past pandemics, however, R₀ has been well approximated by the reproductive number in the early stages of disease spread, when there was almost no immunity in the population. For the second ‘autumn’ wave of the 1918 pandemic, the reproductive number has been estimated to be 2–3 using excess mortality (Mills et al. 2004) and daily case notification data (Chowell et al. 2007). For the first wave, it has been estimated at 1.5 (Chowell et al. 2006). Accordingly, we consider a range of values for R₀: 1.5, 2 and 3, corresponding to values for β: 0.375, 0.5 and 0.75, respectively.

6. Minimum required stockpile: constant α

We first consider the minimum sufficient stockpile for given infection and AV parameters. This is the same as the total AV usage with an unlimited stockpile, which we denote by U=lim_t→∞R_T. Adding equations (3.1) and (3.2) gives $\alpha \dot{S}+{\dot{I}}_{\text{T}}=-{\dot{R}}_{\text{T}}$. Integrating and letting t→∞ yields

$$U(\alpha )=\alpha {\mathcal{R}}_{\infty },$$ (6.1)

where ${\mathcal{R}}_{\infty }=1-{\text{lim}}_{t\to \infty }S$ is the serologic attack rate (final epidemic size). As shown in appendix A.1, equation (6.1) can be used to show that ${\mathcal{R}}_{\infty }$ is a solution of the equation

$${\mathcal{R}}_{\infty }=1-\text{exp}(-R_{\alpha }{\mathcal{R}}_{\infty }),$$ (6.2)

allowing us to determine U as a function of α in (6.1). We note that equation (6.2) is analogous to the final-size equation for an ‘untreated’ epidemic as discussed, for example, by Murray (1989, p. 614), where R_α is replaced by R₀. Figure 2 shows plots of U(α), for different values of R₀. For a given stockpile M and AV coverage α, run-out occurs if M exceeds U(α).

Figure 2.

Plots of AV usage U (or minimum required stockpile) versus coverage α, for different values of R₀.

It is of interest to note that U(α) is not necessarily a monotonically increasing function of α, i.e. that an aggressive AV policy is not necessarily linked with a higher overall AV usage than a more conservative one. In particular, in figure 2 when R₀ is sufficiently low (e.g. R₀=1.5, 2) there is a turning point in U(α), where it is maximum. However, when R₀ is sufficiently high (e.g. R₀=3), an increase in AV coverage α is always associated with an increase in overall AV usage.

This has the following implications for a limited stockpile M. Consider the situation illustrated in figure 3a, where there exists a turning point in U(α) in the range 0<α<1, and the stockpile M is less than the maximum possible AV usage but greater than the AV usage with 100% coverage (i.e. U(1)). Then there are precisely two values of α, say α₁, α₂, where α₁<α₂, such that U(α)=M. Therefore, run-out may be avoided by a sufficiently aggressive programme (i.e. α>α₂), as well as by a sufficiently conservative programme (i.e. α<α₁). This is significant from a disease control point of view: it is straightforward to show, using equations (4.2) and (6.2), that, as long as run-out is avoided, increasing α decreases the attack rate ${\mathcal{R}}_{\infty }$, by lowering the treated reproductive number, R_α. Thus, the former aggressive strategy above represents the more efficient use of a stockpile M, delivering a lower attack rate.

Figure 3.

Illustration of different run-out scenarios. (a) Stockpile of 10% and R₀=1.5. There are precisely two values of AV coverage, marked α₁ and α₂, such that U(α)=M. Run-out may be avoided by α<α₁ or by α>α₂. (b) Stockpile of 30% and R₀=2, 3. Here R₀ is sufficiently large for the antiviral usage U(α) to be monotonically increasing with respect to α. Run-out can be avoided only by a sufficiently low AV coverage.

On the other hand, when M is less than U(1), there is precisely one value of α for which U(α)=M, as illustrated in figure 3b. In this case, run-out can only be avoided by a sufficiently conservative programme.

We can show that, with R₀>1, U(α) has a turning point in the range 0<α<1, if and only if

$$R_0\left(1-\frac{\text{ln}{R}_0}{R_0-1}\right)<R_0-\frac{\beta }{{\gamma }_{\text{T}}}.$$ (6.3)

The r.h.s. is the drug efficacy in reducing infectiousness: it is the reduction, due to treatment, in the average number of secondary cases arising from one clinical case. This result is derived in appendix A.2. If R₀ is sufficiently high to invalidate this inequality, then, with a limited stockpile, R₀ is too high with respect to the drug efficacy for it to be possible to avoid run-out by maximizing α.

7. Run-out scenario: general α

We now consider the implications of run-out. Figure 4 shows a plot of attack rate versus α, for the parameters used in figure 3a. The attack rate is monotonically decreasing with respect to α, except for an interval where it is constant. Figure 3a confirms that this interval is associated with AV run-out.

Figure 4.

Attack rate versus AV coverage α. For R₀=1.5 and a stockpile M=0.1.

Indeed, it can be shown analytically that the attack rate in a run-out scenario is a solution of the equation

$${\mathcal{R}}_{\infty }=1-A\text{exp}(-R_0{\mathcal{R}}_{\infty }),$$ (7.1)

where

$$A=\text{exp}\left[M\left(R_0-\frac{\beta }{{\gamma }_{\text{T}}}\right)\right].$$ (7.2)

This result is derived in appendix A.1.2 and is indeed independent of the AV coverage α. Regarding the role of the constant A, we note that when A=1 we recover the familiar expression for the attack rate for an epidemic without any AV treatment (Murray 1989, p. 614). Moreover, parameters associated with the AV programme (β, M, γ_T) are all contained in A. Thus, A represents the effect of the AV programme, on reducing the attack rate.

However, in a run-out scenario, α can affect the epidemic peak properties. Figure 5 shows numerical plots for the epidemic peak timing and its height; it suggests that, in this model, increasing α can have the effect of delaying the epidemic peak, as well as reducing its height.

Figure 5.

Numerical plots of epidemic peak properties, where prevalence is I_T+I_N. The ‘kinks’ in both plots arise because, for sufficiently high α, the epidemic peak occurs after run-out. Parameters: γ_T=0.4, γ_N=0.25, M=0.2 and R₀=0.25. (a) Peak height and (b) peak timing.

8. Extended model

In order to explore the robustness of these results, the calculations above have been extended to a more biologically detailed model, one that explicitly incorporates the clinical course of infection, as well as broadening the possible effects of AV treatment. Cases of influenza can start being infectious before developing symptoms. Moreover, some infections are subclinical, i.e. never developing symptoms. Longini et al. (2005) estimate the mean latent period (i.e. time from infection to infectiousness) to be 1.2 days, and that individuals subsequently develop symptoms after an average of 0.7 days. It is also estimated that 33% of infected cases will be subclinical.

Accordingly, we assume that a proportion p of infected cases ultimately develop clinical symptoms. These cases are first latent (class L₁), and after 1/σ days become infectious but pre-symptomatic (class L₂). Subsequently, after 1/δ days, they develop symptoms: a proportion α of these cases receives treatment (class I_CT) to recover in 1/γ_T days. The remainder (class I_CN) recover in 1/γ_N days, where again 0<γ_N<γ_T. Overall, therefore, we assume that cases without symptoms do not receive treatment.

The subclinical cases follow a similar course to clinical cases, being first latent (class $L_1^{\prime }$) and after 1/σ′ days becoming infectious (class $L_2^{\prime }$). After another 1/δ′ days, they enter class I_AN, who are also subclinical and infectious. Although there is no clinical distinction between $L_2^{\prime }$ and I_AN, we use this structure to preserve symmetry between the clinical and subclinical courses of infection. Infected cases in class I_AN recover in 1/γ_N days.

We assign an infection rate β_N to all cases that are infectious but without symptoms, i.e. classes L₂, $L_2^{\prime }$ and I_N; these infected cases receive no treatment. Moreover, we now assume that the effect of AV treatment is not only to reduce the infectious period, but also to reduce infectiousness. Thus, we assign infection rates β_CT and β_CN to classes I_CT and I_CN, respectively, where 0<β_CT<β_CN.

This model is summarized in figure 6. The model equations are

$$\dot{S}=-Sf,$$ (8.1)

$${\dot{L}}_1=pSf-\sigma L_1,{\dot{L}}_1^{\prime }=(1-p)Sf-{\sigma }^{\prime }{L}_1^{\prime },$$ (8.2)

$${\dot{L}}_2=\sigma L_1-\delta L_2,{\dot{L}}_2^{\prime }={\sigma }^{\prime }{L}_1^{\prime }-{\delta }^{\prime }{L}_2^{\prime },$$ (8.3)

$${\dot{I}}_{\text{CT}}=\alpha \delta L_2-{\gamma }_{\text{T}}{I}_{\text{CT}},{\dot{I}}_{\text{AN}}={\delta }^{\prime }{L}_2^{\prime }-{\gamma }_{\text{N}}{I}_{\text{AN}},$$ (8.4)

$${\dot{I}}_{\text{CN}}=(1-\alpha )\delta L_2-{\gamma }_{\text{N}}{I}_{\text{CN}}\text{and}$$ (8.5)

$${\dot{R}}_{\text{CT}}={\gamma }_{\text{T}}{I}_{\text{CT}},$$ (8.6)

where

$$f={\beta }_{\text{CT}}{I}_{\text{CT}}+{\beta }_{\text{CN}}{I}_{\text{CN}}+{\beta }_{\text{N}}(L_2+L_2^{\prime }+I_{\text{AN}}).$$ (8.7)

If the disease is seeded by a perturbation in the class L₁ (say) to the disease-free state, then the initial conditions are

$$S=S_0;L_1=1-S_0\ll 1;L_2=I_{\text{CT}}=I_{\text{CN}}=L_1^{\prime }=L_2^{\prime }=I_{\text{AN}}=R_{\text{CT}}=0\text{when}t=0.$$ (8.8)

Once again, for simplicity in the analytical calculations, we shall take S₀≈1, L₁≈0. We note that the basic model is a limiting case of the extended model: the former can be retrieved from the latter by taking p=1, β_CT=β_CN=β and letting σ, δ→∞ in (8.1)–(8.7).

Figure 6.

Schematic illustration of the extended model, where $f={\beta }_{\text{CT}}{I}_{\text{CT}}+{\beta }_{\text{CN}}{I}_{\text{CN}}+{\beta }_{\text{N}}(L_2+L_2^{\prime }+I_{\text{AN}})$.

9. Reproductive numbers

Setting α=0, we follow van den Driessche & Watmough (2002) once again to find R₀. As in the basic model, the next-generation matrix has rank 1, so that the spectral radius is equal to its trace, giving

$$R_0=p\left(\frac{{\beta }_{\text{CN}}}{{\gamma }_{\text{N}}}+\frac{{\beta }_{\text{N}}}{\delta }\right)+(1-p)\left(\frac{{\beta }_{\text{N}}}{{\delta }^{\prime }}+\frac{{\beta }_{\text{N}}}{{\gamma }_{\text{N}}}\right).$$ (9.1)

Similarly, when α is non-zero, we find for the treated reproductive number,

$$R_{\alpha }=R_0-p\alpha \left(\frac{{\beta }_{\text{CN}}}{{\gamma }_{\text{N}}}-\frac{{\beta }_{\text{CT}}}{{\gamma }_{\text{T}}}\right).$$ (9.2)

10. Minimum required stockpile

We assume constant α and an unlimited stockpile. As shown in appendix A.1.1, the total AV usage is given by

$$U(\alpha )=p\alpha {\mathcal{R}}_{\infty }$$ (10.1)

and the overall attack rate ${\mathcal{R}}_{\infty }$ is a solution of the equation

$${\mathcal{R}}_{\infty }=1-\text{exp}(-R_{\alpha }{\mathcal{R}}_{\infty }),$$ (10.2)

the same as equation (6.2) for the basic model. The discussion for the basic model, on the maximum in U(α) and the possibility of avoiding run-out with a sufficiently high α, also applies here. In particular, we have that, with R₀>1, U(α) has a turning point in the range 0<α<1 if and only if

$$R_0\left(1-\frac{\text{ln}{R}_0}{R_0-1}\right)<p\left(\frac{{\beta }_{\text{CN}}}{{\gamma }_{\text{N}}}-\frac{{\beta }_{\text{CT}}}{{\gamma }_{\text{T}}}\right),$$ (10.3)

as derived in appendix A.2. If R₀ is sufficiently high to invalidate this inequality, then U(α) is monotonically increasing for 0≤α≤1 and it is not possible to avoid run-out by maximal coverage. Here again the important parameters are R₀ and the drug efficacy in reducing infectiousness, where the relevant measure of drug efficacy is the reduction, due to treatment, in the average number of secondary cases arising from a single clinical case.

11. Run-out scenario

Relaxing the assumption of constant α, it can be shown that, where a stockpile sufficient to treat a proportion M of the population is exhausted before the end of the epidemic, the overall attack rate ${\mathcal{R}}_{\infty }$ is a solution of the equation

$${\mathcal{R}}_{\infty }=1-A\text{exp}(-R_0{\mathcal{R}}_{\infty }),$$ (11.1)

where

$$A=\text{exp}\left[M\left(\frac{{\beta }_{\text{CN}}}{{\gamma }_{\text{N}}}-\frac{{\beta }_{\text{CT}}}{{\gamma }_{\text{T}}}\right)\right].$$ (11.2)

A derivation of this result is given in appendix A.1.2. Once again we have that, after run-out, the attack rate depends not on the AV coverage, but on the stockpile, and the drug efficacy in reducing infectiousness.

However, the behaviour of the epidemic peak shows an interesting departure from the basic model. Assuming constant α once again, we consider I_CT+I_CN, the proportion of the population that is symptomatic, since it is these infected cases that pose the most immediate challenge to health services. Figure 7a,b shows numerical plots of the epidemic peak height and the peak timing, respectively, where we have used Longini's parameter estimates, stated above, for illustration. Comparing peak timing with figure 5b, it appears to remain true in the extended model that, whether the stockpile is exhausted or not, a higher AV coverage leads to a delayed epidemic peak. However, considering the peak height, whereas in figure 5a it is a decreasing function of α, figure 7a shows an example of a case where peak height can also slightly increase with increasing coverage. This effect also occurs with different values of σ and is stronger with smaller values of δ. It occurs only where the stockpile is exhausted, but suggests a potential trade-off, in an aggressive AV programme, for the benefits of minimizing the number of cases and delaying the epidemic peak.

Figure 7.

Numerical plots of epidemic peak properties for the extended model, measuring I_CT+I_CN. The ‘kinks’ arise because, for sufficiently high α, the peak occurs after run-out. (a) Peak height versus AV coverage. In the run-out range (α>0.32), peak height is an increasing function of α. (b) Peak timing in days versus AV coverage. Parameters: p=0.67, σ=σ′=1/1.2, δ=δ′=1/0.7, γ_T=0.4, γ_N=0.25, β_CT=0.3, β_CN=0.6, β_N=0.39, M=0.1 and R₀=2.5.

12. Limited distribution capacity

We now consider the case of a maximum in the number of treatment courses that can be dispensed per day, due to limits on manpower. We refer to this as a ‘limited distribution capacity’. Returning to the basic model, when there are few infected cases at the beginning of an epidemic, a proportion α₀ receive treatment. As the epidemic progresses, however, there is a limit C to the number of doses of treatment that can be dispensed per day, as a proportion of the population. In other words, we require

$$\alpha \to {\alpha }_0\text{as}{I}_{\text{T}}+I_{\text{N}}\to 0\text{and}(I_{\text{T}}+I_{\text{N}})\alpha \to C\text{as}{I}_{\text{T}}+I_{\text{N}}\to 1.$$ (12.1)

A convenient choice of such α is

$$\alpha =\frac{C}{I_{\text{T}}+I_{\text{N}}}\text{tanh}\left[\frac{{\alpha }_0(I_{\text{T}}+I_{\text{N}})}{C}\right].$$ (12.2)

When C→∞ we have constant α=α₀, which will be our baseline in discussing the effect of finite C. We also assume an unlimited stockpile, since the post-run-out results above apply for any α, and hence also hold in this case.

Assuming R₀=2, attack rates were computed numerically for different values of α₀ and C and are plotted in figure 8a. The attack rate can depend sensitively on C, when the latter is sufficiently small. This is because a decrease in α during the course of an epidemic is self-reinforcing: it leads to an increase in infections, compared with the case of constant α, which in turn reduces α still further.

Figure 8.

(a) Calculated attack rate versus distribution capacity C, for different values of α₀. (b) Prevalence versus time under a limited distribution capacity, α₀=0.6, for different values of C. Parameters: γ_N=0.25, γ_T=0.4 and R₀=2.

However, if C is sufficiently high, it has no significant effect on the attack rate, nor on the course of the epidemic, as shown by a comparison of the cases C=0.25 and 0.1 in figure 8b. To quantify this, we say that a limited distribution capacity ‘fails’ if it results in an increase in the attack rate of greater than 10%, compared with the case of unlimited distribution capacity (constant α). We choose this figure as an estimated lower bound on the increase in attack rate that may be considered significant in terms of policy. Numerically, for a given α₀ we calculate the value of C yielding a 10% increase in the attack rate, and maximize this over α₀, to give C_fail. Thus, for given AV and infection parameters, any AV programme capable of dispensing treatment to at least a proportion C_fail of the population would avoid failure, whatever the value of α₀. Figure 9 shows plots of C_fail versus R₀, for different values of γ_T. In all of the curves, C_fail is a decreasing function of R₀ if the latter is sufficiently high, and this is because in such cases there is little percentage difference in attack rate between the cases of limited and unlimited distribution capacity. Overall, figure 9 suggests that, with R₀ in the range of 1–3 estimated from past pandemics, distribution ‘failure’ would be avoided as long as there is a capability of distributing drugs to at least 6% of the population per day. This value is decreased by taking a threshold higher than 10% for failure and vice versa.

Figure 9.

Minimum required distribution capacity C_fail, to ensure that attack rate is within 10% of the case of unlimited distribution capacity, versus R₀, for different values of γ_T. The ‘termination’ of each curve is where R₀ is sufficiently high that the percentage difference in attack rate between even the two most extreme cases, C=0 and C→∞, is less than 10%. γ_N=0.25.

13. Summary

Much of the previous modelling work on the use of AVs in a pandemic has concentrated on containment at the source (Ferguson et al. 2005; Longini et al. 2005), and on the use of drugs in conjunction with other interventions such as case isolation and air traffic reduction (Flahault et al. 2006; Colizza et al. 2007). Should containment fail, however, a widespread AV programme by itself would have a ‘society-wide’ effect by reducing the disease reproductive number, and such an effect has also been noted by Gani et al. (2005). Using a simple model we have explored some implications of this effect, with two types of logistical constraints: a limited stockpile and a limited distribution capacity.

We find that the most aggressive possible AV programme can offer several benefits: first, it minimizes the overall attack rate, even if it should lead to run-out. A conservative programme, while avoiding run-out, would dispense fewer courses of treatment overall, without the society-level benefit of widespread aggressive AV treatment and would thus result in a higher epidemic size. Second, if R₀ is not too high, a sufficiently aggressive AV programme can avoid run-out altogether, by lowering disease spread to such an extent that the required AV stockpile is also sufficiently lowered. We have derived a condition on R₀, in terms of the drug efficacy, for this to be possible. Third, our numerical results suggest that, whether run-out occurs or not, an aggressive AV policy would delay the epidemic peak. In practical terms, this could buy valuable time for the development of an effective vaccine, or to replenish the stockpile.

Nonetheless, an aggressive AV policy is not without risk: where it would lead to run-out, we have seen an instance of an aggressive programme leading to a higher epidemic peak than a more conservative one. Such an effect would place a greater peak burden on health services, and further work is required to determine under which conditions this effect could occur. Another potential issue with an aggressive programme, which we have not considered in detail here, is the emergence of drug resistance (Lipsitch et al. 2007). Indeed, cases have been recorded of resistance of H5N1 against Tamiflu in humans (De Jong et al. 2005). The benefits discussed above must therefore be weighed against the possibility of these effects occurring.

Even with an unlimited stockpile, however, an AV programme would be constrained by an upper limit on the number of treatment courses that can be dispensed per day. We have found that the attack rate and peak prevalence can increase significantly, if this ceiling in distribution is reached; however, for the parameters we have adopted here, a capability of dispensing courses of drugs to at least 6% of the population per day should avoid this occurring. This low threshold suggests that, in practice, it would be unlikely for a limited distribution capacity to be a significant issue.

Appendix A. Technical supporting information

Note. The basic model is a limiting case of the extended model presented above: the former follows from the latter by allowing σ, δ→∞, and setting p=1, β_CT=β_CN=β. For brevity, we therefore present the following derivations for the extended model only, and briefly show how the results from the basic model can be obtained from these.

A.1 Final epidemic size

Relaxing the assumption of constant α, we derive a ‘final-state equation’ that is valid, whether the stockpile is exhausted or not. We work on equations (8.1)–(8.6) of the extended model. For simplicity in the calculations to follow, we shall approximate the initial conditions by S≈1 and all other variables being 0 at t=0. Dividing (8.1) by S and integrating,

$$-\text{ln}S(t)={\int }_0^t{\beta }_{\text{CT}}{I}_{\text{CT}}+{\beta }_{\text{CN}}{I}_{\text{CN}}+{\beta }_{\text{N}}\left(L_2+L_2^{\prime }+I_{\text{AN}}\right)\text{d}\tau .$$ (A1)

The first integral term on the r.h.s. is proportional to R_CT, from (8.6). Letting t→∞, and noting that ${\text{lim}}_{t\to \infty }S=1-{\mathcal{R}}_{\infty }$,

$$-\text{ln}(1-{\mathcal{R}}_{\infty })=\frac{{\beta }_{\text{CT}}}{{\gamma }_{\text{T}}}\underset{t\to \infty }{\text{lim}}{R}_{\text{CT}}+{\int }_0^{\infty }{\beta }_{\text{CN}}{I}_{\text{CN}}+{\beta }_{\text{N}}\left(L_2+L_2^{\prime }+I_{\text{AN}}\right)\text{d}\tau .$$ (A2)

To find the remaining terms on the r.h.s., we note, from (8.1)–(8.5), that

$$p\dot{S}+{\dot{L}}_1+{\dot{L}}_2=-\delta L_2$$ (A3)

$$p\dot{S}+{\dot{L}}_1+{\dot{L}}_2+{\dot{I}}_{\text{CT}}+{\dot{I}}_{\text{CN}}=-{\gamma }_{\text{N}}{I}_{\text{CN}}-{\gamma }_{\text{T}}{I}_{\text{CT}},$$ (A4)

$$(1-p)\dot{S}+{\dot{L}}_1^{\prime }+{\dot{L}}_2^{\prime }=-{\delta }^{\prime }{L}_2^{\prime }\text{and}$$ (A5)

$$(1-p)\dot{S}+{\dot{L}}_1^{\prime }+{\dot{L}}_2^{\prime }+{\dot{I}}_{\text{AN}}=-{\gamma }_{\text{N}}{I}_{\text{AN}}.$$ (A6)

Integrating each of these equations in turn, letting t→∞ and noting that all infected classes tend to 0 in this limit,

$$p{\mathcal{R}}_{\infty }=\delta {\int }_0^{\infty }{L}_2\text{d}\tau ,p{\mathcal{R}}_{\infty }={\gamma }_{\text{N}}{\int }_0^{\infty }{I}_{\text{CN}}\text{d}\tau +\underset{t\to \infty }{\text{lim}}{R}_{\text{CT}}\text{and}$$ (A7)

$$(1-p){\mathcal{R}}_{\infty }={\delta }^{\prime }{\int }_0^{\infty }{L^{\prime }}_2\text{d}\tau ,(1-p){\mathcal{R}}_{\infty }={\gamma }_{\text{N}}{\int }_0^{\infty }{I}_{\text{AN}}\text{d}\tau .$$ (A8)

Substituting these terms into (A 2) and recalling (9.1) yield the final-state equation

$$\text{ln}(1-{\mathcal{R}}_{\infty })=\left(\frac{{\beta }_{\text{CN}}}{{\gamma }_{\text{N}}}-\frac{{\beta }_{\text{CT}}}{{\gamma }_{\text{T}}}\right)\underset{t\to \infty }{\text{lim}}{R}_{\text{CT}}-R_0{\mathcal{R}}_{\infty }.$$ (A9)

As an aside, we can show with the same working that this equation applies also for the basic model, but with β_CN=β_CT=β.

It is now straightforward to distinguish between the cases of sufficient and insufficient stockpiles.

A.1.1 Sufficient stockpile

Where the stockpile avoids exhaustion, we have, from (8.1)–(8.4),

$$\alpha (p\dot{S}+{\dot{L}}_1+{\dot{L}}_2)+{\dot{I}}_{\text{CT}}=-{\gamma }_{\text{T}}{I}_{\text{CT}}.$$ (A10)

Assuming now constant α, integrating and letting t→∞, we find

$$\underset{t\to \infty }{\text{lim}}{R}_{\text{CT}}=p\alpha {\mathcal{R}}_{\infty }.$$ (A11)

By definition, the l.h.s. is U(α), and so this is a derivation of equation (10.1) for the overall AV usage. Substituting (A 11) into (A 9) and rearranging,

$${\mathcal{R}}_{\infty }=1-\text{exp}(-R_{\alpha }{\mathcal{R}}_{\infty }),$$ (A12)

where R_α is given by (9.2). The corresponding result (6.2) for the basic model is obtained by taking R_α given in (4.2).

A.1.2 Insufficient stockpile

Where a stockpile sufficient to treat a proportion M of the population is exhausted before the end of the epidemic, we have simply ${\text{lim}}_{t\to \infty }{R}_{\text{CT}}=M$. Substituting into (A 9) and rearranging this gives

$${\mathcal{R}}_{\infty }=1-A\text{exp}(-R_0{\mathcal{R}}_{\infty }),$$ (A13)

where

$$A=\text{exp}\left[M\left(\frac{{\beta }_{\text{CN}}}{{\gamma }_{\text{N}}}-\frac{{\beta }_{\text{CT}}}{{\gamma }_{\text{T}}}\right)\right],$$ (A14)

independent of α. The corresponding result (7.1), (7.2) for the basic model is obtained by taking β_CN=β_CT=β, and R₀ as given in (4.2).

A.2 Maximizing antiviral usage with respect to α

We seek to maximize

$$U(\alpha )=p\alpha {\mathcal{R}}_{\infty },$$ (A15)

where p is a constant, set to unity in the basic model, ${\mathcal{R}}_{\infty }$ is given by (A 12), and R_α by (9.2).

First, it follows from (A 15) that dU/dα=0 when

$${\mathcal{R}}_{\infty }=-\alpha \frac{\text{d}{\mathcal{R}}_{\infty }}{\text{d}\alpha }.$$ (A16)

Differentiating both ${\mathcal{R}}_{\infty }$ and R_α with respect to α yields, respectively,

$$\frac{\text{d}{\mathcal{R}}_{\infty }}{\text{d}\alpha }\left[\frac{1}{1-{\mathcal{R}}_{\infty }}-R_{\alpha }\right]={\mathcal{R}}_{\infty }\frac{\text{d}{R}_{\alpha }}{\text{d}\alpha }\text{and}$$ (A17)

$$\frac{\text{d}{R}_{\alpha }}{\text{d}\alpha }=-p\left(\frac{{\beta }_{\text{CN}}}{{\gamma }_{\text{N}}}-\frac{{\beta }_{\text{CT}}}{{\gamma }_{\text{T}}}\right).$$ (A18)

Using (A 18) in the r.h.s. of (A 17), substituting for $\text{d}{\mathcal{R}}_{\infty }/\text{d}\alpha$ using (A 16) and rearranging this gives

$${\mathcal{R}}_{\infty }=1-\frac{1}{R_0}.$$ (A19)

Substituting for ${\mathcal{R}}_{\infty }$ into (A 12),

$$R_{\alpha }=\frac{R_0\text{ln}{R}_0}{R_0-1}.$$ (A20)

Using (9.2) to eliminate R_α in (A 20) and rearranging, we can thus express the value of α at a turning point of U(α) as

$${\alpha }_{\text{max}}=\frac{1}{p}{R}_0\left(1-\frac{\text{ln}{R}_0}{R_0-1}\right){{\displaystyle \left(\frac{{\beta }_{\text{CN}}}{{\gamma }_{\text{N}}}-\frac{{\beta }_{\text{CT}}}{{\gamma }_{\text{T}}}\right)}}^{-1}.$$ (A21)

For R₀≥1, this is a strictly increasing function of R₀, and α_max=0 when R₀=1. It follows that, with R₀≥1, we have 0<α_max<1 if and only if

$$0<R_0\left(1-\frac{\text{ln}{R}_0}{R_0-1}\right)<p\left(\frac{{\beta }_{\text{CN}}}{{\gamma }_{\text{N}}}-\frac{{\beta }_{\text{CT}}}{{\gamma }_{\text{T}}}\right).$$ (A22)

The corresponding condition (6.3) for the basic model is obtained by taking p=1, β_CN=β_CT=β.