Abstract
We have examined the causes of the asymmetry of the current-voltage curve induced by addition of alamethicin to one side of a black lipid membrane. We find that the alamethicin-induced current-voltage (I-V) curve has an inherent asymmetry. If it were possible to confine all alamethicin molecules to one side of the membrane, the I-V curve would exhibit a positive branch (voltage being measured with respect to the side of the membrane trans to the alamethicin addition) of steeper logarithmic slope than the negative branch and at a lower absolute value of potential. This condition is not usually realized, however, because alamethicin can leak through the membrane, so that, except at very high alamethicin concentrations and in certain kinds of membranes, the positive branch of the current-voltage curve has the same logarithmic slope as the negative branch and appears to arise from alamethicin which diffuses from the cis to the trans side of the membrane. We develop simple quantitative models for these two cases.
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