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Journal of Mathematical Physics logoLink to Journal of Mathematical Physics
. 2015 Sep 11;56(9):091507. doi: 10.1063/1.4930189

Segregated and synchronized vector solutions to linearly coupled systems of Schrödinger equations

Wei Long 1,a), Qingfang Wang 2,b)
PMCID: PMC4570592  PMID: 26396438

Abstract

In this paper, we study the following linearly coupled system ε2Δui+Pi(x)ui=ui3+jiNλijuj,uiH1(R3),i=1,,N, where ε > 0 is a small parameter, Pi(x) are positive potentials, and λij = λji > 0 (ij) are coupling constants for i, j = 1, …, N. We investigate the effect of potentials to the structure of the solutions. More precisely, we construct multi-spikes solutions concentrating near the local maximum point x0i of Pi(x). When x0i=x0j, Pi(x0i)=Pj(x0j)=a,ij,i,j=1,,N, the components have spikes clustering at the same point as ε → 0+. When x0ix0j,ij, the components have spikes clustering at the different points as ε → 0+.

I. INTRODUCTION

This paper is concerned with the following nonlinear Schrödinger (NLS) system in ℝ3:

{ε2Δui+Pi(x)ui=ui3+ijNλijuj,xR3,uiH1(R3),i=1,,N, (1.1)

where ε > 0 is a small parameter, Pi(x) are positive potentials, and λij are coupling constants satisfying λij = λji > 0 for i, j = 1, …, N. This type of system arises when one considers stationary pulselike (standing wave) solutions of the time-dependent N-coupled Schrödinger system of the form

{iħψjtħ22Δψj+Pj(x)ψj=ψj2ψj+kjNλjkψk,xR3,t>0,ψj=ψj(x,t)C,j=1,,N, (1.2)

where i denotes the imaginary unit and ħ is the Plank constant. In fact, system (1.2) appears in nonlinear optics (cf. Ref. 1). For example, the propagation of optical pulses in nonlinear N-core directional coupler can be described by N linearly coupled nonlinear Schrödinger system (1.2). Here, ψj (j = 1, 2…, N) are envelope functions and λjk, which is the normalized coupling coefficient between the cores, is equal to the linear coupling coefficient times the dispersion length. Generally speaking, for system (1.2) with constant potentials, the sign of λjk determines whether the interactions of fiber couplers are repulsive or attractive. In the attractive case, the components of a vector solution tend to go along with each other leading to synchronization, and in the repulsive case, the components tend to segregate with each other leading to phase separations. These phenomena have been documented in numeric simulations (e.g., Ref. 1 and references therein) and in mathematical proofs (e.g., Ref. 18 and references therein). However, if the potentials are not constants, what will happen? That is the main motivation of this paper. In the rest of this paper, we will investigate whether the interactions of fiber couplers are repulsive or attractive in the case of the potentials being not constants.

In particular for N = 1, problem (1.1) is the following classic Schrödinger equation

ε2Δu+P(x)u=up,xRn,u>0, (1.3)

where 1<p<n+2n2. The Equation (1.3) arises in the study of solitary waves in nonlinear equations of the Klein-Gordon or Schrödinger type and has been under extensive studies in recent years (see, e.g., Refs. 8–10, 16, 17, 25, 27, 33, and 34 and references therein).

Recently, the system of Schrödinger equations has been broadly investigated in many aspects, such as the existence and qualitative properties of solutions, asymptotic behavior, concentration, and multi-bump phenomena for semiclassical states. For results in this direction, the readers can refer Refs. 3, 4, 14, 15, 17, 20–22, 26, and 30 and the references therein. Mathematical work on systems with the nonlinearly coupling terms (e.g., the term ijui in (1.1) being replaced by ijNui2uj) has been studied extensively in recent years, for example, Refs. 6, 7, 12, 15, 19, 23, 24, 28, 29, 31, 32, and 35 and references therein, where phase separation or synchronization vector solutions have been proved in several cases. From these papers, we know that the existence of multi-bump solutions requires the presence of a suitable potential depending upon x which breaks the symmetry invariance of the autonomous NLS.

However, as far as we know, it seems that there are few results for linearly coupled system (1.1). In Ref. 18, for ε fixed and sufficiently small λij = λ(ij) > 0, Lin and Peng construct non-radial vector solutions of segregated type with two components having exactly l positive bumps, where l is a positive integer. In Ref. 13, Chen and Zou get positive solutions of the coupled system for sufficiently small ε > 0, which have concentration phenomenon as ε → 0. In Ref. 2, by using concentration compactness principle, Ambrosetti, Cerami, and Ruiz studied the existence of both positive ground and bound states under some decaying assumptions of the potentials at infinity for N = 2. In Ref. 5, Ambrosetti et al. showed that there exists a solution with one multi-bump component having bumps located near some points, while the other component has one negative peak when N = 2.

The main purpose of this paper is to investigate how potentials Pi(x) and coupling constants λij influence the structure of solutions to Equation (1.1). Under some assumptions on λij and Pi(x), we construct multi-peak positive vector solutions for both the segregate case and the synchronize case for problem (1.1).

More precisely, we construct multi-spike solutions concentrating near the local maximum point x0i of Pi(x). When x0i=x0j, Pi(x0i)=Pj(x0j)=a,ij,i,j=1,,N, the components have spikes clustering at the same point as ε → 0+. When x0ix0j,ij, the components have spikes clustering at the different points as ε → 0+.

As for i = 1, …, N, we assume that Pi(x) satisfy the following hypotheses.

(H0): Pi(x) ∈ C1(ℝ3, ℝ) and there exist positive constants bi such that infRNPi(x)bi for all x ∈ ℝ3.

(H1): Suppose that A1, …, Ah ⊂ {1, …, N} disjoint mutually such that s=1hAs={1,,N}. For each As(s = 1, …, h), there exist δs > 0 and x0sR3 such that Pj(x)<Pj(x0s) for xBδs(x0s){x0s} and jAs. For every s, we denote Pk1(x0s)=Pk2(x0s)=as for k1, k2As. Moreover, for every k1As1,  k2As2 (s1s2), we assume x0s1x0s2.

(H2): There exist positive constants Li and θi such that Pi(x)Pi(y)Lixyθi for all x, y ∈ ℝ3, θi > 0.

Our main result is as follows.

Theorem 1.1.

Suppose that (H0), (H1), and (H2) hold. There exists ε0 > 0 such that for any ε ∈ (0, ε0), problem (1.1) has a positive solution (u, …, uNε), with ujε (for every j ∈ {1, …, N}) having multiple spikes clustering near x0s(s=1,,h) provided that

  • (1)

    λAs1<λijλ<miniAsbiAs1, if   i, j belong to the same As,

  • (2)

    λij ∼ εα, if  i, j do not belong to the same As,

where λAs1, α are constants, αmini{θi,1}2, and As denotes the number of the set As’s elements.

In particular, when h = 1, we rewrite Theorem 1.1 in the following form.

Theorem 1.2.

Suppose that (H0), (H1), and (H2) hold and h = 1. Then there is λ > 0 such that λN1<λijλ<mini{1,,N}biN1(ij,i,j=1,,N). For any positive integer k ∈ ℤ+, problem (1.1) has a positive solution (u, …, uNε), with k spikes concentrating near x0 and (u, …, uNε) is a synchronized vector solution for ε sufficient small.

Let us outline the main idea in the proof of Theorem 1.1. Without loss of generality, we only consider the case N = 3, i.e., problem (1.1) can be written as

{ε2Δu+P1(x)u=u3+λ1v+λ2w,xR3,ε2Δv+P2(x)v=v3+λ1u+λ3w,xR3,ε2Δw+P3(x)w=w3+λ2u+λ3v,xR3, (1.4)

where λ1 > 0,  λ2 > 0,  λ3 > 0 are coupling constants. Suppose that

maxBδ(x01){x01}Pi(x)=Pi(x01)=a1,i=1,2

and

maxBδ(x02){x02}P3(x)=P3(x02)=a2,x01x02.

We denote θ1 = min{θ1, θ2, θ3} .

Hereafter,

H=(u,v,w)H1(R3)×H1(R3)×H1(R3):R3P1(x)u2<,R3P2(x)v2<,
R3P3(x)w2<

endowed with following norm:

(u,v,w)2=(u,v,w),(u,v,w)=uε,P12+vε,P22+wε,P32,(u,v,w)H,

where

uε,Pi2=u,uε,Pi=R3(ε2u2+Pi(x)u2),i=1,2,3.

Let Wai denote the solution of the equation

{Δw+aiw=w3,w>0,xR3,w(0)=maxxR3w(x),w(x)H1(R3). (1.5)

Particularly, we set W = W1. It is well-known that W(x)=W(x) is nondegeneracy and satisfies

W(r)<0,limrrN12erW(r)=C>0,limrW(r)W(r)=1.

We will use (U, V, Wa2) = (Wa1λ1, Wa1λ1, Wa2) to build up the approximate solutions for (1.4), where (U, V) = (Wa1λ1, Wa1λ1) is the solution of following equation:

{Δu+a1u=u3+λ1v,xR3,Δv+a1v=v3+λ1u,xR3. (1.6)

We define

Dε,δk,y={x=(y1,,yk)(R3)k:yjBδ(x01),yiyjεlnε12,ij,i,j=1,,k}

and

Dε,δm,z={z=(z1,,zm)(R3)m:zjBδ(x02),zizjεlnε12,ij,i,j=1,,m}.

Fix y=(y1,,yk)Dε,δk,y,  z=(z1,,zm)Dε,δm,z,  we set

Uε,y=i=1kUε,yi(x),Vε,y=i=1kVε,yi(x),Wε,z=i=1mWε,zi(x),

where

Uε,yi=Wa1λ1(xyiε),Vε,yi=Wa1λ1(xyiε),Wε,zi=Wa2(xziε).

We write

Ek,my,z=(φ,ψ,ϕ)H:(Uε,yiyli,Vε,yliyli),(φ,ψ)P1P2=0,Wε,zjzlj,ϕε,P3=0,
i=1,,k,j=1,,m,l=1,2,3

and

Mk,my,z=(y1,,yk,z1,,zm,φ,ψ,ϕ):(y1,,yk)Dε,δk,y,(z1,,zm)Dε,δm,z,
(φ,ψ,ϕ)Ek,my,z.

Here,

(Uε,yiyli,Vε,yiyli),(φ,ψ)P1P2=Uε,yiyli,φε,P1+Vε,yliyli,ψε,P2.

It is easy to see that Theorem 1.1 is a direct consequence of the following result in the case of N = 3.

Theorem 1.3.

Under the assumptions of Theorem 1.1, λ < λ1 < a1, λ2, λ3 ∼ εα, αmin{θ1,1}2, for ε sufficiently small, problem (1.4) has a solution of the form

(uε,vε,wε)=(Uε,y(x)+φε,Vε,y(x)+ψε,Wε,z(x)+ϕε),

where (φε,ψε,ϕε)Ek,my,z.

Remark 1.4.

In Theorem (1.3), taking wε = 0. In a similar way, we can obtain that (uε, vε) = (Uε,y(x) + φε,  Vε,y(x) + ψε) is a synchronized vector solution of Equation (1.1) for N = 2. Similarly, Theorem (1.2) is proved.

To prove Theorem 1.3, we will use the well-known Lyapunov-Schmidt reduction in dealing with the singularly perturbed elliptic problems. For Lyapunov-Schmidt reduction, one needs to use the nondegeneracy of solution of (2.1). So, we will adopt the idea of Ambrosetti, Cerami, and Ruiz in Ref. 2 to research the nondegeneracy of the solutions for the l-linearly coupled Schrödinger equations.

The main difficulty in constructing solutions to the linearly coupled system is to get a better control of the error terms. Compared with non-linearly coupled system, the linear term ∑uj ’s attenuation speed is not enough quick. To overcome this difficulty, we need to adjust the parameter λij to increase the speed of attenuation.

Our paper is organized as follows. In Section II, we will give nondegeneracy of the solution. In Sec. III, we will establish some preliminary estimate. We will carry out a reduction procedure and study the reduced one dimensional problem to prove Theorem 1.3 in Sec. IV. In the Appendix, an energy expansion for the functional corresponding to problem (1.1) will be established.

II. NONDEGENERACY OF THE SOLUTION

First, we will introduce the nondegeneracy of the solutions (u1, …, ul) for the l ≥ 2 coupled Schrödinger equations,

{Δui+aui=ui3+λijluj,xR3,uiH1(R3),i=1,,l, (2.1)

where u1(x) = ⋯ = ul(x) = Wa−(l−1) λ(x).

Proposition 2.1.

If λ(λl1,al1), where λl1 is a positive constant, (u1, …, ul) is nondegeneracy for system (2.1) in (H1(ℝ3))l in the sense that the kernel is given by span {(Wxi,,Wxi)|i=1,2,3}.

Proof.

Following from Ref. 2, let us denote

Zλ{(Wa(l1)λ(xξ),,Wa(l1)λ(xξ)):ξR3}

and

Fλ(u1,,ul)(Δu1+au1u13λj1uj,,Δui+auiui3λjiuj,,Δul+aulul3λjluj). (2.2)

We may take ξ = 0. It is easy to compute

T(Wa(l1)λ,,Wa(l1)λ)Z=span{(Wxi,,Wxi),i=1,2,3}.

On the other hand,

Fλ(Wa(l1)λ,,Wa(l1)λ)(ϕ1,,ϕl)=Δϕ1+aϕ13Wa(l1)λ2ϕ1λj1ϕj
Δϕi+aϕi3Wa(l1)λ2ϕiλjiϕj
Δϕl+aϕl3Wa(l1)λ2ϕlλjlϕj. (2.3)

Letting (ϕ1, …, ϕl) belong to its kernel, by the subtraction of the l equations with each other, we get

Δ(ϕiϕj)+a(ϕiϕj)+(λ3Wa(l1)λ2)(ϕiϕj)=0,(ij,i,j=1,,l).

Taking into account the choice of λ, we have λ3Wa(l1)λ20. Hence, ϕiϕj = 0. Moreover, ϕj satisfies the equation

Δϕj+(a(l1)λ)ϕj3Wa(l1)λ2ϕj=0(j=1,,l).

We conclude that ϕj ∈ span {Wxi,i=1,2,3}. □

III. SOME PRELIMINARIES

Let

Iε(u,v,w)12R3(ε2u2+P1(x)u2+ε2v2+P2(x)v2+ε2w2+P3(x)w2)
14R3(u4+v4+w4)λ1R3uvλ2R3uwλ3R3vw

and

Jε(φ,ψ,ϕ)=Iε(Uε,y+φ,Vε,y+ψ,Wε,z+ϕ),(φ,ψ,ϕ)Ek,my,z.

Expand Jε(φ, ψ, ϕ) as follows:

Jε(φ,ψ,ϕ)=Jε(0,0,0)+ε(φ,ψ,ϕ)+12Lε(φ,ψ,ϕ),(φ,ψ,ϕ)+Rε(φ,ψ,ϕ), (3.1)

where

ε(φ,ψ,ϕ)=R3P1(x)a1Uε,yφ+(P2(x)a1)Vε,yψ+(P3(x)a2)Wε,zϕ
+R3i=1kUε,yi3Uε,y3φ+(i=1kVε,yi3Vε,y3)ψ+(i=1mWε,zi3Wε,z3)ϕ
λ2R3(Uε,yϕ+Wε,zφ)λ3R3(Vε,yϕ+Wε,zψ) (3.2)

and

Lε(φ,ψ,ϕ)=R3(ε2φ2+P1(x)φ2+ε2ψ2+P2(x)ψ2+ε2ϕ2+P3(x)ϕ2)
R3(3Uε,y2φ2+3Vε,y2ψ2+3Wε,z2ϕ2)2λ1R3φψ
2λ2R3φϕ2λ3R3ψϕ. (3.3)

In order to find a critical point for Jε(φ, ψ, ϕ), we need to discuss each term in expansion (3.1).

Lemma 3.1.

There exist a constant C > 0 independent of ε such that

Rε(i)(φ,ψ,ϕ)C(ε32(φ,ψ,ϕ)3i+ε3(φ,ψ,ϕ)4i),i=0,1,2.

Proof.

By (3.1)(3.3), we know that

R(φ,ψ,ϕ)R3i=1k(Uε,yiφ3+Vε,yiψ3)+i=1mWε,ziϕ3+14φ4+14ψ4+14ϕ4.

Let φ˜(x)=φ(εx). Since infR3Pi(x)bi>0, we see

R3φ4dx=ε3R3φ˜4dxCε3R3φ˜2+φ˜22
=Cε3ε3R3(ε2φ2+P1(x)φ2)dx2
Cε3φε,P14. (3.4)

Similar to (3.4), we obtain

R3ψ4dxCε3ψε,P24,R3ϕ4dxCε3ϕε,P34. (3.5)

Using the Hölder inequality, we get

R3i=1kUε,yiφ3i=1k(R3Uε,yi4)14(R3φ4)34
Ci=1k(ε3R3W4)14(ε3φε,P14)34
Cε32φε,P13, (3.6)

and analogously,

R3i=1kVε,yiψ3Cε32ψε,P23,R3i=1mWε,yiϕ3Cε32ϕε,P33. (3.7)

Combining (3.4)(3.7), we find

Rε(φ,ψ,ϕ)C(ε32(φ,ψ,ϕ)3+ε3(φ,ψ,ϕ)4).

Similarly, we deduce that

Rε(φ,ψ,ϕ),(g,h,f)C(ε32(φ,ψ,ϕ)2+ε3(φ,ψ,ϕ)3)(g,h,f)

and

Rε(φ,ψ,ϕ)(g,h,f),(w1,w2,w3)
C(ε32(φ,ψ,ϕ)+ε3(φ,ψ,ϕ)2)(g,h,f)(w1,w2,w3).

Lemma 3.2.

There exist a constant C > 0 independent of ε such that

εC(λ2+λ3)ε32+ε32+θ1+ε32i=1k(P1(yi)P1(x01))+ε32i=1k(P2(yi)P2(x01))
+ε32i=1m(P3(zi)P3(x02))+ε32ijkea1λ1yiyjε+ε32ijmea2zizjε.

Proof.

Directly calculating, we have

i=1kR3(P1(x)P1(x01))Uε,yiφ
=i=1kR3(P1(x)P1(yi)+P1(yi)P1(x01))Uε,yiφ
C(i=1kε32P1(x01)P1(yi)+ε32+θ1)φε,P1. (3.8)

Analogously,

i=1kR3(P2(x)P2(x01))Vε,yiψC(i=1kε32P2(x01)P2(yi)+ε32+θ2)ψε,P2 (3.9)

and

i=1mR3(P3(x)P3(x02))Wε,ziϕC(i=1mε32P3(x02)P3(zi)+ε32+θ3)ϕε,P3. (3.10)

By direct computation, we obtain

R3(j=1kUε,yj3Uε,y3)φCR3ijkUε,yi2Uε,yjφCε32ijkea1λ1yiyjεφε,P1. (3.11)

Similar to (3.12), we get the following result:

R3(j=1kVε,yj3Vε,y3)ψCε32ijkea1λ1yiyjεψε,P2 (3.12)

and

R3(j=1mWε,zj3Wε,z3)ϕCε32ijmea2zizjεϕε,P3. (3.13)

We know

R3Uε,yϕCε32ϕε,P32,R3Vε,yϕCε32ϕε,P32,
R3Wε,zφCε32φε,P12,R3Wε,zψCε32ψε,P22. (3.14)

From (3.8)(3.14) and (3.2), we obtain

εCε32+θ1+ε32i=1kP1(yi)P1(x01)+P2(yi)P2(x01)
+ε32i=1mP3(zi)P3(x02)+(λ2+λ3)ε32+ε32ijkea1λ1yiyjε
+ε32ijmea2zizjε.

IV. THE FINITE-DIMENSIONAL REDUCTION AND PROOF OF THE MAIN RESULTS

In this section, we intend to prove the main theorem by the Lyapunov-Schmidt reduction.

First, we discuss the invertibility of Lε.

Lemma 4.1.

For λ1(λ1,a1), λ2, λ3 ∼ εα and ε sufficiently small, there is a constant ϱ > 0 independent of ε such that

Lε(φ,ψ,ϕ)ϱ(φ,ψ,ϕ),(φ,ψ,ϕ)Ek,my,z,

where λ1 is defined in Proposition 2.1.

Proof.

Arguing by contradiction, we suppose there are (yn,zn)=(y1,n,,yk,n,z1,n,,zm,n)Dεn,δnk,yn×Dεn,δnm,zn and (φn,ψn,ϕn)Ek,myn,zn, with

Lε(φn,ψn,ϕn),(g,h,f)=on(1)(φn,ψn,ϕn)(g,h,f),(g,h,f)Ek,myn,zn. (4.1)

We may assume that (φn,ψn,ϕn)2=εn3. Fix i(i ∈ {1, …, k}),  j(j ∈ {1, …, m}) and let

φ˜n,i=φn(εnx+yi,n),ψ˜n,i=φn(εnx+yi,n),ϕ˜n,j=ϕn(εnx+zj,n).

We have

R3(φ˜n,i2+P1(εnx+yi,n)φ˜n,i2+ψ˜n,i2+P2(εnx+yi,n)ψ˜n,i2)C

and

R3(ϕ˜n,j2+P3(εnx+zj,n)ϕ˜n,j2)C.

So, we suppose the existence of (φ, ψ, ϕ) ∈ (H1(ℝ3))3 such that

φ˜n,iφ,weakly inHloc1(R3),φ˜n,iφ,strongly inLloc2(R3),
ψ˜n,iψ,weakly inHloc1(R3),ψ˜n,iψ,strongly inLloc2(R3),
ϕ˜n,jϕ,weakly inHloc1(R3),ϕ˜n,jϕ,strongly inLloc2(R3).

Moreover, (φ, ψ, ϕ) satisfy

R3(Uylφ+Uylφ+Vylψ+Vylψ)=0,
R3(Wylϕ+Wylϕ)=0,l=1,2,3.

We claim that

φ=0,ψ=0,ϕ=0.

For any (g,h)C0(R3)×C0(R3), we decompose

(gn,hn)=(g,h)i=1kl=13an,i,l(U˜εn,ylt,nylt,n,V˜εn,ylt,nylt,n),

where

U˜εn,yt,n=Uεn,yt,n(εnx+yi,n),V˜εn,yt,n=Vεn,yt,n(εnx+yi,n).

Then, with the same argument as in Ref. 11, it is not difficult to check that an,t,lat,l, an,i,l → 0, it,  l = 1, 2, 3 as n → ∞.

Taking (gn(xyt,nε),hn(xyt,nε),0) into (4.1), we obtain

R3(φg+φg3U2φg)+R3(ψh+ψh3V2ψh)
+l=13at,lR3(Uxlφ+Uxlφ3U2Uxlφ)+(Vxlψ+Vxlψ3V2Vxlψ)
R3λ1(Uxlφ+Vxlψ)λ1R3(φh+ψg)=0,l=1,2,3. (4.2)

Note that

R3Uxlφ+Uxlφ+Vxlψ+Vxlψ
3U2Uxlφ3V2Vxlψλ1(Uxlφ+Vxlψ)=0.

Therefore, we have

R3(φg+φg3U2φg)+R3(ψh+ψh3V2ψh)
λ1R3(φh+ψg)=0.

Then, we get (φ, ψ) that satisfies

{Δφ+a1φ3U2φλ1ψ=0,xR3,Δψ+a1ψ3V2ψλ1φ=0,xR3.

From Proposition 2.1 for l = 2, we have (U, V) = (Wa1λ1, Wa1λ1) which is nondegeneracy, with λ < λ1 < a1, which implies that (φ, ψ) = (0, 0).

Next, we denote

fn=fj=1ml=13an,j,lW˜εn,zr,nzlr,n,

where W˜εn,zr,n=Wεn,zr,n(εnx+zj,n) and taking (0,0,fn(xzr,nε)) into (4.1), we get

R3(ϕf+ϕf3W2ϕf)=0.

We get that ϕ = 0.

Hence, by λ2,λ3εα,α>min{θ1,1}2, we obtain

on(1)εn3=R3(εn2φn2+P1(x)φn2+εn2ψn2+P2(x)ψn2+εn2ϕn2+P3(x)ϕn2)
R3(3Uεn,yn2φn2+3Vεn,yn2ψn2+3Wεn,zn2ϕn2)2λ1R3φnψn
2λ2R3φnϕn2λ3R3ψnϕn
=(1λ1b)(φn,ψn,ϕn)2R3(3Uεn,yn2φn2+3Vεn,yn2ψn2+3Wεn,zn2ϕn2)
+O(εnα)(φn,ψn,ϕn)2
(1λ1b)(φn,ψn,ϕn)2+o(eR)εn3+O(εnα)εn3.

Since b > λ1, we get contradiction. Then, we complete the result. □

Proposition 4.2.

For ε > 0 small enough, there is a C1 map from Dε,δk,y×Dε,δk,y×Dε,δm,z to H such that (φ,ψ,ϕ)Ek,my,z satisfying

Jε(y,z,φ,ψ,ϕ)(φ,ψ,ϕ),(f1,f2,f3)=0,(f1,f2,f3)Ek,my,z.

Moreover,

Proposition 4.2.

Proof.

We know that ℓε(φ, ψ, ϕ) is a bounded linear function in Ek,my,z by Lemma 3.2. Thus, there is ¯ε such that

ε(φ,ψ,ϕ)=¯ε,(φ,ψ,ϕ).

So, finding a critical point for Jε(φ, ψ, ϕ) in Ek,my,z is equivalent to solving

¯εLε(φ,ψ,ϕ)+Rε(φ,ψ,ϕ)=0.

Since Lε is invertible by Lemma 4.1, we get

A(φ,ψ,ϕ)=Lε1¯εLε1Rε(φ,ψ,ϕ).

Set

D=(φ,ψ,ϕ)Ek,my,z:(φ,ψ,ϕ)ε32+θ1τ+(λ2+λ3)ε32τ+ε32i=1k(P1(yi)P1(x01)1τ)
+i=1k(P2(zi)P2(x01)1τ)+i=1m(P3(zi)P3(x02)1τ)
+ε32ijkea1λ1(1τ)yiyjε+ε32ijmea2(1τ)zizjε.

Now, we verify that A is a contraction from D to D. Indeed, for any (φ, ψ, ϕ) ∈ D, by Lemmas 3.1 and 3.2, we obtain

A(φ,ψ,ϕ)C(¯ε+Rε)C(¯ε+ε32(φ,ψ,ϕ)2)
Cε32+θ1+(λ2+λ3)ε32τ+ε32i=1k(P1(yi)P1(x01))2(1τ)
+i=1k(P2(yi)P2(x01))2(1τ)+i=1m(P3(zi)P3(x02))2(1τ)
+ε32ijke2a1λ1(1τ)yiyjε+ε32ijme2a2(1τ)zizjε
ε32+θ1τ+(λ2+λ3)ε32τ+ε32i=1k(P1(yi)P1(x01))1τ
+i=1k(P2(yi)P2(x01))1τ+i=1m(P3(yi)P3(x02))1τ
+ε32ijkea1λ1(1τ)yiyjε+ε32ijmea2(1τ)zizjε,

and we get A maps from D to D. On the other hand, for (φ1, ψ1, ϕ1), (φ2, ψ2, ϕ2) ∈ D and ε sufficiently small, we have

A(φ1,ψ1,ϕ1)A(φ2,ψ2,ϕ2)=Lε1Rε(φ1,ψ1,ϕ1)Lε1Rε(φ2,ψ2,ϕ2)
CRε(φ1,ψ1,ϕ1)+s(φ2,ψ2,ϕ2)(φ1,ψ1,ϕ1)(φ2,ψ2,ϕ2)
C(ε32(φ1,ψ1,ϕ1)+ε3(φ1,ψ1,ϕ1)2)(φ1,ψ1,ϕ1)(φ2,ψ2,ϕ2)
12(φ1,ψ1,ϕ1)(φ2,ψ2,ϕ2).

Therefore, A is a contraction map from D to D. By the contraction mapping theorem, there exist (φ,ψ,ϕ)Ek,my,z such that A(φ, ψ, ϕ) = (φ, ψ, ϕ).

Moreover,

Proof.

Proof of Theorem 1.3.

It follows from Lemma 4.1 and Propositions 4.2 and A.2 that

F(y,z)=Jε(φ(y,z),ψ(y,z),ϕ(y,z))=Iε(Uε,y+φ,Vε,y+ψ,Wε,z+ϕ)=Jε(0,0,0)+ε(φ,ψ,ϕ)+12Lε(φ,ψ,ϕ),(φ,ψ,ϕ)+Rε(φ,ψ,ϕ)=Iε(Uε,y,Vε,y,Wε,z)+O(ε(φ,ψ,ϕ)+(φ,ψ,ϕ)2)=14Aε3ε3(C1i=1k(P1(x01)P1(yi))+C1i=1k(P2(x01)P2(yi))+C2i=1m(P3(x02)P3(zi)))ε3C3ijkea1λ1yiyjεε3C4ijmea2zizjε+O(ε3+θ1),

since λ2,  λ3 ∼ εα, αmin{θ1,1}2.

Consider the following maximization problem:

max(y,z)Dε,δk,y×Dε,δm,zF(y,z). (4.3)

Assume (4.3) is achieved by some (yε,zε)Dε,δk,y×Dε,δm,z, next we claim that (yε, zε) is an interior point of Dε,δk,y×Dε,δm,z.

Let us choose y¯j=x01+L1εlnεej, z¯j=x02+L2εlnεej for L1, L2 > 0, and some vectors e1, e2, …, en, with eiej=1 for ij. Then, y¯iy¯jε=L1lnε, z¯iz¯jε=L2lnε, which means that y¯(y¯1,,y¯k)Dε,δk,y, z¯(z¯1,,z¯m)Dε,δm,z for ε sufficiently small.

Thus, for L1, L2 large enough, we have

14Aε3Cε3(εlnε)min{θ1,1}F(y¯,z¯)F(yε,zε)
14Aε3ε3i=1k(P1(x01)P1(yi))+(P2(x01)P2(yi))
ε3i=1m(P3(x02)P3(zi))ε3ijkea1λ1yiyiε
ε3ijmea2zizjε,

that is,

Proof of Theorem 1.3.

Therefore, we can deduce

i=1k(P1(x01)P1(yi))C(εlnε)min{θ1,1},i=1k(P2(x01)P2(yi))C(εlnε)min{θ1,1},
i=1m(P3(x02)P3(zi))C(εlnε)min{θ1,1},
ijkyiyjεClnε>lnε12,ijmzizjεClnε>lnε12,

which imply that (yε, zε) is an interior point of Dε,δk,y×Dε,δm,z. Then, the corresponding vector function (uε, vε, wε) is a critical point of Iε, where uε=i=1kUε,yi+φε, vε=i=1kVε,yi+ψε, vε=i=1mWε,zi+ϕε.

That uε,  vε,  wε are all positive and can be proved following the argument in Ref. 22. We get (yε, zε) which is an interior point Dε,δk,y×Dε,δm,z. Hence, (Uε,y + φε, Vε,y + ψε, Wε,y + ϕε) is the solution of problem (1.4). □

Acknowledgments

The authors are grateful to the editors and two reviewers for their suggestions and comments. W. Long was partially supported by NSFC (No. 11501264) and the NSF of Jiangxi Province. Q. Wang acknowledges support from the excellent doctorial dissertation cultivation grant from Central China Normal University (2013YBZD16).

The authors sincerely thank Professor Shuangjie Peng for helpful discussions and suggestions.

APPENDIX: ENERGY EXPANSIONS

In this section, we will expand the energies Iε(Uε,y, Vε,y, Wε,z), where

Iε(u,v,w)=12R3(ε2u2+P1(x)u2+ε2v2+P2(x)v2+ε2w2+P3(x)w2)
14R3(u4+v4+w4)λ1R3uvλ2R3uwλ3R3vw.

Proposition A.1 see Ref. 5

Suppose that u(x),v(x)Hr1(RN) satisfy

u(r)rαeβr,v(r)rγeηr(r+),

where α, γ ∈ ℝ, β > 0, η > 0. Let y ∈ ℝN, with y+. We have the following:

  • (i)
    if β < η, then
    R3uyvyαeβy.
  • (ii)
    If β = η, suppose for simplicity that αγ, then,
    R3uyveβyyα+γ+1+N2,ifγ>1+N2,eβyyαlny,ifγ=N+12,eβyyα,ifγ<N+12. (A1)

Proposition A.2.

There is a small constant σ > 0 and positive constants C1,  C2,  C3,  C4 such that

Iε(Uε,y(x),Vε,y(x),Wε,z(x))=14Aε3ε3C1i=1k(P1(x01)P1(yi))
+C1i=1k(P2(x01)P2(yi))+C2i=1m(P3(x02)P3(zi))
ε3C3ijkea1λ1yiyjεε3C4ijmea2zizjε
+O(ε3+θ1), (A2)

where A = (2k + m)∫3W4.

Proof.

By the definition of Iε, we get

Iε(Uε,y,Vε,y,Wε,z)=12R3ε2Uε,y2+P1(x)Uε,y2+ε2Vε,y2+P2(x)Vε,y2
+ε2Wε,z2+P3(x)Wε,z214R3(Uε,y4+Vε,y4+Wε,z4)
λ1R3Uε,yVε,yλ2R3Uε,yWε,zλ3R3Vε,yWε,z
=12R3i=1k(P1(x)P1(x01))Uε,yi2+ijk(P1(x)P1(x01))Uε,yiUε,yj
+i=1k(P2(x)P2(x01))Vε,yi2+ijk(P2(x)P2(x01))Vε,yiVε,yj
+i=1m(P3(x)P3(x02))Wε,zi2+ijm(P3(x)P3(x02))Wε,ziWε,zj
14R3(i=1kUε,yi)4i=1kUε,yi42ijkUε,yi3Uε,yj
14R3(i=1kVε,yi)4i=1kVε,yi42ijkVε,yi3Vε,yj
14R3(i=1mWε,zi)4i=1mWε,zi42ijmWε,zi3Wε,zj
+14R3i=1kUε,yi4+i=1kVε,yi4+i=1mWε,zi4
λ2R3Uε,yWε,zλ3R3Vε,yWε,z. (A3)

By direct computation, we obtain

R3i=1k(P1(x)P1(x01))Uε,yi2+ijk(P1(x)P1(x01))Uε,yiUε,yj
=R3i=1k(P1(x)P1(yi)+P1(yi)P1(x01))Uε,yi2
+ijk(P1(x)P1(yi)+P1(yi)P1(x01))Uε,yiUε,yj
=ε3C1i=1k(P1(x01)P1(yi))+O(ε3+θ1). (A4)

Similar to (A4), we obtain

R3i=1k(P2(x)P2(x01))Vε,yi2+ijk(P2(x)P2(x01))Vε,yiVε,yj
=ε3C1i=1k(P2(x01)P2(yi))+O(ε3+θ2) (A5)

and

R3i=1m(P3(x)P3(x02))Wε,zi2+ijm(P3(x)P3(x02))Wε,ziWε,zj
=ε3C1i=1m(P3(x02)P3(zi))+O(ε3+θ3). (A6)

With elementary computations, we have

R3(i=1kUε,yi)4i=1kUε,yi42ijkUε,yi3Uε,yj
=2R3ijkUε,yi3Uε,yj+O(R3ijkUε,yi2Uε,yj2)
=ε3C2ijkea1λ1yiyjε+O(ε3ijke2a1λ1yiyjεεyiyj2lnyiyj)
=ε3C2ijkea1λ1yiyjε+O(ε3+θ1). (A7)

Similar to (A7), we obtain

R3(i=1kVε,yi)4i=1kVε,yi42ijkVε,yi3Vε,yj=ε3C2ijkea1λ1yiyjε+O(ε3+θ2), (A8)
R3(i=1mWε,zi)4i=1mWε,zi42ijmWε,zi3Wε,zj=ε3C2ijea2zizjε+O(ε3+θ3), (A9)
R3Uε,yiWε,zj=Cε3emin{a1λ1,a2}yizjε=O(ε3+θ1). (A10)

Inserting (A4)(A10) into (A3), we get (A2). □

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