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. 2017 Nov 25;2017(1):292. doi: 10.1186/s13660-017-1568-8

Oscillation and variation inequalities for the multilinear singular integrals related to Lipschitz functions

Yue Hu 1,, Yueshan Wang 2
PMCID: PMC5701964  PMID: 29213199

Abstract

The main purpose of this paper is to establish the weighted (Lp,Lq) inequalities of the oscillation and variation operators for the multilinear Calderón-Zygmund singular integral with a Lipschitz function.

Keywords: oscillation operator, variation operator, multilinear operator, Lipschitz function

Introduction and results

Let K be a kernel on R×R{(x,x):xR}. Suppose that there exist two constants δ and C such that

|K(x,y)|C|xy|for xy; 1.1
|K(x,y)K(x,y)|C|xx|δ|xy|1+δfor |xy|2|xx|; 1.2
|K(x,y)K(x,y)|C|yy|δ|xy|1+δfor |xy|2|yy|. 1.3

We consider the family of operators T={Tϵ}ϵ>0 given by

Tϵf(x)=|xy|>ϵK(x,y)f(y)dy. 1.4

A common method of measuring the speed of convergence of the family Tϵ is to consider the square functions

(i=1|TϵifTϵi+1f|2)1/2,

where ϵi is a monotonically decreasing sequence which approaches 0. For convenience, other expressions have also been considered. Let {ti} be a fixed sequence which decreases to zero. Following [1], the oscillation operator is defined as

O(Tf)(x)=(i=1supti+1ϵi+1<ϵiti|Tϵi+1f(x)Tϵif(x)|2)1/2

and the ρ-variation operator is defined as

Vρ(Tf)(x)=supϵi0(i=1|Tϵi+1f(x)Tϵif(x)|ρ)1/ρ,

where the sup is taken over all sequences of real number {ϵi} decreasing to zero.

The oscillation and variation for some families of operators have been studied by many authors on probability, ergodic theory, and harmonic analysis; see [24]. Recently, some authors [58] researched the weighted estimates of the oscillation and variation operators for the commutators of singular integrals.

Let m be a positive integer, let b be a function on R, and let Rm+1(b;x,y) be the m+1th Taylor series remainder of b at x expander about y, i.e.

Rm+1(b;x,y)=b(x)αm1α!b(α)(y)(xy)α.

We consider the family of operators Tb={Tϵb}ϵ>0, where Tϵb are the multilinear singular integral operators of Tϵ,

Tϵbf(x)=|xy|>ϵRm+1(b;x,y)|xy|mK(x,y)f(y)dy. 1.5

Note that when m=0, Tϵb is just the commutator of Tϵ and b, which is denoted by Tϵ,b, that is to say

Tϵ,bf(x)=|xy|>ϵ(b(x)b(y))K(x,y)f(y)dy. 1.6

However, when m>0, Tϵb is a non-trivial generation of the commutator. It is well known that multilinear operators are of great interest in harmonic analysis and have been widely studied by many authors (see [913]).

A locally integrable function b is said to be in Lipschitz space Lipβ(R) if

b˙β=supI1|I|1+βI|b(x)bI|dx<,

where

bI=1|I|Ib(x)dx.

In this paper, we will study the boundedness of oscillation and variation operators for the family of the multilinear singular integral related to a Lipschitz function defined by (1.5) in weighted Lebesgue space. Our main results are as follows.

Theorem 1.1

Suppose that K(x,y) satisfies (1.1)-(1.3), b(m)˙β, 0<βδ<1, where δ is the same as in (1.2). Let ρ>2, T={Tϵ}ϵ>0 and Tb={Tϵb}ϵ>0 be given by (1.4) and (1.5), respectively. If O(T) and Vρ(T) are bounded on Lp0(R,dx) for some 1<p0<, then, for any 1<p<1/β with 1/q=1/pβ, ωAp,q(R), O(Tb) and Vρ(Tb) are bounded from Lp(R,ωpdx) into Lq(R,ωqdx).

Corollary 1.1

Suppose that K(x,y) satisfies (1.1)-(1.3), b˙β, 0<βδ<1, where δ is the same as in (1.2). Let ρ>2, T={Tϵ}ϵ>0 and Tb={Tb,ϵ}ϵ>0 be given by (1.4) and (1.6), respectively. If O(T) and Vρ(T) are bounded on Lp0(R,dx) for some 1<p0<, then, for any 1<p<1/β with 1/q=1/pβ, ωAp,q(R), O(Tb) and Vρ(Tb) are bounded from Lp(R,ωpdx) into Lq(R,ωqdx).

In this paper, we shall use the symbol AB to indicate that there exists a universal positive constant C, independent of all important parameters, such that ACB. AB means that AB and BA.

Some preliminaries

Weight

A weight ω is a nonnegative, locally integrable function on R. The classical weight theories were introduced by Muckenhoupt and Wheeden in [14] and [15].

A weight ω is said to belong to the Muckenhoup class Ap(R) for 1<p<, if there exists a constant C such that

(1|I|Iω(x)dx)(1|I|Iω(x)1p1dx)p1C

for every interval I. The class A1(R) is defined by replacing the above inequality with

1|I|Iω(x)dxessinfxIw(x)for every ball IR.

When p=, we define A(R)=1p<Ap(R).

A weight ω(x) is said to belong to the class Ap,q(R), 1<pq<, if

(1|I|Iω(x)qdx)1/q(1|I|Iω(x)pdx)1/pC.

It is well known that if ωAp.q(R), then ωqA(R).

Function of Lipβ(R)

The function of Lipβ(R) has the following important properties.

Lemma 2.1

Let bLipβ(R). Then

  1. 1p<
    supI1|I|β(1|I|I|b(x)bI|pdx)1/pCb˙β;
  2. for any I1I2,
    1|I2|I2|b(y)bI1|dy|I2||I1||I2|βb˙β.

Maximal function

We recall the definition of Hardy-Littlewood maximal operator and fractional maximal operator. The Hardy-Littlewood maximal operator is defined by

M(f)(x)=supIx1|I|I|f(y)|dy.

The fractional maximal function is defined as

Mβ,r(f)(x)=supIx(1|I|1rβI|f(y)|rdy)1/r

for 1r<. In order to simplify the notation, we set Mβ(f)(x)=Mβ,1(f)(x).

Lemma 2.2

Let 1<p< and ωA(R). Then

MfLp(ω)MfLp(ω)

for all f such that the left hand side is finite.

Lemma 2.3

Suppose 0<β<1, 1r<p<1/β, 1/q=1/pβ. If ωAp,q(R), then

Mβ,rfLq(ωq)fLp(ωp).

Taylor series remainder

The following lemma gives an estimate on Taylor series remainder.

Lemma 2.4

[10] Let b be a function on R and b(m)Ls(R) for any s>1. Then

|Rm(b;x,y)||xy|m(1|Ixy|Ixy|b(m)(z)|sdz)1/s,

where Ixy is the interval (x5|xy|,x+5|xy|).

Oscillation and variation operators

We consider the operator

O(Tf)(x)=(i=1supti+1<δi<ti|Tti+1f(x)Tδif(x)|2)1/2.

It is easy to check that

O(Tf)O(Tf).

Following [4], we denote by E the mixed norm Banach space of two variable function h defined on R×N such that

hE(i(sups|h(s,i)|)2)1/2<.

Given T={Tϵ}ϵ>0, where Tϵ defined as (1.4), for a fixed decreasing sequence {ti} with ti0, let Ji=(ti+1,ti] and define the E-valued operator U(T):fU(T)f by

U(T)f(x)={Tti+1f(x)Tsf(x)}sJi,iN={{ti+1<|xy|<s}K(x,y)f(y)dy}sJi,iN.

Then

O(Tf)(x)=U(T)f(x)E={Tti+1f(x)Tsf(x)}sJi,iNE={{ti+1<|xy|<s}K(x,y)f(y)dy}sJi,iNE.

On the other hand, let Θ={β:β={ϵi},ϵiR,ϵi0}. We denote by Fρ the mixed norm space of two variable functions g(i,β) such that

gFρsupβ(i|g(i,β)|ρ)1/ρ.

We also consider the Fρ-valued operator V(T):fV(T)f given by

V(T)f(x)={Tti+1f(x)Ttif(x)}β={ϵi}Θ.

Then

Vρ(T)f(x)=V(T)f(x)Fρ.

Next, let B be a Banach space and φ be a B-valued function, we define the sharp maximal operator as follows:

φ(x)=supxI1|I|Iφ(y)1|I|Iφ(z)dzBdysupxIinfc1|I|Iφ(y)cBdy.

Then

M(O(Tf))2(U(T)f)(x)

and

M(Vρ(Tf))2(V(T)f)(x).

Finally, let us recall some results about oscillation and variation operators.

Lemma 2.5

([5])

Suppose that K(x,y) satisfies (1.1)-(1.3), ρ>2. Let T={Tϵ}ϵ>0 be given by (1.4). If O(T) and Vρ(T) are bounded on Lp0(R) for some 1<p0<, then, for any 1<p<, ωAp(R),

O(Tf)Lp(ω)O(Tf)Lp(ω)fLp(ω)

and

Vρ(Tf)Lp(ω)fLp(ω).

The proof of main results

Note that if ωAp,q(R), then ωqA(R). By Lemma 2.2 and Lemma 2.3, we only need to prove

M(O(Tb)f)(x)b(m)˙β(Mβ,r(f)(x)+Mβ(f)(x)) 3.1

and

M(Vρ(Tb)f)(x)b(m)˙β(Mβ,r(f)(x)+Mβ(f)(x)) 3.2

hold for any 1<r<.

We will prove only inequality (3.1), since (3.2) can be obtained by a similar argument. Fix f and x0 with an interval I=(x0l,x0+l). Write f=f1+f2=fχ5I+fχR5I, and let

CI={{ti+1<|x0y|<s}Rm+1(b;x0,y)|x0y|mK(x0,y)f2(y)dy}sJi,iN=U(Tb)f2(x0).

Then

U(Tb)f(x)={{ti+1<|xy|<s}Rm+1(b;x,y)|xy|mK(x,y)f(y)dy}sJi,iN=U(T)(Rm+1(b;x,)|x|mf1)+U(Tb)f2(x).

Therefore

1|I|IU(Tb)f(x)CIEdx1|I|IU(T)(Rm+1(b;x,)|x|mf1)Edx+1|I|IU(Tb)f2(x)U(Tb)f2(x0)Edx=M1+M2.

For xI, k=0,1,2, , let Ek={y:2k16l|yx|<2k6l}, let Ik={y:|yx|<2k6l}, and let bk(z)=b(z)1m!(b(m))Ikzm. By [10] we have Rm+1(b;x,y)=Rm+1(bk;x,y) for any yEk.

By Lemma 2.5, we know O(T) is bounded on Lu(R) for u>1. Then, using Hölder’s inequality, we deduce

M1(1|I|IU(T)(Rm+1(b;x,)|x|mf1)Eudx)1/u(1|I|{y:|yx|<6l}|Rm+1(b;,y)|y|mf(y)|udy)1/u=(1|I|k=0Ek|(Rm+1(bk;,y)|y|mf(y))|rdy)1/r(1|I|k=0Ek|((Rm(bk;,y)|y|m1m!(y)mbk(m)(y)|y|m)f(y))|udy)1/u(1|I|k=0Ek|Rm(bk;,y)|y|mf(y)|udy)1/u+(1|I|k=0Ek|1m!(y)mbk(m)(y)|y|mf(y)|udy)1/u=M11+M12.

By Lemma 2.4 and Lemma 2.1,

|Rm(bk;x,y)||xy|m(1|Ixy|Ixy|bk(m)(z)|sdz)1/s|xy|m(12k30l|yx|<2k30l|b(m)(y)(b(m))Ik|sdz)1/s|xy|m(2kl)βb(m)˙β.

Then

M11b(m)˙βlβ(1|I|k=02kβuEk|f(y)|udy)1/ub(m)˙βlβ(1|I|k=0Ek|f(y)|udy)1/ub(m)˙βlβ(1|I|7I|f(y)|udy)1/ub(m)˙βlβ(1|I|7I|f(y)|rdy)1/rb(m)˙βMβ,r(f)(x0).

Since bk(m)(y)=b(m)(y)(b(m))Ik, then, applying Hölder’s inequality and Lemma 2.1, we get

M12(1|I|k=0Ek|(b(m)(y)(b(m))Ik)f(y)|udy)1/u(1|I|k=0(Ik|f(y)|rdy)u/r(Ik|b(m)(y)(b(m))Ik|urru)1u/r)1/ub(m)˙β(1|I|k=0(Ik|f(y)|rdy)u/r|Ik|βu+1u/r)1/ub(m)˙βMβ,r(f)(x0)(1|I|k=0|Ik|)1/ub(m)˙βMβ,r(f)(x0).

We now estimate M2. For xI, we have

U(Tb)f2(x)U(Tb)f2(x0)E={{ti+1<|xy|<s}Rm+1(b;x,y)|xy|mK(x,y)f2(y)dy{ti+1<|x0y|<s}Rm+1(b;x0,y)|x0y|mK(x0,y)f2(y)dy}sJi,iNE{{ti+1<|xy|<s}(Rm+1(b;x,y)|xy|mK(x,y)Rm+1(b;x0,y)|x0y|mK(x0,y))f2(y)dy}sJi,iNE+{R(χ{ti+1<|xy|<s}(y)χ{ti+1<|x0y|<s}(y))Rm+1(b;x0,y)|x0y|mK(x0,y)f2(y)dy}sJi,iNE=N1+N2.

For k=0,1,2, , let Fk={y:2k4l|yx0|<2k+14l}, let I˜k={y:|yx0|<2k4l}, and let b˜k(z)=b(z)1m!(b(m))I˜kzm. Note that

Rm+1(b;x,y)|xy|mK(x,y)Rm+1(b;x0,y)|x0y|mK(x0,y)=Rm+1(b˜k;x,y)|xy|mK(x,y)Rm+1(b˜k;x0,y)|x0y|mK(x0,y)=1|xy|m(Rm(b˜k;x,y)Rm(b˜k;x0,y))K(x,y)+Rm(b˜k;x0,y)(1|xy|m1|x0y|m)K(x,y)1m!b˜k(m)(y)((xy)m|xy|m(x0y)m|x0y|m)K(x,y)+Rm+1(b˜k;x0,y)|x0y|m(K(x,y)K(x0,y)).

By Minkowski’s inequalities and {χ{ti+1<|xy|<s}}sJi,iNE1, we obtain

N1R{χ{ti+1<|xy|<s}}sJi,iNE×|Rm+1(b˜k;x,y)|xy|mK(x,y)Rm+1(b˜k;x0,y)|x0y|mK(x0,y)||f2(y)|dyk=0Fk1|xy|m|Rm(b˜k;x,y)Rm(b˜k;x0,y)||K(x,y)||f2(y)|dy+k=0Fk|Rm(b˜k;x0,y)||1|xy|m1|x0y|m||K(x,y)||f2(y)|dy+k=0Fk1m!|b˜k(m)(y)||(xy)m|xy|m(x0y)m|x0y|m||K(x,y)||f2(y)|dy+k=0Fk|Rm+1(b˜k;x0,y)|x0y|m||K(x,y)K(x0,y)||f2(y)|dy=N11+N12+N13+N14.

From the mean value theorem, there exists ηI such that

Rm(b˜k;x,y)Rm(b˜k;x0,y)=(xx0)Rm1(b˜k;η,y).

For η,xI, yFk, we have |yx0||yx||yη| and 5|yη|5|yx0|2k+120l. By Lemma 2.4 and Lemma 2.1 we get

|Rm1(b˜k;η,y)||ηy|m1(1|Iηy|Iηy|b˜k(m)(z)|sdz)1/s|xy|m1(12k+120l|zx0|<2k+120l|b(m)(z)(b(m))I˜k|sdz)1/sb(m)˙β(2kl)β|xy|m1.

Then

|Rm(b˜k;x,y)Rm(b˜k;x0,y)|b(m)˙β(2kl)β|xx0||xy|m1.

Since |K(x,y)|C|x0y|1,

N11b(m)˙βk=0(2kl)β2k4l|x0y|<2k+14ll(2k4l)2|f(y)|dyb(m)˙βk=012k(2kl)β2kl|x0y|<2k+14l|f(y)|dyb(m)˙βMβ(f)(x0).

For N12, since xI, yFk,

|Rm(b˜k;x,y)||xy|m(1|Ixy|Ixy|b˜k(m)(z)|sdz)1/sb(m)˙β(2kl)β|xy|m

and

|1|xy|m1|x0y|m||xx0||xy|m+1.

Thus

N12b(m)˙βk=0(2kl)β2k4l|x0y|<2k+14ll(2k4l)2|f(y)|dyb(m)˙βMβ(f)(x0).

As for N13, due to

|(xy)m|xy|m(x0y)m|x0y|m||xx0||xy|,

and noting b˜k(m)(y)=b(m)(y)(b(m))I˜k, we have

N13k=0Fk|b(m)(y)(b(m))I˜k||xx0||x0y|2|f(y)|dyk=012k12k4l|x0y|<2k4l|b(m)(y)(b(m))I˜k||f(y)|dyk=012k(12k4l|x0y|<2k4l|f(y)|rdy)1/r×(12k4l|x0y|<2k4l|b(m)(y)(b(m))I˜k|rdy)1/rb(m)˙βMr,β(f)(x0)k=012kb(m)˙βMβ,r(f)(x0).

Notice

|Rm+1(b˜k;x0,y)||Rm(b˜k;x0,y)|+1m!|b˜k(m)(y)(x0y)m|b(m)˙β(2kl)β|x0y|m+|b(m)(y)(b(m))I˜k||x0y|m

and by (1.2),

|K(x,y)K(x0,y)||xx0|δ|x0y|1+δ.

Similar to the estimates for N11, we have

k=0Fk|Rm(b˜k;x0,y)||xy|m|xx0|δ|x0y|1+δ|f(y)|dyb(m)˙βMβ(f)(x0).

Similar to the estimates for N13, we have

k=0Fk|b˜k(m)(y)(x0y)m||xy|m|xx0|δ|x0y|1+δ|f(y)|dyb(m)˙βMβ,r(f)(x0).

Then

N14b(m)˙β(Mβ(f)(x0)+Mβ,r(f)(x0)).

Finally, let us estimate N2. Notice that the integral

R(χ{ti+1<|xy|<s}(y)χ{ti+1<|x0y|<s}(y))Rm+1(b;x0,y)|x0y|mK(x0,y)f2(y)dy

will be non-zero in the following cases:

  • (i)

    ti+1<|xy|<s and |x0y|ti+1;

  • (ii)

    ti+1<|xy|<s and |x0y|s;

  • (iii)

    ti+1<|x0y|<s and |xy|ti+1;

  • (iv)

    ti+1<|x0y|<s and |xy|s.

In case (i) we have ti+1<|xy||x0x|+|x0y|<l+ti+1 as |xx0|<l. Similarly, in case (iii) we have ti+1<|x0y|<l+ti+1 as |xx0|<l. In case (ii) we have s<|x0y|<l+s and in case (iv) we have s<|xy|<l+s. By (1.1) and taking 1<t<r, we have

R(χ{ti+1<|xy|<s}(y)χ{ti+1<|x0y|<s}(y))Rm+1(b;x0,y)|x0y|mK(x0,y)f2(y)dyRχ{ti+1<|xy|<s}(y)χ{ti+1<|xy|<l+ti+1}(y)|Rm+1(b;x0,y)|x0y|m||f2(y)||x0y|dy+Rχ{ti+1<|xy|<s}(y)χ{s<|x0y|<l+s}(y)|Rm+1(b;x0,y)|x0y|m||f2(y)||x0y|dy+Rχ{ti+1<|x0y|<s}(y)χ{ti+1<|x0y|<l+ti+1}(y)|Rm+1(b;x0,y)|x0y|m||f2(y)||x0y|dy+Rχ{ti+1<|x0y|<s}(y)χ{s<|xy|<l+s}(y)|Rm+1(b;x0,y)|x0y|m||f2(y)||x0y|dyl1/t(Rχ{ti+1<|xy|<s}(y)|Rm+1(b;x0,y)|x0y|m|t|f2(y)|t|x0y|tdy)1/t+l1/t(Rχ{ti+1<|x0y|<s}(y)|Rm+1(b;x0,y)|x0y|m|t|f2(y)|t|x0y|tdy)1/t.

Then

N2l1/t{(Rχ{ti+1<|xy|<s}(y)|Rm+1(b;x0,y)|x0y|m|t|f2(y)|t|x0y|tdy)1/t}sJi,iNE+l1/t{(Rχ{ti+1<|x0y|<s}(y)|Rm+1(b;x0,y)|x0y|m|t|f2(y)|t|x0y|tdy)1/t}sJi,iNE=N21+N22.

Notice

|Rm+1(b˜k;x0,y)|b(m)˙β(2kl)β|x0y|m+|b(m)(y)(b(m))I˜k||x0y|m.

Choosing 1<r<p with t=r, we have

N21l1/t{iNsupsJi(Rχ{ti+1<|xy|<s}(y)|Rm+1(b;x0,y)|x0y|m|t|f2(y)|t|x0y|tdy)2/t}1/2l1/t{iNRχ{ti+1<|xy|<ti}(y)|Rm+1(b;x0,y)|x0y|m|t|f2(y)|t|x0y|tdy}1/tl1/t{R|Rm+1(b;x0,y)|x0y|m|t|f2(y)|t|x0y|tdy}1/tl1/t{k=0Fk|Rm+1(b˜k;x0,y)|x0y|m|t|f2(y)|t|x0y|tdy}1/tb(m)˙βl1/t{k=0(2kl)βtFk|f(y)|t|x0y|tdy}1/t+l1/t{k=0Fk(|b(m)(y)(b(m))I˜k|)t|f(y)|t|x0y|tdy}1/t.

But

l1/t{k=0(2kl)βtFk|f(y)|t|x0y|tdy}1/tl1/t(k=1(2kl)βt(2k4l)t|x0y|<2k+14l|f(y)|tdy)1/t(k=112k(t1)(2kl)βt2k5l|x0y|<2k5l|f(y)|tdy)1/t(k=112k(t1)((2kl)βt22k5l|x0y|<2k5l|f(y)|t2dy)1/t)1/t(k=112k(t1))1/tMβ,r(f)(x0)Mβ,r(f)(x0)

and

l1/t{k=0Fk(|b(m)(y)(b(m))I˜k|)t|f(y)|t|x0y|tdy}1/t(k=012k(t1)12k4l|x0y|<2k4l|b(m)(y)(b(m))I˜k|t|f(y)|tdy)1/t(k=012k(t1)(12k4l|x0y|<2k4l|f(y)|t2dy)1/t×(12k4l|x0y|<2k4l|b(m)(y)(b(m))I˜k|tt)1/t)1/tb(m)˙β(k=012k(t1)((2k4l)rβ2k4l|x0y|<2k4l|f(y)|t2dy)1/t)1/tb(m)˙βMβ,r(f)(x0)(k=012k(t1))1/tb(m)˙βMβ,r(f)(x0).

Therefore

N21b(m)˙βMβ,r(f)(x0).

Similarly,

N22b(m)˙βMβ,r(f)(x0).

This completes the proof of (3.1). Hence, Theorem 1.1 is proved.

Authors’ contributions

The authors completed the paper together. They also read and approved the final manuscript.

Competing interests

The authors declare that they have no competing interests.

Footnotes

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Contributor Information

Yue Hu, Email: huu3y3@163.com.

Yueshan Wang, Email: wangys1962@163.com.

References

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