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. 2018 Mar 14;2018(1):58. doi: 10.1186/s13660-018-1654-6

Positive periodic solution for p-Laplacian neutral Rayleigh equation with singularity of attractive type

Yun Xin 1, Hongmin Liu 1,, Zhibo Cheng 2,3
PMCID: PMC5852206  PMID: 29576715

Abstract

In this paper, we consider a kind of p-Laplacian neutral Rayleigh equation with singularity of attractive type,

(ϕp(u(t)cu(tδ)))+f(t,u(t))+g(t,u(t))=e(t).

By applications of an extension of Mawhin’s continuation theorem, sufficient conditions for the existence of periodic solution are established.

Keywords: Neutral operator, p-Laplacian, Periodic solution, Rayleigh equation, Singularity of attractive type

Introduction

As is well known, the Rayleigh equation can be derived from many fields, such as physics, mechanics and engineering technique fields, and an important question is whether this equation can support periodic solutions. In 1977, Gaines and Mawhin [1] introduced some continuation theorems and applied this theorem to discussing the existence of solutions for the Rayleigh equation [1, p. 99]

u+f(u)+g(t,u)=0.

Gaines and Mawhin’s work has attracted the attention of many scholars in the field of the Rayleigh equations. More recently, the existence of periodic solutions for Rayleigh equation was extensively studied (see [211] and the references therein). Some classical tools have been used to study Rayleigh equation in the literature, including the method of upper and lower solutions [6], the time map continuation theorem [7, 9], fixed point theory [4], the Manásevich–Mawhin continuation theorem [10, 11], and coincidence degree theory [2, 3, 5, 8].

Recently there have been published some results on singular Rayleigh equations [1216]. In 2015, Wang and Ma [15] investigated the following singular Rayleigh equation:

u+f(t,u)+g(u)=p(t),

where g had a repulsive singularity at the origin, i.e.,

limu0+g(u)=. 1.1

By applications of the limit properties of the time map, the authors obtained the result of the existence of periodic solution for this equation. Afterwards, by using topological degree theory, Chen and Lu [12] discussed that the existence of periodic solution for the following singular Rayleigh equations:

u+f(t,u)+φ(t)u(t)1ur(t)=h(t). 1.2

The authors found new methods for estimating a lower priori bounds of periodic solutions to equation (1.2). Recently, Xin and Cheng [16] investigated a kind of neutral Rayleigh equation with singularity of repulsive type,

(u(t)cu(tδ))+f(t,u(t))+g(t,u(t))=e(t), 1.3

where g(t,u)=g1(t,u)+g0(u) and g0 had a strong singularity at u=0, i.e.,

limu0+1ug0(s)ds=+. 1.4

By applications of coincidence degree theory, the authors found the existence of positive periodic solution for equation (1.3).

All the aforementioned results are related to Rayleigh equation or neutral Rayleigh equation with singularity of repulsive type. Naturally, a new question arises: how p-Laplacian neutral Rayleigh equation works on singularity of attractive type? Besides practical interests, the topic has obvious intrinsic theoretical significance. To answer this question, in this paper, we consider a kind of p-Laplacian neutral Rayleigh equation with singularity of attractive type,

(ϕp(u(t)cu(tδ)))+f(t,u(t))+g(t,u(t))=e(t), 1.5

where p>1, φp(u)=|u|p2u for u0 and φp(0)=0; |c|1 and δ is a constant with 0δ<ω; e:RR is continuous periodic functions with e(t+ω)e(t)0 and 0Te(t)dt=0; f is for continuous functions defined on R2 and periodic in t with f(t,)=f(t+ω,) and f(t,0)=0, g(t,u)=g0(u)+g1(t,u), here g1:R×(0,+)R is an L2-Carathéodory function, g1(t,)=g1(t+ω,); g0C((0,);R) has an attractive singularity at the origin, i.e.,

limu0+1ug0(s)ds=. 1.6

Obviously, the attractive condition (1.6) is in contradiction with the repulsive singularity of (1.1) and (1.4). Therefore, the above methods of [12, 15, 16] are no long applicable to the proof of existence of a periodic solution for (1.5) with singularity of attractive type. So we need to find a new method to get over it.

In this paper, by applications of an extension of Mawhin’s continuation theorem in [17] and some analysis techniques, we see the existence of a positive periodic solution for (1.5). Our results improve and extend the results in [12, 15, 16].

Preliminary lemmas

For convenience, define

Cω1={uC1(R,R):u(t+ω)=u(t)},

which is a Banach space endowed with the norm define by u=max{u,u}, for all x, and

u=maxt[0,ω]|u(t)|,u=maxt[0,ω]|u(t)|.

Lemma 2.1

(see [18])

If |c|1, then the operator (Au)(t):=u(t)cu(tδ) has a continuous inverse A1 on the space Cω, and satisfying

(A1f)(t)={f(t)+j=1cjf(tjδ),for |c|<1,fCω,f(t+δ)cj=11cj+1f(t+(j+1)δ),for |c|>1,fCω.

Lemma 2.2

If |c|1, then operator A1 satisfying

0ω|(A1f)(t)|pdt1|1|c||p0ω|f(t)|pdt,fCω,here 1p<.

Proof

We first consider |c|<1. From Lemma 2.1, we have

0ω|(A1f)(t)|pdt=0ω|j=0cjf(tjδ)|pdt0ω(j=0|cjf(tjδ)|)pdt1(1|c|)p0ω|f(t)|pdt.

Similarly, for |c|>1, we can get

0ω|(A1f)(t)|pdt1(|c|1)p0ω|f(t)|pdt.

Therefore, we have

0T|(A1f)(t)|pdt1|1|c||p0T|f(t)|pdt.

 □

Lemma 2.3

(see [19])

If uCω1(R,R), and there exists a point t[0,ω] such that |u(t)|<d, then

ud+120ω|u(t)|dt

and

(0ω|u(t)|pdt)1p(ωπp)(0ω|u(t)|2dt)1p+dω1p,

where 1p<, πp=20(p1)/pds(1spp1)1/p=2π(p1)1/ppsin(π/p).

The following lemma involves the consequences of Theorem 3.1 of [17].

Lemma 2.4

Assume that condition |c|1, Ω is an open bounded set in Cω1. If:

  • (i)
    for each λ(0,1) the equation
    (ϕp(Au)(t))+λf(t,u(t))+λg(t,u(t))=λe(t) 2.1
    has no solution on Ω;
  • (ii)
    the equation
    F(a):=1ω0ωg(t,a)dt=0
    has no solution on ΩR;
  • (iii)
    the Brouwer degree
    deg{F,ΩR,0}0,
    then Eq. (2.1) has at least one periodic solution on Ω̄.

Main results: positive periodic solution for (1.5)

In this section, we will consider the existence of a positive periodic solution for (1.5) with singularity.

Theorem 3.1

Assume that the following conditions hold:

(H1)

there exists a positive constant K such that |f(t,v)|K, for (t,v)R×R;

(H2)

there exist positive constants D1 and D2 with D1>D2>0 such that g(t,u)<K for (t,u)R×(D1,+) and g(t,u)>K for (t,u)R×(0,D2);

(H3)
there exist positive constants a, b such that
g(t,u)aup1+b,for all u>0.

Then (1.5) has at least one positive solution with period ω if ω(1+|c|)1pa1p|1|c||<2p1p.

Proof

Firstly, we will claim that the set of all possible ω-periodic solutions of (2.1) is bounded. Let u(t)Cω1 be an arbitrary solution of (2.1) with period ω.

We claim that there exists a point t0[0,ω] such that

0<u(t0)D1. 3.1

Integrating both sides of (2.1) over [0,ω], we have

0ω[f(t,u(t))+g(t,u(t))]dt=0. 3.2

Therefore, from (H1), we have

Kω0ωg(t,u(t))dtKω.

From (H2), we know that there exist two points t0, τ(0,T), such that

u(t0)D1,andu(τ)>D2. 3.3

Since u(t)>0, t[0,ω], we get 0<u(t0)D1. Equation (3.1) is proved.

Then, from Lemma 2.3, we have

uD1+120ω|u(s)|ds. 3.4

Multiplying both sides of (2.1) by (Au)(t) and integrating over [0,ω], we get

0ω(ϕp(Au)(t))(Au)(t)dt+λ0ωf(t,u(t))(Au)(t)dt+λ0ωg(t,u(t))(Au)(t)dt=λ0ωe(t)(Au)(t)dt,

i.e.

0ω|(Au)(t)|pdt=λ0ωf(t,u(t))(Au)(t)dt+λ0ωg(t,u(t))(Au)(t)dtλ0ωe(t)(Au)(t)dt. 3.5

From (H1), we have

0ω|(Au)(t)|pdt(1+|c|)0ω|f(t,u(t))||u(t)|dt+0ω|g(t,u(t))||u(t)|dt+0ω|e(t)||u(t)|dt(1+|c|)u(0ω|f(t,u(t))|dt+0ω|g(t,u(t))|dt+0ω|e(t)|dt)(1+|c|)u(Kω+eω+0ω|g(t,u(t))|dt). 3.6

We get from (H1), (H3) and (3.2)

0ω|g(t,u(t))|dt=g(t,u(t))0g+(t,u(t))dtg(t,u(t))0g(t,u(t))dt=2g(t,u(t))0g(t,u(t))dt+0ωf(t,u(t))dt2a0ω|u(t)|p1dt+2bω+Kω2aωup1+2bω+Kω, 3.7

where g:=min{g(t,u),0}. Substituting (3.4) and (3.7) into (3.6), we have

0ω|(Au)(t)|pdt(1+|c|)u(2aωup1+2bω+2Kω+eω)=2(1+|c|)aωup+(1+|c|)N1u2(1+|c|)aω(D1+120ω|u(t)|dt)p+(1+|c|)N1(D1+120ω|u(t)|dt)=(1+|c|)aω2p1(1+2D10ω|u(t)|dt)p(0ω|u(t)|dt)p+12(1+|c|)N10ω|u(t)|dt+(1+|c|)N1D1,

where N1:=2bω+2Kω+eω. For a given constant ζ>0, which is only dependent on k>0, we have

(1+u)k1+(1+k)u,for u[0,ζ].

Therefore, we have

0ω|(Au)(t)|pdt(1+|c|)aω2p1(1+2D1p0ω|u(t)|dt)(0ω|u(t)|dt)p+12(1+|c|)N10ω|u(t)|dt+(1+|c|)N1D1=(1+|c|)aω2p1(0ω|u(t)|dt)p+(1+|c|)aωD1p2p2(0ω|u(t)|dt)p1+12(1+|c|)N10ω|u(t)|dt+(1+|c|)N1D1. 3.8

By application of Lemma 2.1, we have

0ω|u(t)|dt=0ω|(A1Au)(t)|dt0ω|(Au)(t)|dt|1|c||ω1q(0ω|(Au)(t)|pdt)1p|1|c||, 3.9

since (Au)(t)=(Au)(t) and 1p+1q=1. Apply the inequality

(a+b)kak+bk,for a,b>0,0<k<1.

Substituting (3.8) into (3.9), we have

0ω|u(t)|dtω1q((1+|c|)aω2p1)1p0ω|u(t)|dt+ω1q((1+|c|)aωD1p2p2)1p(0ω|u(t)|dt)p1p|1|c||+ω1q(12(1+|c|)N10ω|u(t)|dt)1p+ω1q((1+|c|)N1D1)1p|1|c||.

Since ω(1+|c|)1pa1p|1|c||<2p1p, it is easy to see that there exists a positive constant M1 such that

0ω|u(t)|dtM1. 3.10

From (3.4) and (3.10), we have

uD1+120ω|u(t)|dtD1+12M1:=M1. 3.11

As (Au)(0)=(Au)(ω), there exists t1[0,ω] such that (Au)(t1)=0, while ϕp(0)=0, we have

|ϕp((Au)(t))|=|t1t(ϕp((Au)(s)))ds|λ0ω|f(t,u(t))|dt+λ0ω|g(t,u(t))|dt+λ0ω|e(t)|dt, 3.12

where t[t1,t1+ω]. In view of (H1), (3.7) and (3.12), we have

ϕp(Au)=maxt[0,ω]{|ϕp((Au)(t))|}=maxt[t1,t1+ω]{|t1t(ϕp((Au)(s)))ds|}λ(0ω|f(t,u(t)|dt+0ω|g(t,u(t))|dt+0ω|e(t)|dt)λ(Kω+2aωup1+2bω+Kω+eω)λ(2aωM1p1+2Kω+2bω+eω):=λM2. 3.13

We claim that there exists a positive constant M2>M2+1 such that, for all tR,

uM2. 3.14

In fact, if u is not bounded, there exists a positive constant M2 such that u>M2 for some uR. Therefore, we have

ϕp(Au)=ϕp(Au)=Aup1=(1+|c|)p1up1(1+|c|)p1M2p1:=M2.

Then it is a contradiction. So (3.14) holds.

On the other hand, it follows by (2.1) that

(ϕp(Au)(t))+λf(t,u(t))+λ(g0(u(t))+g1(t,u(t)))=λe(t). 3.15

Multiplying both sides of (3.15) by u(t) we get

(ϕp(Au)(t))u(t)+λf(t,u(t))u(t)+λ(g0(u(t))+g1(t,u(t)))u(t)=λe(t)u(t). 3.16

Let τ[0,ω] be as in (3.3), for any τtω, we integrate (3.16) on [τ,t] and get

λu(τ)u(t)g0(v)dv=λτtg0(u(s))u(s)ds=τt(ϕp(Au)(s))u(s)dsλτtf(s,u(s))u(s)dsλτtg1(s,u(s))u(s)ds+λτte(s)u(s)ds. 3.17

By (3.7), (3.11) and (3.14), we have

|τt(ϕp(Au)(s))u(s)ds|0T|(ϕp(Au)(s))||u(s)|dsλu(0ω|f(t,u(t))dt+0ω|g(t,u(t))|dt+0ω|e(t)|dt)λM2(Kω+2aω|up1+2bω+Kω+eω)λM2(2Kω+2aωM1p1+2bω+eω).

Moreover, from (H1) and (3.14)

|τtf(s,u(s))u(s)ds|0T|f(s,u(s))||u(s)|dsKM2ω,|τtg1(s,u(s))u(s)ds|0T|g1(s,u(s))||u(s)|dsM2|gM1|ω,

where gM1=max0uM1|g1(t,u)|L2(0,ω).

|τte(s)u(s)ds|0ω|e(s)||u(s)|dseωM2.

With these inequalities we can derive from (3.17) that

|u(τ)u(t)g0(v)dv|M2(3Kω+2aωM1p1+2bω+2eω+|gM1|ω).

In view of (1.6), we know there exists M3>0 such that

u(t)M3,t[τ,ω]. 3.18

The case t[0,τ] can be treated similarly.

Having in mind (3.11), (3.14) and (3.18), we define

Ω={uX:E1<u(t)<E2 and |u(t)|<E3tR},

where 0<E1<min{D2,M3}, E2>max{M1,D1} and E3>M2. We know that (2.1) has no solution on Ω as λ(0,1) and when u(t)ΩR, u(t)=E2 or u(t)=E1, from (3.4), we know that E2+1>D1; therefore, from (H2) we see that

1ω0ωg(t,E2)dt<0

and

1ω0ωg(t,E1)dt>0.

So condition (ii) is also satisfied. Set

H(u,μ)=μu+(1μ)1ω0ωg(t,u)dt,

where xΩR, μ[0,1], we have

uH(u,μ)=μu2+(1μ)uω0ωg(t,u)dt0,

and thus H(u,μ) is a homotopic transformation and

deg{F,ΩR,0}=deg{1ω0ωg(t,u)dt,ΩR,0}=deg{u,ΩR,0}0.

So condition (iii) is satisfied. In view of Lemma 2.1, there exists a solution with period ω. □

Example

Example 4.1

Consider the following p-Laplacian neutral Rayleigh equation with singularity:

(ϕp(u(t)14u(tδ)))cos2(2t)sinu(t)13π4(sin4t+2)u3(t)+1uμ=sin2(2t), 4.1

where μ1 and p=4, δ is a constant and 0δ<ω.

It is clear that ω=π2, c=14, e(t)=sin2(2t), f(t,v)=cos2(2t)sinv, g(t,u)=13π3(sin4t+2)u4(t)+1uμ(t). Choose K=1, D1=2, D2=1, a=1π4, it is obvious that (H1), (H2) and (H3) hold. Next, we consider

ω(1+|c|)1pa1p2p1p|1|c||=π2(1+14)14(1π4)14234(114)1.0571.783<1.

Therefore, by Theorem 3.1, (4.1) has at least one nonconstant π2-periodic solution.

Conclusions

In this article we introduce the existence of a periodic solution for a p-Laplacian neutral Rayleigh equation with singularity of attractive type. Due to the attractive condition being in contradiction with the repulsive condition, the methods of [12, 15, 16] are no long applicable to the proof of a periodic solution for equation (1.5) with singularity of attractive singularity. In this paper, we give attractive conditions (1.6) and (H3), and we see the existence of a periodic solution for (1.5) by applications of the extension of Mawhin’s continuation theorem [17]. Moreover, in view of the mathematical points, the results satisfying the conditions of an attractive singularity are valuable to understand the periodic solution for Rayleigh equations.

Acknowledgements

YX, HML and ZBC would like to thank the referee for invaluable comments and insightful suggestions. This work was supported by National Natural Science Foundation of China (No. 11501170), Education Department of Henan Province project (No. 16B110006) and Henan Polytechnic University Outstanding Youth Fund (J2016-03).

Authors’ contributions

YX, HML and ZBC worked together on the derivation of the mathematical results. All authors read and approved the final manuscript.

Competing interests

The authors declare that they have no competing interests.

Footnotes

Publisher’s Note

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Contributor Information

Yun Xin, Email: xy_1982@126.com.

Hongmin Liu, Email: hongminliu_1982@126.com.

Zhibo Cheng, Email: czbo@hpu.edu.cn.

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