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. 2017 Dec 16;2017(1):307. doi: 10.1186/s13660-017-1580-z

Some classes of singular integral equations of convolution type in the class of exponentially increasing functions

Pingrun Li 1,
PMCID: PMC5732317  PMID: 29263638

Abstract

In this article, we study some classes of singular integral equations of convolution type with Cauchy kernels in the class of exponentially increasing functions. Such equations are transformed into Riemann boundary value problems on either a straight line or two parallel straight lines by Fourier transformation. We propose one method different from the classical one for the study of such problems and obtain the general solutions and the conditions of solvability. Thus, the result in this paper improves the theory of integral equations and the classical boundary value problems for analytic functions.

Keywords: singular integral equations, Riemann boundary value problems, dual type, convolution kernel, the class of exponentially increasing functions

Introduction

It is well known that singular integral equations (SIEs) and integral equations of convolution type are two basic kinds of equations in the theory of integral equations. There have been many papers studying singular integral equations and a relatively complete theoretical system is almost formed (see, e.g., [16]). These equations play important roles in other subjects and practical applications, such as engineering mechanics, physics, fracture mechanics, and elastic mechanics. For operators containing both the Cauchy principal value integral and convolution, Karapetiants-Samko [7] studied the conditions of their Noethericity in the more general case. In recent decades, many mathematicians studied some SIEs of convolution type. Litvinchuk [8] studied a class of Wiener-Hopf type integral equations with convolution and Cauchy kernel and proved the solvability of the equation. Giang-Tuan [9] studied the Noether theory of convolution type SIEs with constant coefficients. Nakazi-Yamamoto [10] proposed a class of convolution SIEs with discontinuous coefficients and transformed the equations into a Riemann boundary value problem (RBVP) by Fourier transform, and given the general solutions of the equation. Later on, Li [11] discussed the SIEs with convolution kernels and periodicity, which can be transformed into a discrete jump problems by discrete Fourier transformation, and the solvable conditions and the explicit expressions of general solutions were obtained.

The purpose of this article is to extend the theory to some classes of singular integral equations of convolution type with Cauchy kernels in the class of exponentially increasing functions. Such equations can be transformed to RBVPs with either an unknown function on a straight line or two unknown functions on two parallel straight lines by Fourier transformation. We prove the existence of the solution for the equations; moreover, the general solutions and the conditions of solvability are obtained under some conditions. Therefore, the result in this paper further generalizes the results of [711].

The Fourier transforms used in this paper are understood to be performed in L2(R) and the functions involved certainly belong to this space.

Definitions and lemmas

Definition 2.1

A function F(x) belongs to class {{0}}, if the following two conditions are fulfilled:

(1) F(x)Hˆ, that is, it satisfies the Hölder condition on the whole real domain R, including ∞, i.e. ±∞;

(2) F(x)L2(R), that is, L2(R)={F(x)+|F(x)|2dx<+}.

Definition 2.2

A function f(t) belongs to class {0}, if its Fourier transform,

F(x)=V[f(t)]=12π+f(t)eixtdt,xR,

belongs to the class {{0}}.

Definition 2.3

The inverse transform V1 of F(x) is defined by

V1[F(x)]=12π+F(x)eixtdx,tR

and we denote it as V1[F(x)]=f(t).

Definition 2.4

If there exists a real constant τ such that f(t)eτt{0}, we say that f(t) belongs to the class of exponentially increasing functions, and we denote it as f(t){τ}, where τ is called the order of the exponential increase.

Denote

f+(t)={f(t),t0,0,t<0;f(t)={f(t),t<0,0,t0,

obviously, f(t)=f+(t)f(t).

If f+(t){τ}, f(t){σ}, then we call f(t){τ,σ}, where τ and σ are real constants.

Definition 2.5

For two functions f(x) and g(x), their convolution is

12π+f(xs)g(s)ds, 2.1

we denote it as fg(x), where the integral (2.1) exists.

We also introduce the operator T of the Cauchy principal value integral as

Tf(x)=1πi+f(t)txdt,xR.

We have the following lemmas.

Lemma 2.1

([4])

If f(t){0}, F(0)=0, then V(Tf(t))=F(x)sgnx, and Tf(t){0}.

Lemma 2.2

If fj(t){pj,qj} (j=1,2,,n), then

j=1nfj(t){max1jn(pj),min1jn(qj)}.

Proof

Without loss of generality, we assume that p1pj (2jn). Since

fj+(t){pj}(1jn),ep1tfj+(t)=e(p1pj)tepjtfj+(t),

and epjtfj+(t){0}, we obtain j=1nfj+(t){p1}, that is,

j=1nfj+(t){max1jn(pj)}.

Similarly,

j=1nfj(t){min1jn(qj)}.

Lemmas 2.3-2.4 are obvious facts and we omit their proofs here. □

Lemma 2.3

Let f(t){p}, f(t){q}, then f(t){min(p,q),max(p,q)}.

Lemma 2.4

Let h(t){σ,τ}, f(t){p,q}. If pτ, qσ, then hf(t) exists, and

hf(t){max(p,σ),min(τ,q)}.

We introduce the following two lemmas (see [4]).

Lemma 2.5

If f(t), g(t){0}, then fg(t){0}, and V[fg(t)]=F(x)G(x), where F(x)=Vf(t), G(x)=Vg(t).

Lemma 2.6

Let F(x)=Vf(t), if f(t){p,q}, F(ip)=F(iq)=0, then Tf(t){p,q}.

Presentation of the problem

In this section we consider the following several classes of SIEs in the class of exponentially increasing functions, and we shall transform these equations into the generalized RBVPs.

(1) SIEs of dual type:

{a1f(t)+b1Tf(t)+h1f(t)=g(t),tR+;a2f(t)+b2Tf(t)+h2f(t)=g(t),tR.

(2) Wiener-Hopf type: af+(t)+bTf+(t)+hf+(t)=g(t), tR+.

(3) One convolution kernel: af(t)+bTf(t)+hf(t)=g(t), tR.

(4) Two convolution kernels: af(t)+bTf(t)+h1f+(t)+h2f(t)=g(t), tR, where a, b (b0), aj, bj are constants and bj are not equal to zero simultaneously. In the literature [2, 7], equations (1)-(4) were discussed in class {0} and the general solutions and the conditions of solvability were obtained. In this paper we extend the results of [2, 7] to the class of exponentially increasing functions. Without loss of generality, we mainly study the SIEs of dual type. The method mentioned in this paper may also be applied to solving the other classes of equations.

Consider the following SIEs of dual type:

{a1f(t)+b1Tf(t)+h1f(t)=g(t),tR+;a2f(t)+b2Tf(t)+h2f(t)=g(t),tR, 3.1

where aj, bj are as the above, and hj(t){σj,τj} (j=1,2). The known function g(t) belongs to the following certain function class, and the unknown function f(t){p,q}. Let φ{0} be an undetermined function and define

φ(t)=12(sgnt1)φ(t),φ+(t)=12(sgnt+1)φ(t),

obviously,

φ±(t){0},φ(t)|R+=0,φ+(t)|R=0.

Extending t in (3.1) to tR, we rewrite (3.1) as

{a1f(t)+b1Tf(t)+h1f(t)=g+(t)φ(t);a2f(t)+b2Tf(t)+h2f(t)=g(t)+φ+(t),tR. 3.2

In order to guarantee that hjf(t) (j=1,2) exist, we apply Lemmas 2.2-2.4 and obtain

p=min{τ1,τ2},q=max{σ1,σ2},

hence

g{max{p,σ1},min{q,τ2}},φ{max{p,σ2},min{q,τ1}}.

Since the relationship of the size among σ1, σ2, τ1 and τ2 has 24 kinds of permutations, each permutation shall determine a different class of exponentially increasing function, and then cause different boundary value problems (BVPs). As a whole, after taking the Fourier transform for (3.2), we can obtain the following four cases.

Case 1: Equation (3.2) (or (3.1)) is transformed into the RBVP on one straight line.

Case 2: Equation (3.2) is transformed into the RBVP with two unknown functions on two parallel straight lines.

Case 3: Equation (3.2) is transformed into one-sided BVP.

Case 4: In class {p,q}, (3.2) is not solvable.

But in Case 3 it is possible that a solution of (3.1) exists under some additional conditions. By using the method of analytic continuation, this case can be transformed into Case 2, therefore, in this paper we only discuss Case 1 and Case 2.

For Case 1, without loss of generality, we only study equation (3.2) under the following condition:

(a)τ2>σ2=τ1>σ1.

It follows from condition (a) that f, φ±, g, and Tf belong to {τ1}. In (3.2), each term is multiplied by etτ1, then all terms in the obtained equations belong to {0}. Taking the Fourier transform on the above obtained equations, respectively, we obtain

{1C1(ξ)F(ξ)=G+(ξ)+Φ(ξ);C2(ξ)F(ξ)=G(ξ)+Φ+(ξ), 3.3

where

Φ±(ξ)=V[φ±(t)],G±(ξ)=V[g±(t)],F(ξ)=V[f(t)],Hj(ξ)=V[hj(t)],C1(ξ)=1a1b1δ(ξ)+H1(ξ),C2(ξ)=a2b2δ(ξ)+H2(ξ),δ(ξ)={1,Reξ>0;1,Reξ<0,

and δ(ξ) is obtained by taking the Fourier transform to Tf(t) and applying Lemma 2.1.

By eliminating F(ξ) in (3.3), we obtain the following RBVP on Imξ=τ1:

Φ+(ξ)=C(ξ)Φ(ξ)+D(ξ),ξ=x+iτ1,xR, 3.4

in which we have put

C(ξ)=C1(ξ)C2(ξ),D(ξ)=C(ξ)G+(ξ)G(ξ).

For Case 2, we only solve equation (3.2) under the following condition:

(b)τ2τ1>σ2σ1.

In this case, in order to solve (3.1), we may rewrite it as

a1f+(t)+b1Tf+(t)+h1f+(t)g+(t)=a1f(t)+b1Tf(t)+h1f(t)φ(t), 3.5
a2f+(t)+b2Tf+(t)+h2f+(t)φ+(t)=a2f(t)+b2Tf(t)+h2f(t)g(t). 3.6

From condition (b) we know that f{τ1,σ2}, g{τ1,σ2}, φ+{τ1}, and φ{σ2}. Hence, in (3.5) and (3.6), each term of the left-hand sides belongs to {τ1},while each term of the right-hand sides belongs to {σ2}. Let

a1f+(t)+b1Tf+(t)+h1f+(t)g+(t)=a1f(t)+b1Tf(t)+h1f(t)φ(t)=e1(t), 3.7
a2f+(t)+b2Tf+(t)+h2f+(t)φ+(t)=a2f(t)+b2Tf(t)+h2f(t)g(t)=e2(t). 3.8

By Lemmas 2.2-2.4, we find that ej(t) (j=1,2) belong to {τ1,σ2}. Hence, we multiply each term of (3.7) and (3.8) by etτ1, etσ2, respectively. Then by taking the Fourier transform on the above obtained equations, we get

{1C1(ξ)F+(ξ)=G+(ξ)+E1(ξ);C2(ξ)F+(ξ)=Φ+(ξ)+E2(ξ),ξ=x+iτ1,xR, 3.9

and

{1C1(ξ)F(ξ)=Φ(ξ)+E1(ξ);C2(ξ)F(ξ)=G(ξ)+E2(ξ),ξ=x+iσ2,xR, 3.10

where

F±(ξ)=V[f±(t)],Ej(ξ)=V[ej(t)],j=1,2.

In this paper we only consider the case of normal type, that is,

Hj(ξ){(ajbj),Reξ>0;(aj+bj),Reξ<0,ξ=x+iτ1,ξ=x+iσ2, 3.11

in view of this, we have C2(ξ)0 on ξ=x+iσ2. For the exceptional cases, that is, C2(ξ)=0 on ξ=x+iσ2, a method of solution is similar to the one used in [8].

By eliminating F+(ξ), F(ξ) in (3.9), (3.10), respectively, we obtain the following RBVP with the unknown functions Φ(ξ) and Ψ(ξ) on two parallel straight lines:

{Φ+(ξ)=C1(ξ)Ψ(ξ)+G1(ξ),ξ=x+iτ1;Ψ(ξ)=C2(ξ)Φ(ξ)+G2(ξ),ξ=x+iσ2,xR, 3.12

where

G1(ξ)=C(ξ)G+(ξ),G2(ξ)=C1(ξ)G(ξ),Ψ(ξ)=C2(ξ)E1(ξ)C1(ξ)E2(ξ),C1(ξ)=1C1(ξ).

Note that BVP (3.12) is a generalization of the classical RBVPs with one unknown function.

Methods of solutions of (3.4) and (3.12)

On the solutions of (3.4)

Since b1, b2 are not equal to zero simultaneously, thus (3.4) is the RBVP with discontinuous coefficients and nodal point iτ1 on Imξ=τ1, and it can be described as follows: we want to get a function Φ(z) such that it is analytic in Imξ>τ1, Imξ<τ1, respectively, and satisfies the boundary value condition (3.4).

According to the method used in [12], take a continuous branch of InC(ξ) such that it is continuous at ξ=, e.g., InC()=0, and denote

γ0=α0+iβ0=12πi{InC(iτ1+0)InC(iτ10)}.

Then choose an integer κ, the index of the problem, such that 0α=α0κ<1. Denote γ=γ0κ=α+iβ0. Without loss of generality, take two points z1, z2 such that Imz1>Imξ, Imz2<Imξ, and assume that z1, z2 are a pair of symmetry points on Imξ=τ1, then we have |z1iτ1|=|z2iτ1|, arg(z1iτ1)=arg(z2iτ1).

Define the following piecewise function:

X(z)={eΓ(z),Imz>τ1;(zz2zz1)κeΓ(z),Imz<τ1, 4.1

where

Γ(z)=12πi+iτ1++iτ1lnC0(t)tzdt,C0(z)=(tz2tz1)κC(z), 4.2

in which we have taken the definite branch of

InC0(t)=κIntz2tz1+InC(t),

provided that we have chosen Intz2tz1|t==0, or, which is the same, Intz2tz1|t=±0=±iπ. Since Φ(ξ){{0}} and Φ()=0, we get:

when κ0, the general solution of (3.4) is

Φ(z)=X(z)χ(z)+X(z)Qκ(z)(zz1)κ, 4.3

where

χ(z)=12πi+iτ1++iτ1D(t)X+(t)(tz)dt 4.4

and Qκ(z)=q0+q1z++qκzκ is an arbitrary polynomial of degree κ (κ0).

When κ<0, the solution of (3.4) is still (4.3). In this case, (3.4) is solvable if and only if the conditions

+iτ1++iτ1D(t)X+(t)(tz1)jdt=0,j=1,2,,κ, 4.5

are satisfied, and (3.4) has the unique solution (4.3) (in the sequel we understand Qκ(z)0 when κ<0). By applying the Plemelj equation (see [10]) to (4.3), we get

{Φ+(t)=12D(t)+X+(t)χ(t)+X+(t)Qκ(t)(tz1)κ;Φ(t)=C(t)2D(t)+X(t)χ(t)+X(t)Qκ(t)(tz1)κ, 4.6

and thereby

Φ(t)=12D(t)[1+1C(t)]+[X+(t)X(t)][χ(t)+Qκ(t)(tz1)κ]. 4.7

Since the X±(t) are bounded and X±(t)0, it is easy to prove that Φ±(t), Φ(t){{0}}. Putting (4.6) into (3.3), we can obtain F(x), thus a solution f(t) of (3.4) is given by f(t)=V1[F(x)].

Above all, we have the following.

Theorem 4.1

Under condition (a), if hj(t){σj,τj} (j=1,2), in the normal type case, that is, for (3.11) to be valid, then (3.1) is solvable and has the unique solution f(t)=V1[F(x)] in {p,q}, where F(x) is given by (3.3).

The solutions and the solvability conditions of (3.12)

In this subsection, we shall solve (3.12). It follows from Section 3 that (3.12) is the RBVP with nodes iτ1, iσ2 on two parallel straight lines, where Φ+(ξ) is the boundary value of the analytic function Φ(z), which is analytic in Imz>τ1 and belongs to {{0}} on ξ=x+iτ1. Φ(ξ) is the boundary value of the analytic function Φ(z), which is analytic in Imz<σ2 and belongs to {{0}} on ξ=x+iσ2; Ψ±(ξ) are the boundary values of the analytic function Ψ(z), which is analytic in σ2<Imz<τ1 and belongs to {{0}} on ξ=x+iτ1, ξ=x+iσ2, respectively. The functions C1(ξ), G1(ξ) and C2(ξ), G2(ξ) belong to {{0}} on ξ=x+iτ1, ξ=x+iσ2, respectively. Hence, for the functions appearing in (3.2), their one-sided limits exist when x on ξ=x+iτ1, ξ=x+iσ2. In order to unify the notations, denote l1=τ1, l2=σ2. Set

γ0(j)=α0(j)+iβ0(j)=12πi{InCj(ilj+0)InCj(ilj0)},j=1,2,

then choose integers κj (j=1,2), such that 0α0(j)κj<1. Denote

γj=γ0(j)κj=α(j)+iβ0(j),

we call κ=κ1+κ2 the index of (3.1). Set

γ(j)=α(j)+iβ(j)=12πi{InCj(ilj+)InCj(ilj)},α=α(1)+α(2),j=1,2.

Note that InCj(ξ) is taken to be continuous in Reξ>0 and Reξ<0, respectively, such that 0α<1. Without loss of generality, we take the three points z0, z1, z2 such that l2<Imz0<l1, Imz1>l1, Imz2<l2, and |z0il2|=|z2il2|, |z0il1|=|z1il1|.

In order to solve (3.12), we define the following piecewise functions:

X1(z)={eΓ1(z),Imz>l1,(zz1zz0)κ1eΓ1(z),Imz<l1;X2(z)={(zz2zz0)κ2eΓ2(z),Imz>l2,eΓ2(z),Imz<l2, 4.8

where

Γj(z)=12πi+ilj++ilj(lnMj(t)tzlnMj(t)tz0)dt,Mj(t)=(tzjtz0)κjCj(t),Imzlj,j=1,2,

here lnMj(t) (j=1,2) have certain analytic branches such that lntz0tzj|t==0 (j=1,2). Setting X(z)=X1(z)X2(z), we call X(z) the canonical function of (3.12). Taking the boundary values for Xj(z) in (4.8), we obtain by applying Plemelj’s formula

Xj+(t)=Cj(t)Xj(t),j=1,2. 4.9

Putting (4.9) into (3.12), one has

{Φ+(ξ)=X1+(ξ)X1(ξ)Ψ(ξ)+G1(ξ),ξL1:ξ=x+il1;Ψ(ξ)=X2+(ξ)X2(ξ)Φ(ξ)+G2(ξ),ξL2:ξ=x+il2,xR, 4.10

by multiplying [X+(ξ)]1 to the first equality of (4.10) and [X˜(ξ)]1 to the second one, we have

{Φ+(ξ)X+(ξ)=Ψ(ξ)X˜(ξ)+G1(ξ)X+(ξ),ξL1;Ψ(ξ)X˜(ξ)=Φ(ξ)X(ξ)+G2(ξ)X˜(ξ),ξL2, 4.11

where X˜(ξ)=X1(ξ)X2+(ξ). Since X1(ξ) and X2(ξ) are bounded on L1, L2, respectively, and G1(ξ){{0}}, we have G1(ξ)X+(ξ){{0}}, thus we may define the following piecewise function:

ψ1(z)=12πi+il1++il1(zz0)G1(t)X+(t)(tz)(tz0)dt,Imzl1. 4.12

It follows from Privalov’s theorem (see [12]) that ψ1(z) is analytic in Imz>l1 and Imz<l1, respectively. By applying Plemelj’s formula to ψ1(z) in (4.12), we have

ψ1+(ξ)ψ1(ξ)=G1(ξ)X+(ξ),ξL1.

Then the first equality of (4.11) can be transformed to

Φ+(ξ)X+(ξ)ψ1+(ξ)=Ψ(ξ)X˜(ξ)ψ1(ξ),ξL1.

Again we define

ψ2(z)=12πi+il2++il2(zz0)G2(t)X˜(t)(tz)(tz0)dt,Imzl2. 4.13

Similarly, the second equality of (4.11) can also be transformed to

Ψ(ξ)X˜(ξ)ψ2+(ξ)=Φ(ξ)X(ξ)ψ2(ξ),ξL2.

Thus, we need only to discuss (4.14) instead of (3.12):

{Φ+(ξ)X+(ξ)ψ1+(ξ)=Ψ(ξ)X˜(ξ)ψ1(ξ);Ψ(ξ)X˜(ξ)ψ2+(ξ)=Φ(ξ)X(ξ)ψ2(ξ), 4.14

by subtracting ψ2+(ξ) in the first equality of (4.14) and ψ1(ξ) in the second one, we have

{Φ+(ξ)X+(ξ)ψ1+(ξ)ψ2+(ξ)=Ψ(ξ)X˜(ξ)ψ1(ξ)ψ2+(ξ);Ψ(ξ)X˜(ξ)ψ2+(ξ)ψ1(ξ)=Φ(ξ)X(ξ)ψ2(ξ)ψ1(ξ). 4.14′

In (4.14′), the left-hand side of the first equality is denoted by Φ1+, while the right-hand side is denoted by Φ1; the left-hand side of the second equality is denoted by Φ2+, while the right-hand side is denoted by Φ2. Thus we may denote

Φ1(z)={Φ1+(z),Imz>l1;Φ1(z),Imz<l1,

where

Φ1+(z)=Φ+(z)X+(z)ψ1+(z)ψ2+(z),Imz>l1,Φ1(z)=Ψ(z)X˜(z)ψ1(z)Ψ2+(z),Imz<l1.

Obviously Φ1+(z)=Φ1(z) on Imz=l1. When κ>0, [X˜(z)]1 has a κ-order pole-point at z=z0 in l2<Imz<l1; when κ<0, [X˜(z)]1 has no singularity in l2<Imz<l1, but X˜(z) has a |κ|-order pole-point at z0. Therefore, by extended Liouville theory [13], we obtain

Φ1(z)=Pκ(z)(zz0)κ,

where Pκ(z)=c0+c1z+c2z2++cκzκ, and cj (0jκ) are arbitrary constants. When κ>1, Pκ(z) is a polynomial with degree κ; when κ1, Pκ(z)0. Therefore, one has

{Φ+(z)X+(z)ψ1+(z)ψ2+(z)=Pκ(z)(zz0)κ,Imz>l1,Ψ(z)X˜(z)ψ1(z)Ψ2+(z)=Pκ(z)(zz0)κ,Imz<l1,

that is,

{Φ+(z)=X+(z)[ψ1+(z)+ψ2+(z)+Pκ(z)(zz0)κ],Imz>l1,Ψ(z)=X˜(z)[ψ1(z)+ψ2+(z)+Pκ(z)(zz0)κ],Imz<l1.

Similarly, we have

{Φ(z)=X(z)[ψ1(z)+ψ2(z)+Pκ(z)(zz0)κ],Imz<l2,Ψ(z)=X˜(z)[ψ1(z)+ψ2+(z)+Pκ(z)(zz0)κ],Imz>l2.

From the above discussions, we can obtain the solutions of (4.11):

{Φ+(z)=X+(z)[ψ1+(z)+ψ2+(z)+Pκ(z)(zz0)κ],Imz>l1,Φ(z)=X(z)[ψ1(z)+ψ2(z)+Pκ(z)(zz0)κ],Imz<l2,Ψ(z)=X˜(z)[ψ1(z)+ψ2+(z)+Pκ(z)(zz0)κ],l2<Imz<l1, 4.15

where ψj±(z) (j=1,2), defined by (4.12) and (4.13), respectively, are analytic functions in Imz>lj, Imz<lj.

Putting Φ+(z) and Φ(z) into the second equation of (3.9) and the second one of (3.10), respectively, and denoting

B(ξ)=E2(ξ)C2(ξ),S(ξ)=Φ+(ξ)C2(ξ),W(ξ)=G(ξ)C2(ξ),

then we obtain the following RBVP with two unknown functions F(ξ), B(ξ) on two parallel straight lines:

{F+(ξ)=B(ξ)+S(ξ),ξL1;F(ξ)=B(ξ)+W(ξ),ξL2. 4.16

It is easy to see that the zero-points z1,z2,,zμ of C2(z), with the orders s1,s2,,sμ, respectively, are the pole-points of B(z) in l2<Imz<l1. Similar to the method for solving Φ±(z) and Ψ(z), we obtain the solutions of (4.16) as follows:

F+(z)=12πi+il1++il1S(t)tzdt12πi+il1++il1S(t)tz0dt+Pκ(z),Imz>l1, 4.17
F(z)=12πi+il2++il2W(t)tzdt12πi+il2++il2W(t)tz0dt+Pκ(z),Imz<l2, 4.18

and

B(z)=F+(z)F(z)+Δ(z),l2<Imz<l1,

where

Δ(z)=P˜s(z)j=1μ(zzj)sj,s=j=1μsj,

Pκ(z) is defined above, and P˜s(z) is an arbitrary polynomial of degree s.

Therefore, a solution of (3.1) is

f(t)=12π+il1++il1F+(ξ)eiξtdξ12π+il2++il2F(ξ)eiξtdξ, 4.19

where F+(ξ) takes the positive boundary value of (4.17), and F(ξ) takes the negative boundary value of (4.18).

Next, we come to discuss the solvability conditions for equation (3.1).

(1) If C1(z)C2(z)0 in l2<Imz<l1, we can obtain Φ±(z) and Ψ(z) from (4.15).

(2) When κ<0, X1(z)X2+(z) (that is, X˜(z)) has a singularity at z=z0, then the following conditions are fulfilled:

+il1++il1G1(t)X+(t)(tz0)jdt+il2++il2G2(t)X˜(t)(tz0)jdt=0, 4.20

for any j=1,2,,κ.

(3) If z1,z2,,zν are common zero-points of C1(z) and C2(z) with the orders s1,s2,,sν (sjN), respectively, in l2<Imz<l1, then, in order to guarantee that (3.1) has a solution, we require

Ψ(j)(zt)=0,1tν,1jst.

In this case, we also have the following results:

when κ0, equations (4.21) with the unknown elements c0,c1,,cκ have solutions,

j!2πi[+il2++il2G2(ξ)(ξz0)X˜(ξ)(ξzt)j+1dξ++il1++il1G1(ξ)(ξz0)X+(ξ)(ξzt)j+1dξ]=[Pκ(z)(zz0)κ]z=zt(j),j=0,1,2,,st;t=1,2,,μ, 4.21

where c0,c1,,cκ are the coefficients of Pκ(z), and (4.21) contain s+μ equations with κ+1 unknown elements.

When κ<0, the following equalities are fulfilled:

+il2++il2G2(ξ)(ξz0)X˜(ξ)(ξzk)j+1dξ++il1++il1G1(ξ)(ξz0)X+(ξ)(ξzk)j+1dξ=0 4.22

for any j=0,1,2,,st; t=1,2,,μ.

Thus, we have the following conclusion as regards the solution of equation (3.1).

Theorem 4.2

Under condition (b), in the case of normal type, if C1(z)C2(z)0 in l2<Imz<l1, then the solvable condition of (3.1) is (4.20). If C1(z), C2(z) have some common zero-points z1,z2,,zν in l2<Imz<l1, then (4.21) and (4.22) must be augmented. Thus, a solution f(t) of (3.1) is given by (4.19), in which F+(ξ), F(ξ) are obtained by (4.17) and (4.18), respectively. It is easy to verify that f(t){p,q}.

Finally, we remark that the method of this paper may be applied to solving the equations mentioned above in the non-normal cases (or, the exceptional cases), that is,

Hj(ξ)={(ajbj),Reξ>0;(aj+bj),Reξ<0,j=1,2;ξL1,L2.

As for the method of solution for this case, there is no essential difference for the solving method with the normal case. We will not elaborate on that here.

Results and discussion

In this article, some classes of SIEs of convolution type with Cauchy kernels are solved in the class of exponentially increasing functions. By Fourier transform, such equations are transformed into RBVPs on either a straight line or two parallel straight lines. The exact solutions of equation (3.1), denoted by integrals and the conditions of solvability are obtained. Here, our method is different from the ones for the classical boundary value problem, and it is novel and effective. Thus, the result in this paper generalizes the theory of classical boundary value problems and singular integral equations. Similarly, the above equations can also be solved in Clifford analysis (see [1417]). Further discussion is omitted here.

Conclusions

In this paper, we mainly study the singular integral equations of dual type in the class of exponentially increasing functions. This class of equations (that is, equation (3.1)) have important applications in practical problems, such as elastic mechanics, heat conduction, and electrostatics. Hence, the study of equation (3.1) is of significance not only in applications but also in the theory of resolving the equation itself. To many problems, such as piezoelectric material, voltage magnetic materials and functional gradient materials, one can often attribute the problem to finding solutions for this classes of equations. Hence, the result in this paper improves some results in Refs. [2, 4, 911, 18, 19], and it supplies a theoretical basis for solving the physics problems involved.

Acknowledgements

The author would like to express his gratitude to the anonymous referees for their invaluable comments and suggestions, which helped to improve the quality of the paper. This work is supported financially by the National Natural Science Foundation of China (11501318) and the Natural Science Foundation of Shandong Province of China (ZR2017MA045).

Authors’ contributions

All authors read and approved the final manuscript.

Competing interests

The author declares there to be no conflicts of interest.

Footnotes

Publisher’s Note

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